Using find, how to classify like ls -F ? (directories with a trailing slash)












1














I use find to get a list of files, then I grep it to do a path matching :



$ find pc* | grep -i arthur

pc6/arthurv/untitled-2.py

pc6/arthurv/untitled-3.py

pc6/arthur.py

pc9/Arthur 4C

pc9/Arthur 4C/untitled-1.py

pc9/Arthur 4C/untitled-2.py


I would like to do like in ls -F and append a / for each directory.



Alternatively, how do I get find to show all directories matching case insensitive arthur ?






bash grep find







share|improve this question






















  • Related: How to use wc and piping to find how many files and directories are in a certain directory?
    – Stéphane Chazelas
    Dec 19 '18 at 9:06
















1














I use find to get a list of files, then I grep it to do a path matching :



$ find pc* | grep -i arthur

pc6/arthurv/untitled-2.py

pc6/arthurv/untitled-3.py

pc6/arthur.py

pc9/Arthur 4C

pc9/Arthur 4C/untitled-1.py

pc9/Arthur 4C/untitled-2.py


I would like to do like in ls -F and append a / for each directory.



Alternatively, how do I get find to show all directories matching case insensitive arthur ?






bash grep find







share|improve this question






















  • Related: How to use wc and piping to find how many files and directories are in a certain directory?
    – Stéphane Chazelas
    Dec 19 '18 at 9:06














1












1








1







I use find to get a list of files, then I grep it to do a path matching :



$ find pc* | grep -i arthur

pc6/arthurv/untitled-2.py

pc6/arthurv/untitled-3.py

pc6/arthur.py

pc9/Arthur 4C

pc9/Arthur 4C/untitled-1.py

pc9/Arthur 4C/untitled-2.py


I would like to do like in ls -F and append a / for each directory.



Alternatively, how do I get find to show all directories matching case insensitive arthur ?






bash grep find







share|improve this question













I use find to get a list of files, then I grep it to do a path matching :



$ find pc* | grep -i arthur

pc6/arthurv/untitled-2.py

pc6/arthurv/untitled-3.py

pc6/arthur.py

pc9/Arthur 4C

pc9/Arthur 4C/untitled-1.py

pc9/Arthur 4C/untitled-2.py


I would like to do like in ls -F and append a / for each directory.



Alternatively, how do I get find to show all directories matching case insensitive arthur ?






bash grep find




bash grep find






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Dec 19 '18 at 8:27









Robert Vanden Eynde

155




155












  • Related: How to use wc and piping to find how many files and directories are in a certain directory?
    – Stéphane Chazelas
    Dec 19 '18 at 9:06


















  • Related: How to use wc and piping to find how many files and directories are in a certain directory?
    – Stéphane Chazelas
    Dec 19 '18 at 9:06
















Related: How to use wc and piping to find how many files and directories are in a certain directory?
– Stéphane Chazelas
Dec 19 '18 at 9:06




Related: How to use wc and piping to find how many files and directories are in a certain directory?
– Stéphane Chazelas
Dec 19 '18 at 9:06










2 Answers
2






active

oldest

votes


















3














You can use disjunctions in find expressions to implement conditional processing; with GNU find:



find pc* -type d -printf "%p/n" -o -print


will find everything in paths starting with the files and directories matching “pc*”, and print their names, followed by a “/” if they’re directories.



The way this works is as follows:





  • pc* specifies the paths to start from;


  • -type d matches directories;


  • -printf "%p/n" prints the path to the currently-processed file, followed by “/” and a newline; because it follows -type d, it is only executed if -type d matched (there’s an implicit conjunction);


  • -o introduces a disjunction: the expression following it will be evaluated if the expression preceding it did not match (and the expression preceding it is -type d -printf "%p/n" here, because conjunctions have higher precedence than disjunctions);


  • -print prints the path to the currently-processed file.


Showing all directories matching case-insensitive “arthur” can be done using other find expressions:



find . -type d -iname "*arthur*"





share|improve this answer























  • Exactly what I was looking for, however I understand easily the second code and the third but not the first one, I would put it last and explain more in details.
    – Robert Vanden Eynde
    Dec 19 '18 at 8:53










  • You removerd the version find pc* ( -type d -printf "%p/n" ) -o ( ! -type d -print ), just curious about what the parenthesis and the ! meant ? :)
    – Robert Vanden Eynde
    Dec 22 '18 at 21:13






  • 1




    The parentheses group expressions, and ! negates an expression. So ( -type d -printf "%p/n" ) -o ( ! -type d -print ) tells find to consider -type d -printf "%p/n" on the one hand, and ! -type d -print on the other; and ! -type d matches anything which isn’t a directory.
    – Stephen Kitt
    Dec 22 '18 at 21:25



















1














find has a huge amount of options and details. Another variant is to use printf with %y



$ find . -printf "%p:%yn"

./dir:d

./file:f


where %y adds a "d" or a "f" just like ls -l



$ find . -printf "%p%yn" | sed 's!d$!/! ; s!f$!!'





share|improve this answer





















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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3














    You can use disjunctions in find expressions to implement conditional processing; with GNU find:



    find pc* -type d -printf "%p/n" -o -print


    will find everything in paths starting with the files and directories matching “pc*”, and print their names, followed by a “/” if they’re directories.



