Taking text from a file and formatting it
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My code takes numbers from a large text file, then splits it to organise the spacing and to place it into a 2-dimensional array. The code is used to get data for a job scheduler that I'm building.
#reading in workload data
def getworkload():
work =
strings =
with open("workload.txt") as f:
read_data = f.read()
jobs = read_data.split("n")
for j in jobs:
strings.append(" ".join(j.split()))
for i in strings:
work.append([float(s) for s in i.split(" ")])
return work
print(getworkload())
The text file is over 2000 lines long, and looks like this:
1 0 1835117 330855 640 5886 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
2 0 2265800 251924 640 3124 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
3 1 3114175 -1 640 -1 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
4 1813487 7481 -1 128 -1 20250 -1 -1 -1 5 3 1 5 8 -1 -1 -1
5 1814044 0 122 512 1.13 1181 -1 -1 -1 1 1 1 1 9 -1 -1 -1
6 1814374 1 51 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
7 1814511 0 55 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
8 1814695 1 51 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
9 1815198 0 75 512 2.14 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
10 1815617 0 115 512 1.87 1181 -1 -1 -1 1 1 1 1 9 -1 -1 -1
…
It takes 2 and a half minutes to run but I can print the returned data. How can it be optimised?
python performance csv formatting
add a comment |
up vote
0
down vote
favorite
My code takes numbers from a large text file, then splits it to organise the spacing and to place it into a 2-dimensional array. The code is used to get data for a job scheduler that I'm building.
#reading in workload data
def getworkload():
work =
strings =
with open("workload.txt") as f:
read_data = f.read()
jobs = read_data.split("n")
for j in jobs:
strings.append(" ".join(j.split()))
for i in strings:
work.append([float(s) for s in i.split(" ")])
return work
print(getworkload())
The text file is over 2000 lines long, and looks like this:
1 0 1835117 330855 640 5886 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
2 0 2265800 251924 640 3124 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
3 1 3114175 -1 640 -1 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
4 1813487 7481 -1 128 -1 20250 -1 -1 -1 5 3 1 5 8 -1 -1 -1
5 1814044 0 122 512 1.13 1181 -1 -1 -1 1 1 1 1 9 -1 -1 -1
6 1814374 1 51 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
7 1814511 0 55 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
8 1814695 1 51 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
9 1815198 0 75 512 2.14 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
10 1815617 0 115 512 1.87 1181 -1 -1 -1 1 1 1 1 9 -1 -1 -1
…
It takes 2 and a half minutes to run but I can print the returned data. How can it be optimised?
python performance csv formatting
1
Welcome on Code Review. I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. If you're having trouble getting something working, or ask for features, then you'd better ask on StackOverflow (the main site)
– Calak
Nov 12 at 11:07
The code works, as I can print work_row with out any problems and I know that work will be a two dimensional array/list. I just believe it can be sped up.
– timtti
Nov 12 at 11:11
1
"If I try to print work the text is too long and I get an overflow error" for me it's sounds lile you have a problem. Try to reformulated your question to get rid of this doubt.
– Calak
Nov 12 at 11:26
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
My code takes numbers from a large text file, then splits it to organise the spacing and to place it into a 2-dimensional array. The code is used to get data for a job scheduler that I'm building.
#reading in workload data
def getworkload():
work =
strings =
with open("workload.txt") as f:
read_data = f.read()
jobs = read_data.split("n")
for j in jobs:
strings.append(" ".join(j.split()))
for i in strings:
work.append([float(s) for s in i.split(" ")])
return work
print(getworkload())
The text file is over 2000 lines long, and looks like this:
1 0 1835117 330855 640 5886 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
2 0 2265800 251924 640 3124 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
3 1 3114175 -1 640 -1 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
4 1813487 7481 -1 128 -1 20250 -1 -1 -1 5 3 1 5 8 -1 -1 -1
5 1814044 0 122 512 1.13 1181 -1 -1 -1 1 1 1 1 9 -1 -1 -1
6 1814374 1 51 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
7 1814511 0 55 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
8 1814695 1 51 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
9 1815198 0 75 512 2.14 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
10 1815617 0 115 512 1.87 1181 -1 -1 -1 1 1 1 1 9 -1 -1 -1
…
It takes 2 and a half minutes to run but I can print the returned data. How can it be optimised?
python performance csv formatting
My code takes numbers from a large text file, then splits it to organise the spacing and to place it into a 2-dimensional array. The code is used to get data for a job scheduler that I'm building.
#reading in workload data
def getworkload():
work =
strings =
with open("workload.txt") as f:
read_data = f.read()
jobs = read_data.split("n")
for j in jobs:
strings.append(" ".join(j.split()))
for i in strings:
work.append([float(s) for s in i.split(" ")])
return work
print(getworkload())
The text file is over 2000 lines long, and looks like this:
1 0 1835117 330855 640 5886 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
2 0 2265800 251924 640 3124 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
3 1 3114175 -1 640 -1 945 -1 -1 -1 5 2 1 4 9 -1 -1 -1
4 1813487 7481 -1 128 -1 20250 -1 -1 -1 5 3 1 5 8 -1 -1 -1
5 1814044 0 122 512 1.13 1181 -1 -1 -1 1 1 1 1 9 -1 -1 -1
6 1814374 1 51 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
7 1814511 0 55 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
8 1814695 1 51 512 -1 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
9 1815198 0 75 512 2.14 1181 -1 -1 -1 1 1 1 2 9 -1 -1 -1
10 1815617 0 115 512 1.87 1181 -1 -1 -1 1 1 1 1 9 -1 -1 -1
…
It takes 2 and a half minutes to run but I can print the returned data. How can it be optimised?
python performance csv formatting
python performance csv formatting
edited Nov 13 at 7:15
200_success
127k15148410
127k15148410
asked Nov 12 at 10:59
timtti
83
83
1
Welcome on Code Review. I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. If you're having trouble getting something working, or ask for features, then you'd better ask on StackOverflow (the main site)
– Calak
Nov 12 at 11:07
The code works, as I can print work_row with out any problems and I know that work will be a two dimensional array/list. I just believe it can be sped up.
