Elegant way to determine if value is any of a few enum types?












-3














Let say I have an enum called UserRole which contains 100 roles. I am currently checking roles this way:



guard userRole == .admin 
|| userRole == .recruiter
|| ....
else {
...
}


The thing I am repeating all the time is this:



userRole ==


Isn't there something shorter, like:



guard userRole == (.admin | .recruiter | ... )
else {
...
}









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-3














Let say I have an enum called UserRole which contains 100 roles. I am currently checking roles this way:



guard userRole == .admin 
|| userRole == .recruiter
|| ....
else {
...
}


The thing I am repeating all the time is this:



userRole ==


Isn't there something shorter, like:



guard userRole == (.admin | .recruiter | ... )
else {
...
}









share|improve this question







New contributor




J. Doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1




    Like this?
    – esote
    34 mins ago
















-3












-3








-3







Let say I have an enum called UserRole which contains 100 roles. I am currently checking roles this way:



guard userRole == .admin 
|| userRole == .recruiter
|| ....
else {
...
}


The thing I am repeating all the time is this:



userRole ==


Isn't there something shorter, like:



guard userRole == (.admin | .recruiter | ... )
else {
...
}









share|improve this question







New contributor




J. Doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











Let say I have an enum called UserRole which contains 100 roles. I am currently checking roles this way:



guard userRole == .admin 
|| userRole == .recruiter
|| ....
else {
...
}


The thing I am repeating all the time is this:



userRole ==


Isn't there something shorter, like:



guard userRole == (.admin | .recruiter | ... )
else {
...
}






swift






share|improve this question







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J. Doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




J. Doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






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J. Doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 56 mins ago









J. Doe

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New contributor





J. Doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • 1




    Like this?
    – esote
    34 mins ago
















  • 1




    Like this?
    – esote
    34 mins ago










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Like this?
– esote
34 mins ago






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