Bash string to integer comparison
2
Here I see the [[ allows comparison between string and integer.
[usr1@host dir]$ echo $count1
[1] "0"
[usr1@host dir]$ echo $count2
13188
[usr1@host dir]$ if [[ $count1 -ne $count2 ]]
> then
> echo "NE"
> fi
bash: [[: [1] "0": syntax error: operand expected (error token is "[1] "0"")
#this worked fine at one point
if [[ $count1 -ne $count2 ]] then
echo "NE"
fi
syntax error near unexpected token 'then'
if [[ $count1 -ne $count2 ]]; then
echo "NE"
fi
[[: [1] "0": syntax error: operand expected (error token is "[1] "0"")
I am very confused with the way the syntax works. How do we tackle different scenarios? How to prevent the syntax errors irrespective of the value changes(im guessing thats the reason it gives error now).
bash
edited Dec 19 '18 at 8:34
ilkkachu
55.9k784155
asked Dec 19 '18 at 5:42
sjd
1132
add a comment |
2
Here I see the [[ allows comparison between string and integer.
[usr1@host dir]$ echo $count1
[1] "0"
[usr1@host dir]$ echo $count2
13188
[usr1@host dir]$ if [[ $count1 -ne $count2 ]]
> then
> echo "NE"
> fi
bash: [[: [1] "0": syntax error: operand expected (error token is "[1] "0"")
#this worked fine at one point
if [[ $count1 -ne $count2 ]] then
echo "NE"
fi
syntax error near unexpected token 'then'
if [[ $count1 -ne $count2 ]]; then
echo "NE"
fi
[[: [1] "0": syntax error: operand expected (error token is "[1] "0"")
I am very confused with the way the syntax works. How do we tackle different scenarios? How to prevent the syntax errors irrespective of the value changes(im guessing thats the reason it gives error now).
bash
edited Dec 19 '18 at 8:34
ilkkachu
55.9k784155
asked Dec 19 '18 at 5:42
sjd
1132
(1) Does your$count1value really include brackets and quotes? What sort of result do you expect from input like that? (2) In your first example, the]]and thethenare on different lines. If you put them on the same line, you must put a;between them.
– G-Man
Dec 19 '18 at 5:54
@G-Man Simply comparing the count of records from 2 different sources. Which syntax should i be using?
– sjd
Dec 19 '18 at 6:02
@G-Man Ooh Sorry .. Now only i understood the "[1]" was part of the output ofcount1. Will try again.. Thanks
– sjd
Dec 19 '18 at 6:21
@sjd: If the output ofcount1is really:[1] "0", then!=should be used inifcondition to compare thestringand anumber. Eg:if [[ "$count1" != "$count2" ]] ;then echo "NE"; fi
– User123
Dec 19 '18 at 6:42
add a comment |
2
2
2
Here I see the [[ allows comparison between string and integer.
[usr1@host dir]$ echo $count1
[1] "0"
[usr1@host dir]$ echo $count2
13188
[usr1@host dir]$ if [[ $count1 -ne $count2 ]]
> then
> echo "NE"
> fi
bash: [[: [1] "0": syntax error: operand expected (error token is "[1] "0"")
#this worked fine at one point
if [[ $count1 -ne $count2 ]] then
echo "NE"
fi
syntax error near unexpected token 'then'
if [[ $count1 -ne $count2 ]]; then
echo "NE"
fi
[[: [1] "0": syntax error: operand expected (error token is "[1] "0"")
I am very confused with the way the syntax works. How do we tackle different scenarios? How to prevent the syntax errors irrespective of the value changes(im guessing thats the reason it gives error now).
bash
edited Dec 19 '18 at 8:34
ilkkachu
55.9k784155
asked Dec 19 '18 at 5:42
sjd
1132
Here I see the [[ allows comparison between string and integer.
[usr1@host dir]$ echo $count1
[1] "0"
[usr1@host dir]$ echo $count2
13188
[usr1@host dir]$ if [[ $count1 -ne $count2 ]]
> then
> echo "NE"
> fi
bash: [[: [1] "0": syntax error: operand expected (error token is "[1] "0"")
#this worked fine at one point
if [[ $count1 -ne $count2 ]] then
echo "NE"
fi
syntax error near unexpected token 'then'
if [[ $count1 -ne $count2 ]]; then
echo "NE"
fi
[[: [1] "0": syntax error: operand expected (error token is "[1] "0"")
I am very confused with the way the syntax works. How do we tackle different scenarios? How to prevent the syntax errors irrespective of the value changes(im guessing thats the reason it gives error now).
bash
bash
edited Dec 19 '18 at 8:34
ilkkachu
55.9k784155
asked Dec 19 '18 at 5:42
sjd
1132
edited Dec 19 '18 at 8:34
ilkkachu
55.9k784155
asked Dec 19 '18 at 5:42
sjd
1132
edited Dec 19 '18 at 8:34
ilkkachu
55.9k784155
edited Dec 19 '18 at 8:34
ilkkachu
55.9k784155
edited Dec 19 '18 at 8:34
ilkkachu
55.9k784155
55.9k784155
asked Dec 19 '18 at 5:42
sjd
1132
asked Dec 19 '18 at 5:42
sjd
1132
asked Dec 19 '18 at 5:42
sjd
1132
1132
(1) Does your$count1value really include brackets and quotes? What sort of result do you expect from input like that? (2) In your first example, the]]and thethenare on different lines. If you put them on the same line, you must put a;between them.
