How to join a line with a pattern with the next line with sed?
I can't find this case in the board, so I'm asking the question.
This is input file:
module
x(a,b,c)
module
y(d,e,f,
g,h,i)
module
z(j,k,l)
And output file should be:
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
text-processing sed join
edited Dec 17 at 6:34
αғsнιη
16.5k102865
asked Dec 17 at 6:24
funfun
112
add a comment |
I can't find this case in the board, so I'm asking the question.
This is input file:
module
x(a,b,c)
module
y(d,e,f,
g,h,i)
module
z(j,k,l)
And output file should be:
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
text-processing sed join
edited Dec 17 at 6:34
αғsнιη
16.5k102865
asked Dec 17 at 6:24
funfun
112
add a comment |
I can't find this case in the board, so I'm asking the question.
This is input file:
module
x(a,b,c)
module
y(d,e,f,
g,h,i)
module
z(j,k,l)
And output file should be:
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
text-processing sed join
edited Dec 17 at 6:34
αғsнιη
16.5k102865
asked Dec 17 at 6:24
funfun
112
I can't find this case in the board, so I'm asking the question.
This is input file:
module
x(a,b,c)
module
y(d,e,f,
g,h,i)
module
z(j,k,l)
And output file should be:
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
text-processing sed join
text-processing sed join
edited Dec 17 at 6:34
αғsнιη
16.5k102865
asked Dec 17 at 6:24
funfun
112
edited Dec 17 at 6:34
αғsнιη
16.5k102865
asked Dec 17 at 6:24
funfun
112
edited Dec 17 at 6:34
αғsнιη
16.5k102865
edited Dec 17 at 6:34
αғsнιη
16.5k102865
edited Dec 17 at 6:34
αғsнιη
16.5k102865
16.5k102865
asked Dec 17 at 6:24
funfun
112
asked Dec 17 at 6:24
funfun
112
asked Dec 17 at 6:24
funfun
112
112
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
What you want to do is to join the module lines with the next line.
Using sed:
$ sed '/^module/N;s/n//' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
This is with your data copied and pasted as is, with spaces at the end of each line.
The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.
If your data has no spaces at the end of the lines, use
$ sed '/^module/N;s/n/ /' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
Just in case you'd want this (assuming no spaces at end of input lines):
$ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd'
-e ':pp' -e 'x;/^$/d;s/n/ /g' file
module x(a,b,c)
module y(d,e,f, g,h,i)
module z(j,k,l)
Annotated sed script:
/^module/ b print_previous; # print previous record
H; # append this line to hold space
$ b print_previous; # print previous (last) record
d; # end processing this line
:print_previous; # prints a record accumulated in the hold space
x; # swap in the hold space
/^$/ d; # if line is empty, delete it
s/n/ /g; # replace embedded newlines by spaces
# (implicit print)
answered Dec 17 at 6:52
Kusalananda
121k16229372
add a comment |
Using awk:
~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.
answered Dec 17 at 6:52
muru
1
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
What you want to do is to join the module lines with the next line.
Using sed:
$ sed '/^module/N;s/n//' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
This is with your data copied and pasted as is, with spaces at the end of each line.
The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.
If your data has no spaces at the end of the lines, use
$ sed '/^module/N;s/n/ /' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
Just in case you'd want this (assuming no spaces at end of input lines):
$ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd'
-e ':pp' -e 'x;/^$/d;s/n/ /g' file
module x(a,b,c)
module y(d,e,f, g,h,i)
module z(j,k,l)
Annotated sed script:
/^module/ b print_previous; # print previous record
H; # append this line to hold space
$ b print_previous; # print previous (last) record
d; # end processing this line
:print_previous; # prints a record accumulated in the hold space
x; # swap in the hold space
/^$/ d; # if line is empty, delete it
s/n/ /g; # replace embedded newlines by spaces
# (implicit print)
answered Dec 17 at 6:52
Kusalananda
121k16229372
add a comment |
What you want to do is to join the module lines with the next line.
Using sed:
$ sed '/^module/N;s/n//' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
This is with your data copied and pasted as is, with spaces at the end of each line.
