Deletion of a line in a file using perl on solaris












-1















I am trying to delete a particular line in a file using a perl program on solaris. I tried sed but it is not working.



I tried sed /pattern/d filename but it failed. Then I realized that I was actually passing a variable (containing a word of the line that has to be deleted). So basically i was trying sed /$var/d filename which was obviously failing.



So i modified it with a backslash before the variable hoping that would solve my problem



sed /$var/d filename



but that too didn't work. The file remains the same.










share|improve this question


















  • 1





    Using sed "/$var/d" filename should output to stdout the file with the line deleted unless the variable contains a /. The file is expected to remain unchanged. Some versions of sed have a -i flag to do an inplace edit. Typically you would do sed "/$var/d" filename > filename.tmp && mv filename.tmp filename

    – icarus
    Jan 3 at 7:35











  • @icarus nope when i exclude before $ it says command garbled. and i also tried filename>filename.tmp but filename.tmp itself has the line which i want to delete. so it is not reflecting.

    – Mr.AG
    Jan 3 at 9:05











  • @icarus Some versions of sed have a -i flag to do an inplace edit. Beware. That's implemented in GNU sed behind-the-scenes using a temporary file with a rename. "GNU sed does this by creating a temporary file and sending output to this file rather than to the standard output. ... the temporary file is renamed to the output file’s original name." In short, it doesn't really edit the same file inplace, as it creates a new file with the old file's name, thus breaking hard links.

    – Andrew Henle
    Jan 3 at 10:33











  • @Mr.AG what is the value of the variable?

    – icarus
    Jan 3 at 12:32











  • @icarus just a string.

    – Mr.AG
    Jan 4 at 9:43
















-1















I am trying to delete a particular line in a file using a perl program on solaris. I tried sed but it is not working.



I tried sed /pattern/d filename but it failed. Then I realized that I was actually passing a variable (containing a word of the line that has to be deleted). So basically i was trying sed /$var/d filename which was obviously failing.



So i modified it with a backslash before the variable hoping that would solve my problem



sed /$var/d filename



but that too didn't work. The file remains the same.










share|improve this question


















  • 1





    Using sed "/$var/d" filename should output to stdout the file with the line deleted unless the variable contains a /. The file is expected to remain unchanged. Some versions of sed have a -i flag to do an inplace edit. Typically you would do sed "/$var/d" filename > filename.tmp && mv filename.tmp filename

    – icarus
    Jan 3 at 7:35











  • @icarus nope when i exclude before $ it says command garbled. and i also tried filename>filename.tmp but filename.tmp itself has the line which i want to delete. so it is not reflecting.

    – Mr.AG
    Jan 3 at 9:05











  • @icarus Some versions of sed have a -i flag to do an inplace edit. Beware. That's implemented in GNU sed behind-the-scenes using a temporary file with a rename. "GNU sed does this by creating a temporary file and sending output to this file rather than to the standard output. ... the temporary file is renamed to the output file’s original name." In short, it doesn't really edit the same file inplace, as it creates a new file with the old file's name, thus breaking hard links.

    – Andrew Henle
    Jan 3 at 10:33











  • @Mr.AG what is the value of the variable?

    – icarus
    Jan 3 at 12:32











  • @icarus just a string.

    – Mr.AG
    Jan 4 at 9:43














-1












-1








-1








I am trying to delete a particular line in a file using a perl program on solaris. I tried sed but it is not working.



I tried sed /pattern/d filename but it failed. Then I realized that I was actually passing a variable (containing a word of the line that has to be deleted). So basically i was trying sed /$var/d filename which was obviously failing.



So i modified it with a backslash before the variable hoping that would solve my problem



sed /$var/d filename



but that too didn't work. The file remains the same.










share|improve this question














I am trying to delete a particular line in a file using a perl program on solaris. I tried sed but it is not working.



I tried sed /pattern/d filename but it failed. Then I realized that I was actually passing a variable (containing a word of the line that has to be deleted). So basically i was trying sed /$var/d filename which was obviously failing.



So i modified it with a backslash before the variable hoping that would solve my problem



sed /$var/d filename



but that too didn't work. The file remains the same.







files solaris delete






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 3 at 6:18









Mr.AGMr.AG

93




93








  • 1





    Using sed "/$var/d" filename should output to stdout the file with the line deleted unless the variable contains a /. The file is expected to remain unchanged. Some versions of sed have a -i flag to do an inplace edit. Typically you would do sed "/$var/d" filename > filename.tmp && mv filename.tmp filename

    – icarus
    Jan 3 at 7:35











  • @icarus nope when i exclude before $ it says command garbled. and i also tried filename>filename.tmp but filename.tmp itself has the line which i want to delete. so it is not reflecting.

