using std::ios::sync_with_stdio(false) getting “WA”
There are exactly n inputs and in which each entry is getting entered twice
except once but n value may go to 10 000 000 000 spoj ololo
Note-> The xor of two same value is always zero
1^8=9 -> 9^1=8
we can take xor of values while input is getting entered finally we will have a single value that was entered exactly once and all other will be cancelled
But when I am using cin to take input I am getting as TLE but as mentioned in this post cin vs scanf
I changed my program as below
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
cin>>t;
std::ios::sync_with_stdio(false);
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
I am getting as "WA"
But when I am changing the position of std::ios::sync_with_stdio(false);
as
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
std::ios::sync_with_stdio(false);
cin>>t;
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
My answer is getting accepted can any tell me why this is happening ?
c++
asked 13 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
There are exactly n inputs and in which each entry is getting entered twice
except once but n value may go to 10 000 000 000 spoj ololo
Note-> The xor of two same value is always zero
1^8=9 -> 9^1=8
we can take xor of values while input is getting entered finally we will have a single value that was entered exactly once and all other will be cancelled
But when I am using cin to take input I am getting as TLE but as mentioned in this post cin vs scanf
I changed my program as below
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
cin>>t;
std::ios::sync_with_stdio(false);
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
I am getting as "WA"
But when I am changing the position of std::ios::sync_with_stdio(false);
as
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
std::ios::sync_with_stdio(false);
cin>>t;
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
My answer is getting accepted can any tell me why this is happening ?
c++
asked 13 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
There are exactly n inputs and in which each entry is getting entered twice
except once but n value may go to 10 000 000 000 spoj ololo
Note-> The xor of two same value is always zero
1^8=9 -> 9^1=8
we can take xor of values while input is getting entered finally we will have a single value that was entered exactly once and all other will be cancelled
But when I am using cin to take input I am getting as TLE but as mentioned in this post cin vs scanf
I changed my program as below
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
cin>>t;
std::ios::sync_with_stdio(false);
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
I am getting as "WA"
But when I am changing the position of std::ios::sync_with_stdio(false);
as
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
std::ios::sync_with_stdio(false);
cin>>t;
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
My answer is getting accepted can any tell me why this is happening ?
c++
asked 13 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
There are exactly n inputs and in which each entry is getting entered twice
except once but n value may go to 10 000 000 000 spoj ololo
Note-> The xor of two same value is always zero
1^8=9 -> 9^1=8
we can take xor of values while input is getting entered finally we will have a single value that was entered exactly once and all other will be cancelled
But when I am using cin to take input I am getting as TLE but as mentioned in this post cin vs scanf
I changed my program as below
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
cin>>t;
std::ios::sync_with_stdio(false);
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
I am getting as "WA"
But when I am changing the position of std::ios::sync_with_stdio(false);
as
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
std::ios::sync_with_stdio(false);
cin>>t;
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
My answer is getting accepted can any tell me why this is happening ?
c++
c++
asked 13 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 13 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 13 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 13 mins ago
ney123ney123
1
asked 13 mins ago
ney123ney123
1
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "196"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
ney123 is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f211406%2fusing-stdiossync-with-stdiofalse-getting-wa%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
ney123 is a new contributor. Be nice, and check out our Code of Conduct.
ney123 is a new contributor. Be nice, and check out our Code of Conduct.
ney123 is a new contributor. Be nice, and check out our Code of Conduct.
ney123 is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f211406%2fusing-stdiossync-with-stdiofalse-getting-wa%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
