Why does shooting a handgun produce a bullet of deadly speed without injury of the gun user's hand?












4














Momentum is defined by the product of mass and velocity. Now a projectile out of a gun has to have high velocity to penetrate a human body, as its mass isn't significant. But to reach this velocity, due to inertia/the law of energy conservation, momentum on both sides is to be equal. As there is strong negative acceleration in the opposite direction of the bullet, it should result in a strong force in the opposite direction of the bullet ($F = m*a $).



Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart.










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  • 1




    bullets are very small (and handgun bullets aren't that fast) compared to the mass of the shooter
    – Martin Beckett
    6 hours ago






  • 5




    If you ever shoot a .454 Casull, you'll find that there definitely IS a possibility of wrist injury due to the enormous recoil. Such a revolves is NOT fun to shoot.
    – David White
    5 hours ago










  • Short but true story. Years ago, I was the gun loader on an artillery piece. I learnt to respect recoil, especially from firing heavy shells. We tried to tell a newly commissioned officer, about the dangers, but he was a captain and didn't listen to lower ranks. He keep his head on the eyepiece upon firing, and ended up with a smashed eyesocket. Point being, recoil is to be respected.
    – StudyStudy
    1 hour ago










  • @DavidWhite Why would you choose such a firearm cartridge?
    – Zurechtweiser
    1 hour ago








  • 3




    This is a strange question; one could easily build a gun whose recoil badly injured the shooter. We do not build such guns because there is no market for guns that consistently injure the shooter. You ask why a product that has no market does not exist; because no one would build it!
    – Eric Lippert
    44 mins ago
















4














Momentum is defined by the product of mass and velocity. Now a projectile out of a gun has to have high velocity to penetrate a human body, as its mass isn't significant. But to reach this velocity, due to inertia/the law of energy conservation, momentum on both sides is to be equal. As there is strong negative acceleration in the opposite direction of the bullet, it should result in a strong force in the opposite direction of the bullet ($F = m*a $).



Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart.










share|cite|improve this question




















  • 1




    bullets are very small (and handgun bullets aren't that fast) compared to the mass of the shooter
    – Martin Beckett
    6 hours ago






  • 5




    If you ever shoot a .454 Casull, you'll find that there definitely IS a possibility of wrist injury due to the enormous recoil. Such a revolves is NOT fun to shoot.
    – David White
    5 hours ago










  • Short but true story. Years ago, I was the gun loader on an artillery piece. I learnt to respect recoil, especially from firing heavy shells. We tried to tell a newly commissioned officer, about the dangers, but he was a captain and didn't listen to lower ranks. He keep his head on the eyepiece upon firing, and ended up with a smashed eyesocket. Point being, recoil is to be respected.
    – StudyStudy
    1 hour ago










  • @DavidWhite Why would you choose such a firearm cartridge?
    – Zurechtweiser
    1 hour ago








  • 3




    This is a strange question; one could easily build a gun whose recoil badly injured the shooter. We do not build such guns because there is no market for guns that consistently injure the shooter. You ask why a product that has no market does not exist; because no one would build it!
    – Eric Lippert
    44 mins ago














4












4








4







Momentum is defined by the product of mass and velocity. Now a projectile out of a gun has to have high velocity to penetrate a human body, as its mass isn't significant. But to reach this velocity, due to inertia/the law of energy conservation, momentum on both sides is to be equal. As there is strong negative acceleration in the opposite direction of the bullet, it should result in a strong force in the opposite direction of the bullet ($F = m*a $).



Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart.










share|cite|improve this question















Momentum is defined by the product of mass and velocity. Now a projectile out of a gun has to have high velocity to penetrate a human body, as its mass isn't significant. But to reach this velocity, due to inertia/the law of energy conservation, momentum on both sides is to be equal. As there is strong negative acceleration in the opposite direction of the bullet, it should result in a strong force in the opposite direction of the bullet ($F = m*a $).



Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart.







newtonian-mechanics momentum conservation-laws collision estimation






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 1 hour ago

























asked 6 hours ago









Zurechtweiser

1323




1323








  • 1




    bullets are very small (and handgun bullets aren't that fast) compared to the mass of the shooter
    – Martin Beckett
    6 hours ago






  • 5




    If you ever shoot a .454 Casull, you'll find that there definitely IS a possibility of wrist injury due to the enormous recoil. Such a revolves is NOT fun to shoot.
    – David White
    5 hours ago










  • Short but true story. Years ago, I was the gun loader on an artillery piece. I learnt to respect recoil, especially from firing heavy shells. We tried to tell a newly commissioned officer, about the dangers, but he was a captain and didn't listen to lower ranks. He keep his head on the eyepiece upon firing, and ended up with a smashed eyesocket. Point being, recoil is to be respected.
    – StudyStudy
    1 hour ago










  • @DavidWhite Why would you choose such a firearm cartridge?
    – Zurechtweiser
    1 hour ago








  • 3




    This is a strange question; one could easily build a gun whose recoil badly injured the shooter. We do not build such guns because there is no market for guns that consistently injure the shooter. You ask why a product that has no market does not exist; because no one would build it!
    – Eric Lippert
    44 mins ago














  • 1




    bullets are very small (and handgun bullets aren't that fast) compared to the mass of the shooter
    – Martin Beckett
    6 hours ago






  • 5




    If you ever shoot a .454 Casull, you'll find that there definitely IS a possibility of wrist injury due to the enormous recoil. Such a revolves is NOT fun to shoot.
    – David White
    5 hours ago










  • Short but true story. Years ago, I was the gun loader on an artillery piece. I learnt to respect recoil, especially from firing heavy shells. We tried to tell a newly commissioned officer, about the dangers, but he was a captain and didn't listen to lower ranks. He keep his head on the eyepiece upon firing, and ended up with a smashed eyesocket. Point being, recoil is to be respected.
    – StudyStudy
    1 hour ago










  • @DavidWhite Why would you choose such a firearm cartridge?
    – Zurechtweiser
    1 hour ago








  • 3




    This is a strange question; one could easily build a gun whose recoil badly injured the shooter. We do not build such guns because there is no market for guns that consistently injure the shooter. You ask why a product that has no market does not exist; because no one would build it!
    – Eric Lippert
    44 mins ago








1




1




bullets are very small (and handgun bullets aren't that fast) compared to the mass of the shooter
– Martin Beckett
6 hours ago




bullets are very small (and handgun bullets aren't that fast) compared to the mass of the shooter
– Martin Beckett
6 hours ago




5




5




If you ever shoot a .454 Casull, you'll find that there definitely IS a possibility of wrist injury due to the enormous recoil. Such a revolves is NOT fun to shoot.
– David White
5 hours ago




If you ever shoot a .454 Casull, you'll find that there definitely IS a possibility of wrist injury due to the enormous recoil. Such a revolves is NOT fun to shoot.
– David White
5 hours ago












Short but true story. Years ago, I was the gun loader on an artillery piece. I learnt to respect recoil, especially from firing heavy shells. We tried to tell a newly commissioned officer, about the dangers, but he was a captain and didn't listen to lower ranks. He keep his head on the eyepiece upon firing, and ended up with a smashed eyesocket. Point being, recoil is to be respected.
– StudyStudy
1 hour ago




Short but true story. Years ago, I was the gun loader on an artillery piece. I learnt to respect recoil, especially from firing heavy shells. We tried to tell a newly commissioned officer, about the dangers, but he was a captain and didn't listen to lower ranks. He keep his head on the eyepiece upon firing, and ended up with a smashed eyesocket. Point being, recoil is to be respected.
– StudyStudy
1 hour ago












@DavidWhite Why would you choose such a firearm cartridge?
– Zurechtweiser
1 hour ago






@DavidWhite Why would you choose such a firearm cartridge?
– Zurechtweiser
1 hour ago






3




3




This is a strange question; one could easily build a gun whose recoil badly injured the shooter. We do not build such guns because there is no market for guns that consistently injure the shooter. You ask why a product that has no market does not exist; because no one would build it!
– Eric Lippert
44 mins ago




This is a strange question; one could easily build a gun whose recoil badly injured the shooter. We do not build such guns because there is no market for guns that consistently injure the shooter. You ask why a product that has no market does not exist; because no one would build it!
– Eric Lippert
44 mins ago










3 Answers
3






active

oldest

votes


















7














Firstly, some guns do give quite a kick! So the effect you are thinking of is real.



However, conservation of momentum means that Mass_bullet * velocity_bullet = Mass_gun * velocity_gun. So the bullet's velocity is greater than that of the gun by a ratio of Mass_gun / Mass_bullet. Then energy is distributed in the same ratio because while energy scales as velocity squared, it also scales with the mass. So, it is useful for the gun to be heavy and/or for it to have a spring-loaded mechanism to slowly distribute the kick to your hand and body.






share|cite|improve this answer








New contributor




Paul Young is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


























    7














    The handgun is braced with a large surface area of the hand, and the palm and entire hand are robust; the result is that the hand, or hand and arm, or hand and upper body are sharply displaced as a whole before the motion is damped by the rest of the body.