– timtti
Nov 12 at 11:11
1
"If I try to print work the text is too long and I get an overflow error" for me it's sounds lile you have a problem. Try to reformulated your question to get rid of this doubt.
– Calak
Nov 12 at 11:26
add a comment |
1
Welcome on Code Review. I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. If you're having trouble getting something working, or ask for features, then you'd better ask on StackOverflow (the main site)
– Calak
Nov 12 at 11:07
The code works, as I can print work_row with out any problems and I know that work will be a two dimensional array/list. I just believe it can be sped up.
– timtti
Nov 12 at 11:11
1
"If I try to print work the text is too long and I get an overflow error" for me it's sounds lile you have a problem. Try to reformulated your question to get rid of this doubt.
– Calak
Nov 12 at 11:26
1
1
Welcome on Code Review. I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. If you're having trouble getting something working, or ask for features, then you'd better ask on StackOverflow (the main site)
– Calak
Nov 12 at 11:07
Welcome on Code Review. I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. If you're having trouble getting something working, or ask for features, then you'd better ask on StackOverflow (the main site)
– Calak
Nov 12 at 11:07
The code works, as I can print work_row with out any problems and I know that work will be a two dimensional array/list. I just believe it can be sped up.
– timtti
Nov 12 at 11:11
The code works, as I can print work_row with out any problems and I know that work will be a two dimensional array/list. I just believe it can be sped up.
– timtti
Nov 12 at 11:11
1
1
"If I try to print work the text is too long and I get an overflow error" for me it's sounds lile you have a problem. Try to reformulated your question to get rid of this doubt.
– Calak
Nov 12 at 11:26
"If I try to print work the text is too long and I get an overflow error" for me it's sounds lile you have a problem. Try to reformulated your question to get rid of this doubt.
– Calak
Nov 12 at 11:26
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
You are doing a lot of unnecessary work. Why split each row only to join it with single spaces and then split it again by those single spaces?
Instead, here is a list comprehension that should do the same thing:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
return [[float(x) for x in row.split()] for row in f]
This uses the fact that files are iterable and when iterating over them you get each row on its own.
If this is still too slow (or e.g. too large to fit into memory), then you need to process each row separately. For this you would make this a generator of processed lines:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
for row in f:
yield [float(x) for x in row.split()]
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
You are doing a lot of unnecessary work. Why split each row only to join it with single spaces and then split it again by those single spaces?
Instead, here is a list comprehension that should do the same thing:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
return [[float(x) for x in row.split()] for row in f]
This uses the fact that files are iterable and when iterating over them you get each row on its own.
If this is still too slow (or e.g. too large to fit into memory), then you need to process each row separately. For this you would make this a generator of processed lines:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
for row in f:
yield [float(x) for x in row.split()]
add a comment |
up vote
1
down vote
accepted
You are doing a lot of unnecessary work. Why split each row only to join it with single spaces and then split it again by those single spaces?
Instead, here is a list comprehension that should do the same thing:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
return [[float(x) for x in row.split()] for row in f]
This uses the fact that files are iterable and when iterating over them you get each row on its own.
If this is still too slow (or e.g. too large to fit into memory), then you need to process each row separately. For this you would make this a generator of processed lines:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
for row in f:
yield [float(x) for x in row.split()]
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
You are doing a lot of unnecessary work. Why split each row only to join it with single spaces and then split it again by those single spaces?
Instead, here is a list comprehension that should do the same thing:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
return [[float(x) for x in row.split()] for row in f]
This uses the fact that files are iterable and when iterating over them you get each row on its own.
If this is still too slow (or e.g. too large to fit into memory), then you need to process each row separately. For this you would make this a generator of processed lines:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
for row in f:
yield [float(x) for x in row.split()]
You are doing a lot of unnecessary work. Why split each row only to join it with single spaces and then split it again by those single spaces?
Instead, here is a list comprehension that should do the same thing:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
return [[float(x) for x in row.split()] for row in f]
This uses the fact that files are iterable and when iterating over them you get each row on its own.
If this is still too slow (or e.g. too large to fit into memory), then you need to process each row separately. For this you would make this a generator of processed lines:
def get_workload(file_name="workload.txt"):
with open(file_name) as f:
for row in f:
yield [float(x) for x in row.split()]
edited Nov 15 at 16:13
answered Nov 12 at 15:51
Graipher
22k53183
22k53183
add a comment |
add a comment |
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1
Welcome on Code Review. I'm afraid this question does not match what this site is about. Code Review is about improving existing, working code. If you're having trouble getting something working, or ask for features, then you'd better ask on StackOverflow (the main site)
– Calak
Nov 12 at 11:07
The code works, as I can print work_row with out any problems and I know that work will be a two dimensional array/list. I just believe it can be sped up.
– timtti
Nov 12 at 11:11
1
"If I try to print work the text is too long and I get an overflow error" for me it's sounds lile you have a problem. Try to reformulated your question to get rid of this doubt.
– Calak
Nov 12 at 11:26