– G-Man
Dec 19 '18 at 5:54
@G-Man Simply comparing the count of records from 2 different sources. Which syntax should i be using?
– sjd
Dec 19 '18 at 6:02
@G-Man Ooh Sorry .. Now only i understood the "[1]" was part of the output ofcount1. Will try again.. Thanks
– sjd
Dec 19 '18 at 6:21
@sjd: If the output ofcount1is really:[1] "0", then!=should be used inifcondition to compare thestringand anumber. Eg:if [[ "$count1" != "$count2" ]] ;then echo "NE"; fi
– User123
Dec 19 '18 at 6:42
add a comment |
(1) Does your$count1value really include brackets and quotes? What sort of result do you expect from input like that? (2) In your first example, the]]and thethenare on different lines. If you put them on the same line, you must put a;between them.
– G-Man
Dec 19 '18 at 5:54
@G-Man Simply comparing the count of records from 2 different sources. Which syntax should i be using?
– sjd
Dec 19 '18 at 6:02
@G-Man Ooh Sorry .. Now only i understood the "[1]" was part of the output ofcount1. Will try again.. Thanks
– sjd
Dec 19 '18 at 6:21
@sjd: If the output ofcount1is really:[1] "0", then!=should be used inifcondition to compare thestringand anumber. Eg:if [[ "$count1" != "$count2" ]] ;then echo "NE"; fi
– User123
Dec 19 '18 at 6:42
(1) Does your
$count1 value really include brackets and quotes? What sort of result do you expect from input like that? (2) In your first example, the ]] and the then are on different lines. If you put them on the same line, you must put a ; between them.– G-Man
Dec 19 '18 at 5:54
(1) Does your
$count1 value really include brackets and quotes? What sort of result do you expect from input like that? (2) In your first example, the ]] and the then are on different lines. If you put them on the same line, you must put a ; between them.– G-Man
Dec 19 '18 at 5:54
@G-Man Simply comparing the count of records from 2 different sources. Which syntax should i be using?
– sjd
Dec 19 '18 at 6:02
@G-Man Simply comparing the count of records from 2 different sources. Which syntax should i be using?
– sjd
Dec 19 '18 at 6:02
@G-Man Ooh Sorry .. Now only i understood the "[1]" was part of the output of
count1. Will try again.. Thanks– sjd
Dec 19 '18 at 6:21
@G-Man Ooh Sorry .. Now only i understood the "[1]" was part of the output of
count1. Will try again.. Thanks– sjd
Dec 19 '18 at 6:21
@sjd: If the output of
count1 is really: [1] "0", then != should be used in if condition to compare the string and a number. Eg: if [[ "$count1" != "$count2" ]] ;then echo "NE"; fi– User123
Dec 19 '18 at 6:42
@sjd: If the output of
count1 is really: [1] "0", then != should be used in if condition to compare the string and a number. Eg: if [[ "$count1" != "$count2" ]] ;then echo "NE"; fi– User123
Dec 19 '18 at 6:42
add a comment |
1 Answer
1
active
oldest
votes
2
Your count1 variable contains the string [1] "0". This is a eight character string that is not an integer.
Even if the value had been just "0", the test [[ $count1 -ne $count2 ]] with $count1 being "0" is very different from [[ "$count1" -ne "$count2" ]] with $count1 being the single character string 0.
answered Dec 19 '18 at 8:19
Kusalananda
121k16229372
1
even worse,count1seems to contain the seven characters[1] "0". Same syntax error, though.
– ilkkachu
Dec 19 '18 at 8:37
@ilkkachu Ah, I missed that. I'll update in a few minutes. Thanks!
– Kusalananda
Dec 19 '18 at 9:17
Actually the data in count1 was transferred from a R Function. Which always returns the index [1] with the result. once that issue is resolved i cound fix it thanks
– sjd
Dec 19 '18 at 12:00
add a comment |
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1 Answer
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1 Answer
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oldest
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oldest
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2
Your count1 variable contains the string [1] "0". This is a eight character string that is not an integer.
Even if the value had been just "0", the test [[ $count1 -ne $count2 ]] with $count1 being "0" is very different from [[ "$count1" -ne "$count2" ]] with $count1 being the single character string 0.
answered Dec 19 '18 at 8:19
Kusalananda
121k16229372
1
even worse,count1seems to contain the seven characters[1] "0". Same syntax error, though.