    Some details of recoil are discussed here. The recoil of rifles, which are generally more powerful, braced near the shoulder, and operated near the face, can easily cause a broken collarbone, torn rotator cuff, black eye, and/or detached retina.



    Thus, whether injury occurs depends on the stress induced in vivo from the acceleration of the brace position vs. the relative strength of the nearby organs.






    share|cite|improve this answer





















    • The hand (and wrist, forearm, &c) also has many flexible muscles and joints, which act as shock absorbers. Not just when firing a pistol: think of hitting something with your fist.
      – jamesqf
      4 hours ago






    • 2




      If the gun weighed as much (very important) as the projectile, and was as small (also important), it would. We have an ancient Styre rifle that was shortened at some point, vastly reducing it's weight. Its recoil went from being described as 'unpleasant' to 'grim'.
      – Mazura
      2 hours ago



















    0















    Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart.




    Because the mass of the handgun is greater than the mass of the bullet, and because the energy transferred from the gun to your hand is distributed across the surface of the pistol grip.



    One of the more interesting things I heard on a trip to Williamsburg Virginia (which is period of ~1776; American Revolution) was the question of how much the muskets weighed. The historical figure answered (I don't recall the weight) and the questioner said in a surprised voice, "That's basically the same that guns weigh today!"



    "Yes," replied this historical figure, "because the physics hasn't changed. They could make rifles lighter today, but they don't because the recoil would be worse."



    There are other things put in modern pistols to reduce recoil like springs and discharge, but since you tagged it "Newtonian physics" I expect your are less interested in those things.






    share|cite|improve this answer








    New contributor




    J. Chris Compton is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      7














      Firstly, some guns do give quite a kick! So the effect you are thinking of is real.



      However, conservation of momentum means that Mass_bullet * velocity_bullet = Mass_gun * velocity_gun. So the bullet's velocity is greater than that of the gun by a ratio of Mass_gun / Mass_bullet. Then energy is distributed in the same ratio because while energy scales as velocity squared, it also scales with the mass. So, it is useful for the gun to be heavy and/or for it to have a spring-loaded mechanism to slowly distribute the kick to your hand and body.






      share|cite|improve this answer








      New contributor




      Paul Young is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.























        7














        Firstly, some guns do give quite a kick! So the effect you are thinking of is real.



        However, conservation of momentum means that Mass_bullet * velocity_bullet = Mass_gun * velocity_gun. So the bullet's velocity is greater than that of the gun by a ratio of Mass_gun / Mass_bullet. Then energy is distributed in the same ratio because while energy scales as velocity squared, it also scales with the mass. So, it is useful for the gun to be heavy and/or for it to have a spring-loaded mechanism to slowly distribute the kick to your hand and body.






        share|cite|improve this answer








        New contributor




        Paul Young is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





















          7












          7








          7






          Firstly, some guns do give quite a kick! So the effect you are thinking of is real.



          However, conservation of momentum means that Mass_bullet * velocity_bullet = Mass_gun * velocity_gun. So the bullet's velocity is greater than that of the gun by a ratio of Mass_gun / Mass_bullet. Then energy is distributed in the same ratio because while energy scales as velocity squared, it also scales with the mass. So, it is useful for the gun to be heavy and/or for it to have a spring-loaded mechanism to slowly distribute the kick to your hand and body.






          share|cite|improve this answer








          New contributor




          Paul Young is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          Firstly, some guns do give quite a kick! So the effect you are thinking of is real.



          However, conservation of momentum means that Mass_bullet * velocity_bullet = Mass_gun * velocity_gun. So the bullet's velocity is greater than that of the gun by a ratio of Mass_gun / Mass_bullet. Then energy is distributed in the same ratio because while energy scales as velocity squared, it also scales with the mass. So, it is useful for the gun to be heavy and/or for it to have a spring-loaded mechanism to slowly distribute the kick to your hand and body.







          share|cite|improve this answer








          New contributor




          Paul Young is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          share|cite|improve this answer



          share|cite|improve this answer






          New contributor




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          answered 6 hours ago









          Paul Young

          1093




          1093




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          New contributor





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              7














              The handgun is braced with a large surface area of the hand, and the palm and entire hand are robust; the result is that the hand, or hand and arm, or hand and upper body are sharply displaced as a whole before the motion is damped by the rest of the body.



