How to extract word which has only numbers separated by 'dot'
up vote
0
down vote
favorite
From below lines
abcd efgh ijhk lmn opqrs 9.0.8.2c tuv wxyz
abcd efgh ijhk lmn opqrs 8.1.3.9b
How to extract only
9.0.8.2c
8.1.3.9b
linux text-processing pattern-matching
edited Dec 6 at 11:18
Isaac
11k11648
asked Dec 6 at 8:53
GSG
1
add a comment |
up vote
0
down vote
favorite
From below lines
abcd efgh ijhk lmn opqrs 9.0.8.2c tuv wxyz
abcd efgh ijhk lmn opqrs 8.1.3.9b
How to extract only
9.0.8.2c
8.1.3.9b
linux text-processing pattern-matching
edited Dec 6 at 11:18
Isaac
11k11648
asked Dec 6 at 8:53
GSG
1
It would be more helpful if your sample had more examples of things you don't want it to match (like what aboutfoo1.2,foo-1.2,1.2-3). How do you define word? How do you define number?9cbeing a number implies numbers here are hexadecimal numbers. Is that right?
– Stéphane Chazelas
Dec 6 at 9:10
Why isn'tabcdto be matched? That's an hexadecimal number as well. Is that because you need those words to contain at least two numbers?
– Stéphane Chazelas
Dec 6 at 9:44
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
From below lines
abcd efgh ijhk lmn opqrs 9.0.8.2c tuv wxyz
abcd efgh ijhk lmn opqrs 8.1.3.9b
How to extract only
9.0.8.2c
8.1.3.9b
linux text-processing pattern-matching
edited Dec 6 at 11:18
Isaac
11k11648
asked Dec 6 at 8:53
GSG
1
From below lines
abcd efgh ijhk lmn opqrs 9.0.8.2c tuv wxyz
abcd efgh ijhk lmn opqrs 8.1.3.9b
How to extract only
9.0.8.2c
8.1.3.9b
linux text-processing pattern-matching
linux text-processing pattern-matching
edited Dec 6 at 11:18
Isaac
11k11648
asked Dec 6 at 8:53
GSG
1
edited Dec 6 at 11:18
Isaac
11k11648
asked Dec 6 at 8:53
GSG
1
edited Dec 6 at 11:18
Isaac
11k11648
edited Dec 6 at 11:18
Isaac
11k11648
edited Dec 6 at 11:18
Isaac
11k11648
11k11648
asked Dec 6 at 8:53
GSG
1
asked Dec 6 at 8:53
GSG
1
asked Dec 6 at 8:53
GSG
1
1
It would be more helpful if your sample had more examples of things you don't want it to match (like what aboutfoo1.2,foo-1.2,1.2-3). How do you define word? How do you define number?9cbeing a number implies numbers here are hexadecimal numbers. Is that right?
– Stéphane Chazelas
Dec 6 at 9:10
Why isn'tabcdto be matched? That's an hexadecimal number as well. Is that because you need those words to contain at least two numbers?
– Stéphane Chazelas
Dec 6 at 9:44
add a comment |
It would be more helpful if your sample had more examples of things you don't want it to match (like what aboutfoo1.2,foo-1.2,1.2-3). How do you define word? How do you define number?9cbeing a number implies numbers here are hexadecimal numbers. Is that right?
– Stéphane Chazelas
Dec 6 at 9:10
Why isn'tabcdto be matched? That's an hexadecimal number as well. Is that because you need those words to contain at least two numbers?
– Stéphane Chazelas
Dec 6 at 9:44
It would be more helpful if your sample had more examples of things you don't want it to match (like what about
foo1.2, foo-1.2, 1.2-3). How do you define word? How do you define number? 9c being a number implies numbers here are hexadecimal numbers. Is that right?– Stéphane Chazelas
Dec 6 at 9:10
It would be more helpful if your sample had more examples of things you don't want it to match (like what about
foo1.2, foo-1.2, 1.2-3). How do you define word? How do you define number? 9c being a number implies numbers here are hexadecimal numbers. Is that right?– Stéphane Chazelas
Dec 6 at 9:10
Why isn't
abcd to be matched? That's an hexadecimal number as well. Is that because you need those words to contain at least two numbers?– Stéphane Chazelas
Dec 6 at 9:44
Why isn't
abcd to be matched? That's an hexadecimal number as well. Is that because you need those words to contain at least two numbers?– Stéphane Chazelas
Dec 6 at 9:44
add a comment |
4 Answers
4
active
oldest
votes
up vote
0
down vote
Try this,
grep -E -o '[0-9].[0-9].[0-9].[0-9][^[:space:]]+' file
-EInterpret PATTERN as an extended regular expression
-oPrint only the matched parts of a matching line
[^[:space:]]+until white space
answered Dec 6 at 8:58
msp9011
3,65543863
@StéphaneChazelas Thanks, updated fordot, ...