    The way this works is as follows:





    • pc* specifies the paths to start from;


    • -type d matches directories;


    • -printf "%p/n" prints the path to the currently-processed file, followed by “/” and a newline; because it follows -type d, it is only executed if -type d matched (there’s an implicit conjunction);


    • -o introduces a disjunction: the expression following it will be evaluated if the expression preceding it did not match (and the expression preceding it is -type d -printf "%p/n" here, because conjunctions have higher precedence than disjunctions);


    • -print prints the path to the currently-processed file.


    Showing all directories matching case-insensitive “arthur” can be done using other find expressions:



    find . -type d -iname "*arthur*"





    share|improve this answer























    • Exactly what I was looking for, however I understand easily the second code and the third but not the first one, I would put it last and explain more in details.
      – Robert Vanden Eynde
      Dec 19 '18 at 8:53










    • You removerd the version find pc* ( -type d -printf "%p/n" ) -o ( ! -type d -print ), just curious about what the parenthesis and the ! meant ? :)
      – Robert Vanden Eynde
      Dec 22 '18 at 21:13






    • 1




      The parentheses group expressions, and ! negates an expression. So ( -type d -printf "%p/n" ) -o ( ! -type d -print ) tells find to consider -type d -printf "%p/n" on the one hand, and ! -type d -print on the other; and ! -type d matches anything which isn’t a directory.
      – Stephen Kitt
      Dec 22 '18 at 21:25
















    3














    You can use disjunctions in find expressions to implement conditional processing; with GNU find:



    find pc* -type d -printf "%p/n" -o -print


    will find everything in paths starting with the files and directories matching “pc*”, and print their names, followed by a “/” if they’re directories.



    The way this works is as follows:





    • pc* specifies the paths to start from;


    • -type d matches directories;


    • -printf "%p/n" prints the path to the currently-processed file, followed by “/” and a newline; because it follows -type d, it is only executed if -type d matched (there’s an implicit conjunction);


    • -o introduces a disjunction: the expression following it will be evaluated if the expression preceding it did not match (and the expression preceding it is -type d -printf "%p/n" here, because conjunctions have higher precedence than disjunctions);


    • -print prints the path to the currently-processed file.


    Showing all directories matching case-insensitive “arthur” can be done using other find expressions:



    find . -type d -iname "*arthur*"





    share|improve this answer























    • Exactly what I was looking for, however I understand easily the second code and the third but not the first one, I would put it last and explain more in details.
      – Robert Vanden Eynde
      Dec 19 '18 at 8:53










    • You removerd the version find pc* ( -type d -printf "%p/n" ) -o ( ! -type d -print ), just curious about what the parenthesis and the ! meant ? :)
      – Robert Vanden Eynde
      Dec 22 '18 at 21:13






    • 1




      The parentheses group expressions, and ! negates an expression. So ( -type d -printf "%p/n" ) -o ( ! -type d -print ) tells find to consider -type d -printf "%p/n" on the one hand, and ! -type d -print on the other; and ! -type d matches anything which isn’t a directory.
      – Stephen Kitt
      Dec 22 '18 at 21:25














    3












    3








    3






    You can use disjunctions in find expressions to implement conditional processing; with GNU find:



    find pc* -type d -printf "%p/n" -o -print


    will find everything in paths starting with the files and directories matching “pc*”, and print their names, followed by a “/” if they’re directories.



    The way this works is as follows:





    • pc* specifies the paths to start from;


    • -type d matches directories;


    • -printf "%p/n" prints the path to the currently-processed file, followed by “/” and a newline; because it follows -type d, it is only executed if -type d matched (there’s an implicit conjunction);


    • -o introduces a disjunction: the expression following it will be evaluated if the expression preceding it did not match (and the expression preceding it is -type d -printf "%p/n" here, because conjunctions have higher precedence than disjunctions);


    • -print prints the path to the currently-processed file.


    Showing all directories matching case-insensitive “arthur” can be done using other find expressions:



    find . -type d -iname "*arthur*"





    share|improve this answer














    You can use disjunctions in find expressions to implement conditional processing; with GNU find:



    find pc* -type d -printf "%p/n" -o -print


    will find everything in paths starting with the files and directories matching “pc*”, and print their names, followed by a “/” if they’re directories.



    The way this works is as follows:





    • pc* specifies the paths to start from;


    • -type d matches directories;


    • -printf "%p/n" prints the path to the currently-processed file, followed by “/” and a newline; because it follows -type d, it is only executed if -type d matched (there’s an implicit conjunction);


    • -o introduces a disjunction: the expression following it will be evaluated if the expression preceding it did not match (and the expression preceding it is -type d -printf "%p/n" here, because conjunctions have higher precedence than disjunctions);


    • -print prints the path to the currently-processed file.