              Some details of recoil are discussed here. The recoil of rifles, which are generally more powerful, braced near the shoulder, and operated near the face, can easily cause a broken collarbone, torn rotator cuff, black eye, and/or detached retina.



              Thus, whether injury occurs depends on the stress induced in vivo from the acceleration of the brace position vs. the relative strength of the nearby organs.






              share|cite|improve this answer





















              • The hand (and wrist, forearm, &c) also has many flexible muscles and joints, which act as shock absorbers. Not just when firing a pistol: think of hitting something with your fist.
                – jamesqf
                4 hours ago






              • 2




                If the gun weighed as much (very important) as the projectile, and was as small (also important), it would. We have an ancient Styre rifle that was shortened at some point, vastly reducing it's weight. Its recoil went from being described as 'unpleasant' to 'grim'.
                – Mazura
                2 hours ago
















              7














              The handgun is braced with a large surface area of the hand, and the palm and entire hand are robust; the result is that the hand, or hand and arm, or hand and upper body are sharply displaced as a whole before the motion is damped by the rest of the body.



              Some details of recoil are discussed here. The recoil of rifles, which are generally more powerful, braced near the shoulder, and operated near the face, can easily cause a broken collarbone, torn rotator cuff, black eye, and/or detached retina.



              Thus, whether injury occurs depends on the stress induced in vivo from the acceleration of the brace position vs. the relative strength of the nearby organs.






              share|cite|improve this answer





















              • The hand (and wrist, forearm, &c) also has many flexible muscles and joints, which act as shock absorbers. Not just when firing a pistol: think of hitting something with your fist.
                – jamesqf
                4 hours ago






              • 2




                If the gun weighed as much (very important) as the projectile, and was as small (also important), it would. We have an ancient Styre rifle that was shortened at some point, vastly reducing it's weight. Its recoil went from being described as 'unpleasant' to 'grim'.
                – Mazura
                2 hours ago














              7












              7








              7






              The handgun is braced with a large surface area of the hand, and the palm and entire hand are robust; the result is that the hand, or hand and arm, or hand and upper body are sharply displaced as a whole before the motion is damped by the rest of the body.



              Some details of recoil are discussed here. The recoil of rifles, which are generally more powerful, braced near the shoulder, and operated near the face, can easily cause a broken collarbone, torn rotator cuff, black eye, and/or detached retina.



              Thus, whether injury occurs depends on the stress induced in vivo from the acceleration of the brace position vs. the relative strength of the nearby organs.






              share|cite|improve this answer












              The handgun is braced with a large surface area of the hand, and the palm and entire hand are robust; the result is that the hand, or hand and arm, or hand and upper body are sharply displaced as a whole before the motion is damped by the rest of the body.



              Some details of recoil are discussed here. The recoil of rifles, which are generally more powerful, braced near the shoulder, and operated near the face, can easily cause a broken collarbone, torn rotator cuff, black eye, and/or detached retina.



              Thus, whether injury occurs depends on the stress induced in vivo from the acceleration of the brace position vs. the relative strength of the nearby organs.







              share|cite|improve this answer












              share|cite|improve this answer



              share|cite|improve this answer










              answered 5 hours ago









              Chemomechanics

              4,3803922




              4,3803922












              • The hand (and wrist, forearm, &c) also has many flexible muscles and joints, which act as shock absorbers. Not just when firing a pistol: think of hitting something with your fist.
                – jamesqf
                4 hours ago






              • 2




                If the gun weighed as much (very important) as the projectile, and was as small (also important), it would. We have an ancient Styre rifle that was shortened at some point, vastly reducing it's weight. Its recoil went from being described as 'unpleasant' to 'grim'.
                – Mazura
                2 hours ago


















              • The hand (and wrist, forearm, &c) also has many flexible muscles and joints, which act as shock absorbers. Not just when firing a pistol: think of hitting something with your fist.
                – jamesqf
                4 hours ago






              • 2




                If the gun weighed as much (very important) as the projectile, and was as small (also important), it would. We have an ancient Styre rifle that was shortened at some point, vastly reducing it's weight. Its recoil went from being described as 'unpleasant' to 'grim'.
                – Mazura
                2 hours ago
















