create menu with x items depending on variable












0














I am trying to get a menu with x lines depending on a variable.



setup:



i have a network with x ip addresses



i want a user to get a menu where he can simply choose an ip address by entering a number:



for instance:



i have 4 ip adresses



ip1=192.168.1.1

ip2=192.168.1.2

ip3=192.168.1.3

ip4=192.168.1.4


i want the user to get a menu like 



1. 192.168.1.1

2. 192.168.1.2

3. 192.168.1.3

4. 192.168.1.4

Please enter your choice:


however, the number of ip addresses can variate.



I am trying to do this in a case:



echo -n "Please enter your choice: "

read opt

case $opt in

    ipnum=ip$opt



    1)  echo ${!ipnum}

esac


but i cant get it into a loop






shell-script







share|improve this question
























  • Any specific reason for using the case compound command? Wouldn't putting the IPs in an array and loop over it to print a menu be enough? E.g. for i in "${!ips[@]}"; do ... print menu item ... ; done; ... prompt ... ; read answer... ; ... use user's choice ...
    – fra-san
    Dec 11 at 11:39










  • I am fairly new to this, so i am still trying to understand all the functions and what to use when. I use case because i got an other menu working with it
    – WingZero
    Dec 11 at 12:01


















0














I am trying to get a menu with x lines depending on a variable.



setup:



i have a network with x ip addresses



i want a user to get a menu where he can simply choose an ip address by entering a number:



for instance:



i have 4 ip adresses



ip1=192.168.1.1

ip2=192.168.1.2

ip3=192.168.1.3

ip4=192.168.1.4


i want the user to get a menu like 



1. 192.168.1.1

2. 192.168.1.2

3. 192.168.1.3

4. 192.168.1.4

Please enter your choice:


however, the number of ip addresses can variate.



I am trying to do this in a case:



echo -n "Please enter your choice: "

read opt

case $opt in

    ipnum=ip$opt



    1)  echo ${!ipnum}

esac


but i cant get it into a loop






shell-script







share|improve this question
























  • Any specific reason for using the case compound command? Wouldn't putting the IPs in an array and loop over it to print a menu be enough? E.g. for i in "${!ips[@]}"; do ... print menu item ... ; done; ... prompt ... ; read answer... ; ... use user's choice ...
    – fra-san
    Dec 11 at 11:39










  • I am fairly new to this, so i am still trying to understand all the functions and what to use when. I use case because i got an other menu working with it
    – WingZero
    Dec 11 at 12:01
















0












0








0







I am trying to get a menu with x lines depending on a variable.



setup:



i have a network with x ip addresses



i want a user to get a menu where he can simply choose an ip address by entering a number:



for instance:



i have 4 ip adresses



ip1=192.168.1.1

ip2=192.168.1.2

ip3=192.168.1.3

ip4=192.168.1.4


i want the user to get a menu like 



1. 192.168.1.1

2. 192.168.1.2

3. 192.168.1.3

4. 192.168.1.4

Please enter your choice:


however, the number of ip addresses can variate.



I am trying to do this in a case:



echo -n "Please enter your choice: "

read opt

case $opt in

    ipnum=ip$opt



    1)  echo ${!ipnum}

esac


but i cant get it into a loop






shell-script







share|improve this question















I am trying to get a menu with x lines depending on a variable.



setup:



i have a network with x ip addresses



i want a user to get a menu where he can simply choose an ip address by entering a number:



for instance:



i have 4 ip adresses



ip1=192.168.1.1

ip2=192.168.1.2

ip3=192.168.1.3

ip4=192.168.1.4


i want the user to get a menu like 



1. 192.168.1.1

2. 192.168.1.2

3. 192.168.1.3

4. 192.168.1.4

Please enter your choice:


however, the number of ip addresses can variate.



