Cfrtjryk

below is a script that displays a menu, when I run it like ./menu.sh it works, but when I run it like this: ./menu.sh | bash

I get a lot of commands not found.

The reason I want to run it with | bash is because it will be on an ftp server and I need to run it from different remote locations. so I just do a curl -s to the ftp and if i do not use the | bash I just cat a printout of the code

    #!/bin/bash



#$path=./





while :

do

    echo " "

    echo " "

    echo "===== MAIN - MENU ====="





    echo "1. Run old sanity script"

    echo "2. Asterisk"

    echo "3. Audio"

    echo "4. CoCo"

    echo "5. Database"

    echo "6. Mobile"

    echo "7. SSH"

    echo "8. Touch"

    echo "9. VDS"

    echo "10. Wireshark"





    echo -----------------------

    echo "q. Quit"

    echo "r. Reload"

    echo "======================="



    echo -n "Please enter your choice: "

    read opt;

    echo " "

    echo " "



case $opt in





    1)  curl -s sanity_check.sh | bash;;

    2)  exec ./menu/asterisk/menu.sh;;

    3)  exec ./menu/audio/menu.sh;;

    4)  exec ./menu/coco/menu.sh;;

    5)  exec ./menu/database/menu.sh;;

    6)  exec ./menu/mobile/menu.sh;;

    7)  exec ./menu/ssh/menu.sh;;

    8)  exec ./menu/touch/menu.sh;;

    9)  exec ./menu/vds/menu.sh;;

    10)  exec ./menu/wireshark/menu.sh;;





    q)  echo " "

            echo "Bye Bye";

                exit 1;;

    Q)  echo " "

            echo "Bye Bye";

                exit 1;;



    r)  exec ./menu.sh;;

    R)  exec ./menu.sh;;



    *)  echo "$opt is an invaild option.";

            echo "Press [enter] key to continue. . .";

                read enterKey;;

esac

done

it gives me the following errors:

bash: line 3: =====: command not found

bash: line 4: 1.: command not found

bash: line 5: 2.: command not found

bash: line 6: 3.: command not found

bash: line 7: 4.: command not found

bash: line 8: 5.: command not found

bash: line 9: 6.: command not found

bash: line 10: 7.: command not found

bash: line 11: 8.: command not found

bash: line 12: 9.: command not found

bash: line 13: 10.: command not found

bash: line 14: -----------------------: command not found

bash: line 15: q.: command not found

bash: line 16: r.: command not found

bash: line 17: =======================: command not found

but for me these are just the echo commands ..... or am I missing something

When running this code, it will output a text menu. What you are doing with ./menu.sh | bash is that you are feeding the menu into bash for execution. In other words, you say to bash, "please execute this menu". bash does not know what any of the text in the menu means, so it throws errors.

However, this is not how you say you will use this script. You intend to fetch it (the script, not its output) and have it execute:

curl -o- 'ftp://.../menu.sh' | bash

This would not execute the script on the left hand side of the pipeline, while your ./menu.sh | bash does. So what you are proposing would probably work.

Also note that it's a fair bit easier to do multi-line output with a here-document:

cat <<END_MENU

===== MAIN - MENU =====

1. Run old sanity script

2. Asterisk

3. Audio

4. CoCo

5. Database

6. Mobile

7. SSH

8. Touch

9. VDS

10. Wireshark

-----------------------

q. Quit

r. Reload

=======================

END_MENU

Also investigate the select statement in bash. It displays menus for you and makes it easier to do user input (unless you want special formatting of the menu and options, obviously).

You can also do multiple patterns in case statements:

q|Q)  echo 'Bye!'

      exit ;;

or

[qQ]) echo 'Bye!'

      exit ;;

(an exit due to the user's request should probably not return a non-zero exit code, by the way)

You are sending the output of the script to bash. don't you want to send the text of the script to bash to make bash execute it?

cat menu.sh | bash