– ilkkachu
Dec 19 '18 at 8:37
@ilkkachu Ah, I missed that. I'll update in a few minutes. Thanks!
– Kusalananda
Dec 19 '18 at 9:17
Actually the data in count1 was transferred from a R Function. Which always returns the index [1] with the result. once that issue is resolved i cound fix it thanks
– sjd
Dec 19 '18 at 12:00
add a comment |
2
Your count1 variable contains the string [1] "0". This is a eight character string that is not an integer.
Even if the value had been just "0", the test [[ $count1 -ne $count2 ]] with $count1 being "0" is very different from [[ "$count1" -ne "$count2" ]] with $count1 being the single character string 0.
answered Dec 19 '18 at 8:19
Kusalananda
121k16229372
1
even worse,count1seems to contain the seven characters[1] "0". Same syntax error, though.
– ilkkachu
Dec 19 '18 at 8:37
@ilkkachu Ah, I missed that. I'll update in a few minutes. Thanks!
– Kusalananda
Dec 19 '18 at 9:17
Actually the data in count1 was transferred from a R Function. Which always returns the index [1] with the result. once that issue is resolved i cound fix it thanks
– sjd
Dec 19 '18 at 12:00
add a comment |
2
2
2
Your count1 variable contains the string [1] "0". This is a eight character string that is not an integer.
Even if the value had been just "0", the test [[ $count1 -ne $count2 ]] with $count1 being "0" is very different from [[ "$count1" -ne "$count2" ]] with $count1 being the single character string 0.
answered Dec 19 '18 at 8:19
Kusalananda
121k16229372
Your count1 variable contains the string [1] "0". This is a eight character string that is not an integer.
Even if the value had been just "0", the test [[ $count1 -ne $count2 ]] with $count1 being "0" is very different from [[ "$count1" -ne "$count2" ]] with $count1 being the single character string 0.
answered Dec 19 '18 at 8:19
Kusalananda
121k16229372
edited Dec 19 '18 at 12:12
answered Dec 19 '18 at 8:19
Kusalananda
121k16229372
answered Dec 19 '18 at 8:19
Kusalananda
121k16229372
answered Dec 19 '18 at 8:19
Kusalananda
121k16229372
121k16229372
1
even worse,count1seems to contain the seven characters[1] "0". Same syntax error, though.
– ilkkachu
Dec 19 '18 at 8:37
@ilkkachu Ah, I missed that. I'll update in a few minutes. Thanks!
– Kusalananda
Dec 19 '18 at 9:17
Actually the data in count1 was transferred from a R Function. Which always returns the index [1] with the result. once that issue is resolved i cound fix it thanks
– sjd
Dec 19 '18 at 12:00
add a comment |
1
even worse,count1seems to contain the seven characters[1] "0". Same syntax error, though.
– ilkkachu
Dec 19 '18 at 8:37
@ilkkachu Ah, I missed that. I'll update in a few minutes. Thanks!
– Kusalananda
Dec 19 '18 at 9:17
Actually the data in count1 was transferred from a R Function. Which always returns the index [1] with the result. once that issue is resolved i cound fix it thanks
– sjd
Dec 19 '18 at 12:00
1
1
even worse,
count1 seems to contain the seven characters [1] "0". Same syntax error, though.– ilkkachu
Dec 19 '18 at 8:37
even worse,
count1 seems to contain the seven characters [1] "0". Same syntax error, though.– ilkkachu
Dec 19 '18 at 8:37
@ilkkachu Ah, I missed that. I'll update in a few minutes. Thanks!
– Kusalananda
Dec 19 '18 at 9:17
@ilkkachu Ah, I missed that. I'll update in a few minutes. Thanks!
– Kusalananda
Dec 19 '18 at 9:17
Actually the data in count1 was transferred from a R Function. Which always returns the index [1] with the result. once that issue is resolved i cound fix it thanks
– sjd
Dec 19 '18 at 12:00
Actually the data in count1 was transferred from a R Function. Which always returns the index [1] with the result. once that issue is resolved i cound fix it thanks
– sjd
Dec 19 '18 at 12:00
add a comment |
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(1) Does your
$count1value really include brackets and quotes? What sort of result do you expect from input like that? (2) In your first example, the]]and thethenare on different lines. If you put them on the same line, you must put a;between them.– G-Man
Dec 19 '18 at 5:54
@G-Man Simply comparing the count of records from 2 different sources. Which syntax should i be using?
– sjd
Dec 19 '18 at 6:02
@G-Man Ooh Sorry .. Now only i understood the "[1]" was part of the output of
count1. Will try again.. Thanks– sjd
Dec 19 '18 at 6:21
@sjd: If the output of
count1is really:[1] "0", then!=should be used inifcondition to compare thestringand anumber. Eg:if [[ "$count1" != "$count2" ]] ;then echo "NE"; fi– User123
Dec 19 '18 at 6:42