I am trying to do this in a case:



echo -n "Please enter your choice: "

read opt

case $opt in

    ipnum=ip$opt



    1)  echo ${!ipnum}

esac


but i cant get it into a loop






shell-script




shell-script






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 11 at 11:13









Ipor Sircer

10.5k11024




10.5k11024










asked Dec 11 at 10:47









WingZero

385




385












  • Any specific reason for using the case compound command? Wouldn't putting the IPs in an array and loop over it to print a menu be enough? E.g. for i in "${!ips[@]}"; do ... print menu item ... ; done; ... prompt ... ; read answer... ; ... use user's choice ...
    – fra-san
    Dec 11 at 11:39










  • I am fairly new to this, so i am still trying to understand all the functions and what to use when. I use case because i got an other menu working with it
    – WingZero
    Dec 11 at 12:01




















  • Any specific reason for using the case compound command? Wouldn't putting the IPs in an array and loop over it to print a menu be enough? E.g. for i in "${!ips[@]}"; do ... print menu item ... ; done; ... prompt ... ; read answer... ; ... use user's choice ...
    – fra-san
    Dec 11 at 11:39










  • I am fairly new to this, so i am still trying to understand all the functions and what to use when. I use case because i got an other menu working with it
    – WingZero
    Dec 11 at 12:01


















Any specific reason for using the case compound command? Wouldn't putting the IPs in an array and loop over it to print a menu be enough? E.g. for i in "${!ips[@]}"; do ... print menu item ... ; done; ... prompt ... ; read answer... ; ... use user's choice ...
– fra-san
Dec 11 at 11:39




Any specific reason for using the case compound command? Wouldn't putting the IPs in an array and loop over it to print a menu be enough? E.g. for i in "${!ips[@]}"; do ... print menu item ... ; done; ... prompt ... ; read answer... ; ... use user's choice ...
– fra-san
Dec 11 at 11:39












I am fairly new to this, so i am still trying to understand all the functions and what to use when. I use case because i got an other menu working with it
– WingZero
Dec 11 at 12:01






I am fairly new to this, so i am still trying to understand all the functions and what to use when. I use case because i got an other menu working with it
– WingZero
Dec 11 at 12:01












2 Answers
2






active

oldest

votes


















1














In case you are using bash (or a similar shell):



ipnums=( 192.168.1.1 192.168.1.2 192.168.1.3 192.168.1.4 )



select ip in "${ipnums[@]}"; do

    case $ip in

        "") echo 'Invalid choice' >&2 ;;

        *)  break

    esac

done



printf 'You picked IP %sn' "$ip"


This would display a menu and a prompt like this:



1) 192.168.1.1

2) 192.168.1.2

3) 192.168.1.3

4) 192.168.1.4

#?


The prompt may be changed by setting PS3 to the prompt string to use.



The select loop verifies the input and loops until a valid input is had from the user.



After the loop, the IP address that was chosen is available in $ip.



If you don't want to store your addresses in an array, you would have to list the relevant variables instead (this would not easily be generalised to N variables, which is why I suggested using an array in my answer to your other question):



select ip in "$ip1" "$ip2" "$ip3" "$ip4"; do ...; done





share|improve this answer































    0














    In my case i figured it out.



    like @fra-san said why use case and not just print it and ask for the users choice.



    i just used an array to echo all ip addressing with an extra number in front, and when they enter the number it correspondences with the number in the variable, so i have my answer .






    share|improve this answer





















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      In case you are using bash (or a similar shell):



      ipnums=( 192.168.1.1 192.168.1.2 192.168.1.3 192.168.1.4 )
      

      
select ip in "${ipnums[@]}"; do
      
    case $ip in
      
        "") echo 'Invalid choice' >&2 ;;
      
        *)  break
      
    esac
      
done
      

      
printf 'You picked IP %sn' "$ip"


      This would display a menu and a prompt like this:



      1) 192.168.1.1
      
2) 192.168.1.2
      
3) 192.168.1.3
      
4) 192.168.1.4
      
#?


      The prompt may be changed by setting PS3 to the prompt string to use.



      The select loop verifies the input and loops until a valid input is had from the user.



      After the loop, the IP address that was chosen is available in $ip.