The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.
If your data has no spaces at the end of the lines, use
$ sed '/^module/N;s/n/ /' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
Just in case you'd want this (assuming no spaces at end of input lines):
$ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd'
-e ':pp' -e 'x;/^$/d;s/n/ /g' file
module x(a,b,c)
module y(d,e,f, g,h,i)
module z(j,k,l)
Annotated sed script:
/^module/ b print_previous; # print previous record
H; # append this line to hold space
$ b print_previous; # print previous (last) record
d; # end processing this line
:print_previous; # prints a record accumulated in the hold space
x; # swap in the hold space
/^$/ d; # if line is empty, delete it
s/n/ /g; # replace embedded newlines by spaces
# (implicit print)
answered Dec 17 at 6:52
Kusalananda
121k16229372
add a comment |
What you want to do is to join the module lines with the next line.
Using sed:
$ sed '/^module/N;s/n//' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
This is with your data copied and pasted as is, with spaces at the end of each line.
The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.
If your data has no spaces at the end of the lines, use
$ sed '/^module/N;s/n/ /' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
Just in case you'd want this (assuming no spaces at end of input lines):
$ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd'
-e ':pp' -e 'x;/^$/d;s/n/ /g' file
module x(a,b,c)
module y(d,e,f, g,h,i)
module z(j,k,l)
Annotated sed script:
/^module/ b print_previous; # print previous record
H; # append this line to hold space
$ b print_previous; # print previous (last) record
d; # end processing this line
:print_previous; # prints a record accumulated in the hold space
x; # swap in the hold space
/^$/ d; # if line is empty, delete it
s/n/ /g; # replace embedded newlines by spaces
# (implicit print)
answered Dec 17 at 6:52
Kusalananda
121k16229372
What you want to do is to join the module lines with the next line.
Using sed:
$ sed '/^module/N;s/n//' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
This is with your data copied and pasted as is, with spaces at the end of each line.
The sed command will print each line as it is read, but when it encounters a line that starts with the string module, it appends the next line with an embedded newline character in-between (this is what N does). We remove that newline character with a substitution before the result is printed.
If your data has no spaces at the end of the lines, use
$ sed '/^module/N;s/n/ /' file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
Just in case you'd want this (assuming no spaces at end of input lines):
$ sed -e '/^module/bpp' -e 'H;$bpp' -e 'd'
-e ':pp' -e 'x;/^$/d;s/n/ /g' file
module x(a,b,c)
module y(d,e,f, g,h,i)
module z(j,k,l)
Annotated sed script:
/^module/ b print_previous; # print previous record
H; # append this line to hold space
$ b print_previous; # print previous (last) record
d; # end processing this line
:print_previous; # prints a record accumulated in the hold space
x; # swap in the hold space
/^$/ d; # if line is empty, delete it
s/n/ /g; # replace embedded newlines by spaces
# (implicit print)
answered Dec 17 at 6:52
Kusalananda
121k16229372
edited Dec 17 at 10:46
answered Dec 17 at 6:52
Kusalananda
121k16229372
answered Dec 17 at 6:52
Kusalananda
121k16229372
answered Dec 17 at 6:52
Kusalananda
121k16229372
121k16229372
add a comment |
add a comment |
Using awk:
~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.
answered Dec 17 at 6:52
muru
1
add a comment |
Using awk:
~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.
answered Dec 17 at 6:52
muru
1
add a comment |
Using awk:
~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.
answered Dec 17 at 6:52
muru
1
Using awk:
~ awk '/^module/ {l = $0; getline; printf "%s", l} 1' input-file
module x(a,b,c)
module y(d,e,f,
g,h,i)
module z(j,k,l)
For each line that starts with module, save the line in l, move to the next line (getline), and print the saved line without a newline. Then print every line.
answered Dec 17 at 6:52
muru
1
answered Dec 17 at 6:52
muru
1
answered Dec 17 at 6:52
muru
1
answered Dec 17 at 6:52
muru
1
1
add a comment |
add a comment |
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