              The hand (and wrist, forearm, &c) also has many flexible muscles and joints, which act as shock absorbers. Not just when firing a pistol: think of hitting something with your fist.
              – jamesqf
              4 hours ago




              The hand (and wrist, forearm, &c) also has many flexible muscles and joints, which act as shock absorbers. Not just when firing a pistol: think of hitting something with your fist.
              – jamesqf
              4 hours ago




              2




              2




              If the gun weighed as much (very important) as the projectile, and was as small (also important), it would. We have an ancient Styre rifle that was shortened at some point, vastly reducing it's weight. Its recoil went from being described as 'unpleasant' to 'grim'.
              – Mazura
              2 hours ago




              If the gun weighed as much (very important) as the projectile, and was as small (also important), it would. We have an ancient Styre rifle that was shortened at some point, vastly reducing it's weight. Its recoil went from being described as 'unpleasant' to 'grim'.
              – Mazura
              2 hours ago











              0















              Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart.




              Because the mass of the handgun is greater than the mass of the bullet, and because the energy transferred from the gun to your hand is distributed across the surface of the pistol grip.



              One of the more interesting things I heard on a trip to Williamsburg Virginia (which is period of ~1776; American Revolution) was the question of how much the muskets weighed. The historical figure answered (I don't recall the weight) and the questioner said in a surprised voice, "That's basically the same that guns weigh today!"



              "Yes," replied this historical figure, "because the physics hasn't changed. They could make rifles lighter today, but they don't because the recoil would be worse."



              There are other things put in modern pistols to reduce recoil like springs and discharge, but since you tagged it "Newtonian physics" I expect your are less interested in those things.






              share|cite|improve this answer








              New contributor




              J. Chris Compton is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.























                0















                Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart.




                Because the mass of the handgun is greater than the mass of the bullet, and because the energy transferred from the gun to your hand is distributed across the surface of the pistol grip.



                One of the more interesting things I heard on a trip to Williamsburg Virginia (which is period of ~1776; American Revolution) was the question of how much the muskets weighed. The historical figure answered (I don't recall the weight) and the questioner said in a surprised voice, "That's basically the same that guns weigh today!"



                "Yes," replied this historical figure, "because the physics hasn't changed. They could make rifles lighter today, but they don't because the recoil would be worse."



                There are other things put in modern pistols to reduce recoil like springs and discharge, but since you tagged it "Newtonian physics" I expect your are less interested in those things.






                share|cite|improve this answer








                New contributor




                J. Chris Compton is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





















                  0












                  0








                  0







                  Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart.




                  Because the mass of the handgun is greater than the mass of the bullet, and because the energy transferred from the gun to your hand is distributed across the surface of the pistol grip.



                  One of the more interesting things I heard on a trip to Williamsburg Virginia (which is period of ~1776; American Revolution) was the question of how much the muskets weighed. The historical figure answered (I don't recall the weight) and the questioner said in a surprised voice, "That's basically the same that guns weigh today!"



                  "Yes," replied this historical figure, "because the physics hasn't changed. They could make rifles lighter today, but they don't because the recoil would be worse."



                  There are other things put in modern pistols to reduce recoil like springs and discharge, but since you tagged it "Newtonian physics" I expect your are less interested in those things.






                  share|cite|improve this answer








                  New contributor




                  J. Chris Compton is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.










                  Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart.




                  Because the mass of the handgun is greater than the mass of the bullet, and because the energy transferred from the gun to your hand is distributed across the surface of the pistol grip.



                  One of the more interesting things I heard on a trip to Williamsburg Virginia (which is period of ~1776; American Revolution) was the question of how much the muskets weighed. The historical figure answered (I don't recall the weight) and the questioner said in a surprised voice, "That's basically the same that guns weigh today!"



                  "Yes," replied this historical figure, "because the physics hasn't changed. They could make rifles lighter today, but they don't because the recoil would be worse."



                  There are other things put in modern pistols to reduce recoil like springs and discharge, but since you tagged it "Newtonian physics" I expect your are less interested in those things.







                  share|cite|improve this answer








                  New contributor




                  J. Chris Compton is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  share|cite|improve this answer



                  share|cite|improve this answer






                  New contributor




                  J. Chris Compton is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  answered 34 mins ago









                  J. Chris Compton

                  1012




                  1012




                  New contributor




                  J. Chris Compton is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.





                  New contributor





                  J. Chris Compton is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  J. Chris Compton is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






























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