      If you don't want to store your addresses in an array, you would have to list the relevant variables instead (this would not easily be generalised to N variables, which is why I suggested using an array in my answer to your other question):



      select ip in "$ip1" "$ip2" "$ip3" "$ip4"; do ...; done





      share|improve this answer




























        1














        In case you are using bash (or a similar shell):



        ipnums=( 192.168.1.1 192.168.1.2 192.168.1.3 192.168.1.4 )
        

        
select ip in "${ipnums[@]}"; do
        
    case $ip in
        
        "") echo 'Invalid choice' >&2 ;;
        
        *)  break
        
    esac
        
done
        

        
printf 'You picked IP %sn' "$ip"


        This would display a menu and a prompt like this:



        1) 192.168.1.1
        
2) 192.168.1.2
        
3) 192.168.1.3
        
4) 192.168.1.4
        
#?


        The prompt may be changed by setting PS3 to the prompt string to use.



        The select loop verifies the input and loops until a valid input is had from the user.



        After the loop, the IP address that was chosen is available in $ip.



        If you don't want to store your addresses in an array, you would have to list the relevant variables instead (this would not easily be generalised to N variables, which is why I suggested using an array in my answer to your other question):



        select ip in "$ip1" "$ip2" "$ip3" "$ip4"; do ...; done





        share|improve this answer


























          1












          1








          1






          In case you are using bash (or a similar shell):



          ipnums=( 192.168.1.1 192.168.1.2 192.168.1.3 192.168.1.4 )
          

          
select ip in "${ipnums[@]}"; do
          
    case $ip in
          
        "") echo 'Invalid choice' >&2 ;;
          
        *)  break
          
    esac
          
done
          

          
printf 'You picked IP %sn' "$ip"


          This would display a menu and a prompt like this:



          1) 192.168.1.1
          
2) 192.168.1.2
          
3) 192.168.1.3
          
4) 192.168.1.4
          
#?


          The prompt may be changed by setting PS3 to the prompt string to use.



          The select loop verifies the input and loops until a valid input is had from the user.



          After the loop, the IP address that was chosen is available in $ip.



          If you don't want to store your addresses in an array, you would have to list the relevant variables instead (this would not easily be generalised to N variables, which is why I suggested using an array in my answer to your other question):



          select ip in "$ip1" "$ip2" "$ip3" "$ip4"; do ...; done





          share|improve this answer














          In case you are using bash (or a similar shell):



          ipnums=( 192.168.1.1 192.168.1.2 192.168.1.3 192.168.1.4 )
          

          
select ip in "${ipnums[@]}"; do
          
    case $ip in
          
        "") echo 'Invalid choice' >&2 ;;
          
        *)  break
          
    esac
          
done
          

          
printf 'You picked IP %sn' "$ip"


          This would display a menu and a prompt like this:



          1) 192.168.1.1
          
2) 192.168.1.2
          
3) 192.168.1.3
          
4) 192.168.1.4
          
#?


          The prompt may be changed by setting PS3 to the prompt string to use.



          The select loop verifies the input and loops until a valid input is had from the user.



          After the loop, the IP address that was chosen is available in $ip.



          If you don't want to store your addresses in an array, you would have to list the relevant variables instead (this would not easily be generalised to N variables, which is why I suggested using an array in my answer to your other question):



          select ip in "$ip1" "$ip2" "$ip3" "$ip4"; do ...; done






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Dec 11 at 13:09

























          answered Dec 11 at 12:55









          Kusalananda

          121k16228372




          121k16228372

























              0














              In my case i figured it out.



              like @fra-san said why use case and not just print it and ask for the users choice.



              i just used an array to echo all ip addressing with an extra number in front, and when they enter the number it correspondences with the number in the variable, so i have my answer .






              share|improve this answer


























                0














                In my case i figured it out.



                like @fra-san said why use case and not just print it and ask for the users choice.



                i just used an array to echo all ip addressing with an extra number in front, and when they enter the number it correspondences with the number in the variable, so i have my answer .






                share|improve this answer
























                  0












                  0








                  0






                  In my case i figured it out.



                  like @fra-san said why use case and not just print it and ask for the users choice.



                  i just used an array to echo all ip addressing with an extra number in front, and when they enter the number it correspondences with the number in the variable, so i have my answer .






                  share|improve this answer












                  In my case i figured it out.



                  like @fra-san said why use case and not just print it and ask for the users choice.



                  i just used an array to echo all ip addressing with an extra number in front, and when they enter the number it correspondences with the number in the variable, so i have my answer .







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Dec 11 at 12:10









                  WingZero

                  385




                  385






























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