– msp9011
Dec 6 at 9:11
@StéphaneChazelas i mentw+as untile white space, sincewfollowed by+.... correct me if im wrong...
– msp9011
Dec 6 at 9:13
@StéphaneChazelas much thanks...
– msp9011
Dec 6 at 9:39
add a comment |
up vote
0
down vote
If by word, you mean sequence of non-whitespace characters, and by number, you mean hexadecimal (without sign or leading 0x, so sequence of 0123456789abcdefABCDEF characters), and that you need at least two of those numbers per word (otherwise abcd would be matched as well), with GNU grep you can do:
grep -Pio '(?<!S)[0-9a-f]+(.[0-9a-f]+)+(?!S)'
Or with perl:
perl -lne 'for (/S+/g) {print if /^[da-f]+(.[da-f]+)+$/}'
answered Dec 6 at 9:49
Stéphane Chazelas
298k54562909
add a comment |
up vote
0
down vote
Assuming the values are inside a file, with pcre grep:
$ grep -P '(([0-9a-f]+).)(?1)+(?2)' file
9.0.8.2c
8.1.3.9b
Or with perl:
perl -lne '/((([da-f]+).)(?2)+(?3))/;print $1' file
answered Dec 6 at 11:44
Isaac
11k11648
add a comment |
up vote
0
down vote
Try also
grep -oE "(w*[.]w*)*" file
9.0.8.2c
8.1.3.9b
answered Dec 6 at 12:28
RudiC
3,9541312
Perhaps end with+instead of*, to avoid matching the empty string? The output will be the same, but the*form will report "success" even on files containing no such words.
– JigglyNaga
Dec 6 at 13:48
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Try this,
grep -E -o '[0-9].[0-9].[0-9].[0-9][^[:space:]]+' file
-EInterpret PATTERN as an extended regular expression
-oPrint only the matched parts of a matching line
[^[:space:]]+until white space
answered Dec 6 at 8:58
msp9011
3,65543863
@StéphaneChazelas Thanks, updated fordot, ...
– msp9011
Dec 6 at 9:11
@StéphaneChazelas i mentw+as untile white space, sincewfollowed by+.... correct me if im wrong...
– msp9011
Dec 6 at 9:13
@StéphaneChazelas much thanks...
– msp9011
Dec 6 at 9:39
add a comment |
up vote
0
down vote
Try this,
grep -E -o '[0-9].[0-9].[0-9].[0-9][^[:space:]]+' file
-EInterpret PATTERN as an extended regular expression
-oPrint only the matched parts of a matching line
[^[:space:]]+until white space
answered Dec 6 at 8:58
msp9011
3,65543863
@StéphaneChazelas Thanks, updated fordot, ...
– msp9011
Dec 6 at 9:11
@StéphaneChazelas i mentw+as untile white space, sincewfollowed by+.... correct me if im wrong...
– msp9011
Dec 6 at 9:13
@StéphaneChazelas much thanks...
– msp9011
Dec 6 at 9:39
add a comment |
up vote
0
down vote
up vote
0
down vote
Try this,
grep -E -o '[0-9].[0-9].[0-9].[0-9][^[:space:]]+' file
-EInterpret PATTERN as an extended regular expression
-oPrint only the matched parts of a matching line
[^[:space:]]+until white space
answered Dec 6 at 8:58
msp9011
3,65543863
Try this,
grep -E -o '[0-9].[0-9].[0-9].[0-9][^[:space:]]+' file
-EInterpret PATTERN as an extended regular expression
-oPrint only the matched parts of a matching line
[^[:space:]]+until white space
answered Dec 6 at 8:58
msp9011
3,65543863
edited Dec 6 at 9:38
answered Dec 6 at 8:58
msp9011
3,65543863
answered Dec 6 at 8:58
msp9011
3,65543863
answered Dec 6 at 8:58
msp9011
3,65543863
3,65543863
@StéphaneChazelas Thanks, updated fordot, ...