    Showing all directories matching case-insensitive “arthur” can be done using other find expressions:



    find . -type d -iname "*arthur*"






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Dec 19 '18 at 9:03

























    answered Dec 19 '18 at 8:31









    Stephen Kitt

    164k24365444




    164k24365444












    • Exactly what I was looking for, however I understand easily the second code and the third but not the first one, I would put it last and explain more in details.
      – Robert Vanden Eynde
      Dec 19 '18 at 8:53










    • You removerd the version find pc* ( -type d -printf "%p/n" ) -o ( ! -type d -print ), just curious about what the parenthesis and the ! meant ? :)
      – Robert Vanden Eynde
      Dec 22 '18 at 21:13






    • 1




      The parentheses group expressions, and ! negates an expression. So ( -type d -printf "%p/n" ) -o ( ! -type d -print ) tells find to consider -type d -printf "%p/n" on the one hand, and ! -type d -print on the other; and ! -type d matches anything which isn’t a directory.
      – Stephen Kitt
      Dec 22 '18 at 21:25


















    • Exactly what I was looking for, however I understand easily the second code and the third but not the first one, I would put it last and explain more in details.
      – Robert Vanden Eynde
      Dec 19 '18 at 8:53










    • You removerd the version find pc* ( -type d -printf "%p/n" ) -o ( ! -type d -print ), just curious about what the parenthesis and the ! meant ? :)
      – Robert Vanden Eynde
      Dec 22 '18 at 21:13






    • 1




      The parentheses group expressions, and ! negates an expression. So ( -type d -printf "%p/n" ) -o ( ! -type d -print ) tells find to consider -type d -printf "%p/n" on the one hand, and ! -type d -print on the other; and ! -type d matches anything which isn’t a directory.
      – Stephen Kitt
      Dec 22 '18 at 21:25
















    Exactly what I was looking for, however I understand easily the second code and the third but not the first one, I would put it last and explain more in details.
    – Robert Vanden Eynde
    Dec 19 '18 at 8:53




    Exactly what I was looking for, however I understand easily the second code and the third but not the first one, I would put it last and explain more in details.
    – Robert Vanden Eynde
    Dec 19 '18 at 8:53












    You removerd the version find pc* ( -type d -printf "%p/n" ) -o ( ! -type d -print ), just curious about what the parenthesis and the ! meant ? :)
    – Robert Vanden Eynde
    Dec 22 '18 at 21:13




    You removerd the version find pc* ( -type d -printf "%p/n" ) -o ( ! -type d -print ), just curious about what the parenthesis and the ! meant ? :)
    – Robert Vanden Eynde
    Dec 22 '18 at 21:13




    1




    1




    The parentheses group expressions, and ! negates an expression. So ( -type d -printf "%p/n" ) -o ( ! -type d -print ) tells find to consider -type d -printf "%p/n" on the one hand, and ! -type d -print on the other; and ! -type d matches anything which isn’t a directory.
    – Stephen Kitt
    Dec 22 '18 at 21:25




    The parentheses group expressions, and ! negates an expression. So ( -type d -printf "%p/n" ) -o ( ! -type d -print ) tells find to consider -type d -printf "%p/n" on the one hand, and ! -type d -print on the other; and ! -type d matches anything which isn’t a directory.
    – Stephen Kitt
    Dec 22 '18 at 21:25













    1














    find has a huge amount of options and details. Another variant is to use printf with %y



    $ find . -printf "%p:%yn"
    
./dir:d
    
./file:f


    where %y adds a "d" or a "f" just like ls -l



    $ find . -printf "%p%yn" | sed 's!d$!/! ; s!f$!!'





    share|improve this answer


























      1














      find has a huge amount of options and details. Another variant is to use printf with %y



      $ find . -printf "%p:%yn"
      
./dir:d
      
./file:f


      where %y adds a "d" or a "f" just like ls -l



      $ find . -printf "%p%yn" | sed 's!d$!/! ; s!f$!!'





      share|improve this answer
























        1












        1








        1






        find has a huge amount of options and details. Another variant is to use printf with %y



        $ find . -printf "%p:%yn"
        
./dir:d
        
./file:f


        where %y adds a "d" or a "f" just like ls -l



        $ find . -printf "%p%yn" | sed 's!d$!/! ; s!f$!!'





        share|improve this answer












        find has a huge amount of options and details. Another variant is to use printf with %y



        $ find . -printf "%p:%yn"
        
./dir:d
        
./file:f


        where %y adds a "d" or a "f" just like ls -l



        $ find . -printf "%p%yn" | sed 's!d$!/! ; s!f$!!'






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 19 '18 at 9:05









        JJoao

        7,1041928




        7,1041928






























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