Nested double quotes for wrapping variables
There is one line in my bash script file like this:
echo "$string" | sed -e "s|($str)|$(wrap \1 $1 $2)|"
Now, I want to wrap the $1
and $2
with double quotes for preventing errors while $1
equals to null
.
I tried to add before
"
, like ""$1" "$2""
but it does not work.
How can I do that?
bash shell
add a comment |
There is one line in my bash script file like this:
echo "$string" | sed -e "s|($str)|$(wrap \1 $1 $2)|"
Now, I want to wrap the $1
and $2
with double quotes for preventing errors while $1
equals to null
.
I tried to add before
"
, like ""$1" "$2""
but it does not work.
How can I do that?
bash shell
4
Using shell variables and command substitutions to generate ased
script is terribly fragile. Could you explain what$string
and$str
are and what you want to achieve. Are you generating commands that you later execute?
– Kusalananda
Dec 12 at 10:24
1
and as always, when writing "but it does not work", please show the exact command(s) you've entered, the result, any error messages you get, and what you expected to get instead.
– ilkkachu
Dec 12 at 10:46
Do you expectwrap
to be invoked for every line with the captured string as argument or do you expectwrap
to be given a literal1
as argument and its output to be used to generate the content of thesed
inline script?
– Stéphane Chazelas
Dec 12 at 13:19
add a comment |
There is one line in my bash script file like this:
echo "$string" | sed -e "s|($str)|$(wrap \1 $1 $2)|"
Now, I want to wrap the $1
and $2
with double quotes for preventing errors while $1
equals to null
.
I tried to add before
"
, like ""$1" "$2""
but it does not work.
How can I do that?
bash shell
There is one line in my bash script file like this:
echo "$string" | sed -e "s|($str)|$(wrap \1 $1 $2)|"
Now, I want to wrap the $1
and $2
with double quotes for preventing errors while $1
equals to null
.
I tried to add before
"
, like ""$1" "$2""
but it does not work.
How can I do that?
bash shell
bash shell
asked Dec 12 at 10:20
LCB
1012
1012
4
Using shell variables and command substitutions to generate ased
script is terribly fragile. Could you explain what$string
and$str
are and what you want to achieve. Are you generating commands that you later execute?
– Kusalananda
Dec 12 at 10:24
1
and as always, when writing "but it does not work", please show the exact command(s) you've entered, the result, any error messages you get, and what you expected to get instead.
– ilkkachu
Dec 12 at 10:46
Do you expectwrap
to be invoked for every line with the captured string as argument or do you expectwrap
to be given a literal1
as argument and its output to be used to generate the content of thesed
inline script?
– Stéphane Chazelas
Dec 12 at 13:19
add a comment |
4
Using shell variables and command substitutions to generate ased
script is terribly fragile. Could you explain what$string
and$str
are and what you want to achieve. Are you generating commands that you later execute?
– Kusalananda
Dec 12 at 10:24
1
and as always, when writing "but it does not work", please show the exact command(s) you've entered, the result, any error messages you get, and what you expected to get instead.
– ilkkachu
Dec 12 at 10:46
Do you expectwrap
to be invoked for every line with the captured string as argument or do you expectwrap
to be given a literal1
as argument and its output to be used to generate the content of thesed
inline script?
– Stéphane Chazelas
Dec 12 at 13:19
4
4
Using shell variables and command substitutions to generate a
sed
script is terribly fragile. Could you explain what $string
and $str
are and what you want to achieve. Are you generating commands that you later execute?– Kusalananda
Dec 12 at 10:24
Using shell variables and command substitutions to generate a
sed
script is terribly fragile. Could you explain what $string
and $str
are and what you want to achieve. Are you generating commands that you later execute?– Kusalananda
Dec 12 at 10:24
1
1
and as always, when writing "but it does not work", please show the exact command(s) you've entered, the result, any error messages you get, and what you expected to get instead.
– ilkkachu
Dec 12 at 10:46
and as always, when writing "but it does not work", please show the exact command(s) you've entered, the result, any error messages you get, and what you expected to get instead.
– ilkkachu
Dec 12 at 10:46
Do you expect
wrap
to be invoked for every line with the captured string as argument or do you expect wrap
to be given a literal 1
as argument and its output to be used to generate the content of the sed
inline script?– Stéphane Chazelas
Dec 12 at 13:19
Do you expect
wrap
to be invoked for every line with the captured string as argument or do you expect wrap
to be given a literal 1
as argument and its output to be used to generate the content of the sed
inline script?– Stéphane Chazelas
Dec 12 at 13:19
add a comment |
1 Answer
1
active
oldest
votes
I got the answer finally. I misunderstood the effect of double quotes. Actually, I only need to surround the characters that I need. So, I change the code like this:
echo "$string" | sed -e "s|($str)|"$(wrap \1 "$1" "$2")"|g"
Yes. You are in a subshell inside the parentheses, so quotes in there are not affected by "outer" quotes.
– glenn jackman
Dec 12 at 16:04
add a comment |
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I got the answer finally. I misunderstood the effect of double quotes. Actually, I only need to surround the characters that I need. So, I change the code like this:
echo "$string" | sed -e "s|($str)|"$(wrap \1 "$1" "$2")"|g"
Yes. You are in a subshell inside the parentheses, so quotes in there are not affected by "outer" quotes.
– glenn jackman
Dec 12 at 16:04
add a comment |
I got the answer finally. I misunderstood the effect of double quotes. Actually, I only need to surround the characters that I need. So, I change the code like this:
echo "$string" | sed -e "s|($str)|"$(wrap \1 "$1" "$2")"|g"
Yes. You are in a subshell inside the parentheses, so quotes in there are not affected by "outer" quotes.
– glenn jackman
Dec 12 at 16:04
add a comment |
I got the answer finally. I misunderstood the effect of double quotes. Actually, I only need to surround the characters that I need. So, I change the code like this:
echo "$string" | sed -e "s|($str)|"$(wrap \1 "$1" "$2")"|g"
I got the answer finally. I misunderstood the effect of double quotes. Actually, I only need to surround the characters that I need. So, I change the code like this:
echo "$string" | sed -e "s|($str)|"$(wrap \1 "$1" "$2")"|g"
answered Dec 12 at 13:13
LCB
1012
1012
Yes. You are in a subshell inside the parentheses, so quotes in there are not affected by "outer" quotes.
– glenn jackman
Dec 12 at 16:04
add a comment |
Yes. You are in a subshell inside the parentheses, so quotes in there are not affected by "outer" quotes.
– glenn jackman
Dec 12 at 16:04
Yes. You are in a subshell inside the parentheses, so quotes in there are not affected by "outer" quotes.
– glenn jackman
Dec 12 at 16:04
Yes. You are in a subshell inside the parentheses, so quotes in there are not affected by "outer" quotes.
– glenn jackman
Dec 12 at 16:04
add a comment |
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4
Using shell variables and command substitutions to generate a
sed
script is terribly fragile. Could you explain what$string
and$str
are and what you want to achieve. Are you generating commands that you later execute?– Kusalananda
Dec 12 at 10:24
1
and as always, when writing "but it does not work", please show the exact command(s) you've entered, the result, any error messages you get, and what you expected to get instead.
– ilkkachu
Dec 12 at 10:46
Do you expect
wrap
to be invoked for every line with the captured string as argument or do you expectwrap
to be given a literal1
as argument and its output to be used to generate the content of thesed
inline script?– Stéphane Chazelas
Dec 12 at 13:19