– msp9011
Dec 6 at 9:11
@StéphaneChazelas i mentw+as untile white space, sincewfollowed by+.... correct me if im wrong...
– msp9011
Dec 6 at 9:13
@StéphaneChazelas much thanks...
– msp9011
Dec 6 at 9:39
add a comment |
@StéphaneChazelas Thanks, updated fordot, ...
– msp9011
Dec 6 at 9:11
@StéphaneChazelas i mentw+as untile white space, sincewfollowed by+.... correct me if im wrong...
– msp9011
Dec 6 at 9:13
@StéphaneChazelas much thanks...
– msp9011
Dec 6 at 9:39
@StéphaneChazelas Thanks, updated for
dot, ...– msp9011
Dec 6 at 9:11
@StéphaneChazelas Thanks, updated for
dot, ...– msp9011
Dec 6 at 9:11
@StéphaneChazelas i ment
w+ as untile white space, since w followed by +.... correct me if im wrong...– msp9011
Dec 6 at 9:13
@StéphaneChazelas i ment
w+ as untile white space, since w followed by +.... correct me if im wrong...– msp9011
Dec 6 at 9:13
@StéphaneChazelas much thanks...
– msp9011
Dec 6 at 9:39
@StéphaneChazelas much thanks...
– msp9011
Dec 6 at 9:39
add a comment |
up vote
0
down vote
If by word, you mean sequence of non-whitespace characters, and by number, you mean hexadecimal (without sign or leading 0x, so sequence of 0123456789abcdefABCDEF characters), and that you need at least two of those numbers per word (otherwise abcd would be matched as well), with GNU grep you can do:
grep -Pio '(?<!S)[0-9a-f]+(.[0-9a-f]+)+(?!S)'
Or with perl:
perl -lne 'for (/S+/g) {print if /^[da-f]+(.[da-f]+)+$/}'
answered Dec 6 at 9:49
Stéphane Chazelas
298k54562909
add a comment |
up vote
0
down vote
If by word, you mean sequence of non-whitespace characters, and by number, you mean hexadecimal (without sign or leading 0x, so sequence of 0123456789abcdefABCDEF characters), and that you need at least two of those numbers per word (otherwise abcd would be matched as well), with GNU grep you can do:
grep -Pio '(?<!S)[0-9a-f]+(.[0-9a-f]+)+(?!S)'
Or with perl:
perl -lne 'for (/S+/g) {print if /^[da-f]+(.[da-f]+)+$/}'
answered Dec 6 at 9:49
Stéphane Chazelas
298k54562909
add a comment |
up vote
0
down vote
up vote
0
down vote
If by word, you mean sequence of non-whitespace characters, and by number, you mean hexadecimal (without sign or leading 0x, so sequence of 0123456789abcdefABCDEF characters), and that you need at least two of those numbers per word (otherwise abcd would be matched as well), with GNU grep you can do:
grep -Pio '(?<!S)[0-9a-f]+(.[0-9a-f]+)+(?!S)'
Or with perl:
perl -lne 'for (/S+/g) {print if /^[da-f]+(.[da-f]+)+$/}'
answered Dec 6 at 9:49
Stéphane Chazelas
298k54562909
If by word, you mean sequence of non-whitespace characters, and by number, you mean hexadecimal (without sign or leading 0x, so sequence of 0123456789abcdefABCDEF characters), and that you need at least two of those numbers per word (otherwise abcd would be matched as well), with GNU grep you can do:
grep -Pio '(?<!S)[0-9a-f]+(.[0-9a-f]+)+(?!S)'
Or with perl:
perl -lne 'for (/S+/g) {print if /^[da-f]+(.[da-f]+)+$/}'
answered Dec 6 at 9:49
Stéphane Chazelas
298k54562909
answered Dec 6 at 9:49
Stéphane Chazelas
298k54562909
answered Dec 6 at 9:49
Stéphane Chazelas
298k54562909
answered Dec 6 at 9:49
Stéphane Chazelas
298k54562909
298k54562909
add a comment |
add a comment |
up vote
0
down vote
Assuming the values are inside a file, with pcre grep:
$ grep -P '(([0-9a-f]+).)(?1)+(?2)' file
9.0.8.2c
8.1.3.9b
Or with perl:
perl -lne '/((([da-f]+).)(?2)+(?3))/;print $1' file
answered Dec 6 at 11:44
Isaac
11k11648
add a comment |
up vote
0
down vote
Assuming the values are inside a file, with pcre grep:
$ grep -P '(([0-9a-f]+).)(?1)+(?2)' file
9.0.8.2c
8.1.3.9b
Or with perl:
perl -lne '/((([da-f]+).)(?2)+(?3))/;print $1' file
answered Dec 6 at 11:44
Isaac
11k11648
add a comment |
up vote
0
down vote
up vote
0
down vote
Assuming the values are inside a file, with pcre grep:
$ grep -P '(([0-9a-f]+).)(?1)+(?2)' file
9.0.8.2c
8.1.3.9b
Or with perl:
perl -lne '/((([da-f]+).)(?2)+(?3))/;print $1' file
answered Dec 6 at 11:44
Isaac
11k11648
Assuming the values are inside a file, with pcre grep:
$ grep -P '(([0-9a-f]+).)(?1)+(?2)' file
9.0.8.2c
8.1.3.9b
Or with perl:
perl -lne '/((([da-f]+).)(?2)+(?3))/;print $1' file
answered Dec 6 at 11:44
Isaac
11k11648
answered Dec 6 at 11:44
Isaac
11k11648
answered Dec 6 at 11:44
Isaac
11k11648
answered Dec 6 at 11:44
Isaac
11k11648
11k11648
add a comment |
add a comment |
up vote
0
down vote
Try also
grep -oE "(w*[.]w*)*" file
9.0.8.2c
8.1.3.9b
answered Dec 6 at 12:28
RudiC
3,9541312
Perhaps end with+instead of*, to avoid matching the empty string? The output will be the same, but the*form will report "success" even on files containing no such words.
– JigglyNaga
Dec 6 at 13:48
add a comment |
up vote
0
down vote
Try also
grep -oE "(w*[.]w*)*" file
9.0.8.2c
8.1.3.9b
answered Dec 6 at 12:28
RudiC
3,9541312
Perhaps end with+instead of*, to avoid matching the empty string? The output will be the same, but the*form will report "success" even on files containing no such words.
– JigglyNaga
Dec 6 at 13:48
add a comment |
up vote
0
down vote
up vote
0
down vote
Try also
grep -oE "(w*[.]w*)*" file
9.0.8.2c
8.1.3.9b
answered Dec 6 at 12:28
RudiC
3,9541312
Try also
grep -oE "(w*[.]w*)*" file
9.0.8.2c
8.1.3.9b
answered Dec 6 at 12:28
RudiC
3,9541312
answered Dec 6 at 12:28
RudiC
3,9541312
answered Dec 6 at 12:28
RudiC
3,9541312
answered Dec 6 at 12:28
RudiC
3,9541312
3,9541312
Perhaps end with+instead of*, to avoid matching the empty string? The output will be the same, but the*form will report "success" even on files containing no such words.
– JigglyNaga
Dec 6 at 13:48
add a comment |
Perhaps end with+instead of*, to avoid matching the empty string? The output will be the same, but the*form will report "success" even on files containing no such words.
– JigglyNaga
Dec 6 at 13:48
Perhaps end with
+ instead of *, to avoid matching the empty string? The output will be the same, but the * form will report "success" even on files containing no such words.– JigglyNaga
Dec 6 at 13:48
Perhaps end with
+ instead of *, to avoid matching the empty string? The output will be the same, but the * form will report "success" even on files containing no such words.– JigglyNaga
Dec 6 at 13:48
add a comment |
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It would be more helpful if your sample had more examples of things you don't want it to match (like what about
foo1.2,foo-1.2,1.2-3). How do you define word? How do you define number?9cbeing a number implies numbers here are hexadecimal numbers. Is that right?– Stéphane Chazelas
Dec 6 at 9:10
Why isn't
abcdto be matched? That's an hexadecimal number as well. Is that because you need those words to contain at least two numbers?– Stéphane Chazelas
Dec 6 at 9:44