    – Mr.AG
    Jan 3 at 9:05











  • @icarus Some versions of sed have a -i flag to do an inplace edit. Beware. That's implemented in GNU sed behind-the-scenes using a temporary file with a rename. "GNU sed does this by creating a temporary file and sending output to this file rather than to the standard output. ... the temporary file is renamed to the output file’s original name." In short, it doesn't really edit the same file inplace, as it creates a new file with the old file's name, thus breaking hard links.

    – Andrew Henle
    Jan 3 at 10:33











  • @Mr.AG what is the value of the variable?

    – icarus
    Jan 3 at 12:32











  • @icarus just a string.

    – Mr.AG
    Jan 4 at 9:43














  • 1





    Using sed "/$var/d" filename should output to stdout the file with the line deleted unless the variable contains a /. The file is expected to remain unchanged. Some versions of sed have a -i flag to do an inplace edit. Typically you would do sed "/$var/d" filename > filename.tmp && mv filename.tmp filename

    – icarus
    Jan 3 at 7:35











  • @icarus nope when i exclude before $ it says command garbled. and i also tried filename>filename.tmp but filename.tmp itself has the line which i want to delete. so it is not reflecting.

    – Mr.AG
    Jan 3 at 9:05











  • @icarus Some versions of sed have a -i flag to do an inplace edit. Beware. That's implemented in GNU sed behind-the-scenes using a temporary file with a rename. "GNU sed does this by creating a temporary file and sending output to this file rather than to the standard output. ... the temporary file is renamed to the output file’s original name." In short, it doesn't really edit the same file inplace, as it creates a new file with the old file's name, thus breaking hard links.

    – Andrew Henle
    Jan 3 at 10:33











  • @Mr.AG what is the value of the variable?

    – icarus
    Jan 3 at 12:32











  • @icarus just a string.

    – Mr.AG
    Jan 4 at 9:43








1




1





Using sed "/$var/d" filename should output to stdout the file with the line deleted unless the variable contains a /. The file is expected to remain unchanged. Some versions of sed have a -i flag to do an inplace edit. Typically you would do sed "/$var/d" filename > filename.tmp && mv filename.tmp filename

– icarus
Jan 3 at 7:35





Using sed "/$var/d" filename should output to stdout the file with the line deleted unless the variable contains a /. The file is expected to remain unchanged. Some versions of sed have a -i flag to do an inplace edit. Typically you would do sed "/$var/d" filename > filename.tmp && mv filename.tmp filename

– icarus
Jan 3 at 7:35













@icarus nope when i exclude before $ it says command garbled. and i also tried filename>filename.tmp but filename.tmp itself has the line which i want to delete. so it is not reflecting.

– Mr.AG
Jan 3 at 9:05





@icarus nope when i exclude before $ it says command garbled. and i also tried filename>filename.tmp but filename.tmp itself has the line which i want to delete. so it is not reflecting.

– Mr.AG
Jan 3 at 9:05













@icarus Some versions of sed have a -i flag to do an inplace edit. Beware. That's implemented in GNU sed behind-the-scenes using a temporary file with a rename. "GNU sed does this by creating a temporary file and sending output to this file rather than to the standard output. ... the temporary file is renamed to the output file’s original name." In short, it doesn't really edit the same file inplace, as it creates a new file with the old file's name, thus breaking hard links.

– Andrew Henle
Jan 3 at 10:33





@icarus Some versions of sed have a -i flag to do an inplace edit. Beware. That's implemented in GNU sed behind-the-scenes using a temporary file with a rename. "GNU sed does this by creating a temporary file and sending output to this file rather than to the standard output. ... the temporary file is renamed to the output file’s original name." In short, it doesn't really edit the same file inplace, as it creates a new file with the old file's name, thus breaking hard links.

– Andrew Henle
Jan 3 at 10:33













@Mr.AG what is the value of the variable?

– icarus
Jan 3 at 12:32





@Mr.AG what is the value of the variable?

– icarus
Jan 3 at 12:32













@icarus just a string.

– Mr.AG
Jan 4 at 9:43





@icarus just a string.

– Mr.AG
Jan 4 at 9:43










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