Start range from 1 onward
I am counting multiple log files with the range starting from 1 onward however it's starting from 0.
path=(/home/folder/text/*)
for 1 int ${!path}; do
printf "$s: $sn" $i "${list[i]##*/}";
done
shell-script array for
edited Jan 3 at 16:15
Kusalananda
124k16232382
asked Jan 3 at 11:36
User101User101
584
add a comment |
I am counting multiple log files with the range starting from 1 onward however it's starting from 0.
path=(/home/folder/text/*)
for 1 int ${!path}; do
printf "$s: $sn" $i "${list[i]##*/}";
done
shell-script array for
edited Jan 3 at 16:15
Kusalananda
124k16232382
asked Jan 3 at 11:36
User101User101
584
add a comment |
I am counting multiple log files with the range starting from 1 onward however it's starting from 0.
path=(/home/folder/text/*)
for 1 int ${!path}; do
printf "$s: $sn" $i "${list[i]##*/}";
done
shell-script array for
edited Jan 3 at 16:15
Kusalananda
124k16232382
asked Jan 3 at 11:36
User101User101
584
I am counting multiple log files with the range starting from 1 onward however it's starting from 0.
path=(/home/folder/text/*)
for 1 int ${!path}; do
printf "$s: $sn" $i "${list[i]##*/}";
done
shell-script array for
shell-script array for
edited Jan 3 at 16:15
Kusalananda
124k16232382
asked Jan 3 at 11:36
User101User101
584
edited Jan 3 at 16:15
Kusalananda
124k16232382
asked Jan 3 at 11:36
User101User101
584
edited Jan 3 at 16:15
Kusalananda
124k16232382
edited Jan 3 at 16:15
Kusalananda
124k16232382
edited Jan 3 at 16:15
Kusalananda
124k16232382
124k16232382
asked Jan 3 at 11:36
User101User101
584
asked Jan 3 at 11:36
User101User101
584
asked Jan 3 at 11:36
User101User101
584
584
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered Jan 3 at 12:27
KusalanandaKusalananda
124k16232382
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered Jan 3 at 12:27
KusalanandaKusalananda
124k16232382
add a comment |
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered Jan 3 at 12:27
KusalanandaKusalananda
124k16232382
add a comment |
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered Jan 3 at 12:27
KusalanandaKusalananda
124k16232382
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered Jan 3 at 12:27
KusalanandaKusalananda
124k16232382
edited Jan 3 at 14:49
answered Jan 3 at 12:27
KusalanandaKusalananda
124k16232382
answered Jan 3 at 12:27
KusalanandaKusalananda
124k16232382
answered Jan 3 at 12:27
KusalanandaKusalananda
124k16232382
124k16232382
add a comment |
add a comment |
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