Converting input containing special character to float
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4
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This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.
I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.
def toNum(interest):
if '/' not in interest:
if float(interest) > 1:
return float(interest)/100
else:
return float(interest)
else:
l=
n = 0
count = 1
list_interest=
for e in interest:
list_interest.append(e)
for e in list_interest:
if count == 1 or count == 3:
l.append(e)
count = count +1
continue
if e == '/':
n = n + 1
count = count +1
else:
l[n] = l[n] + e
return int(l[0]) / int(l[1])
interest = input("Interest rate: ")
interest = toNum(interest)
print(interest)
python python-3.x
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ikadorus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
up vote
4
down vote
favorite
This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.
I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.
def toNum(interest):
if '/' not in interest:
if float(interest) > 1:
return float(interest)/100
else:
return float(interest)
else:
l=
n = 0
count = 1
list_interest=
for e in interest:
list_interest.append(e)
for e in list_interest:
if count == 1 or count == 3:
l.append(e)
count = count +1
continue
if e == '/':
n = n + 1
count = count +1
else:
l[n] = l[n] + e
return int(l[0]) / int(l[1])
interest = input("Interest rate: ")
interest = toNum(interest)
print(interest)
python python-3.x
New contributor
ikadorus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
4
down vote
favorite
up vote
4
down vote
favorite
This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.
I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.
def toNum(interest):
if '/' not in interest:
if float(interest) > 1:
return float(interest)/100
else:
return float(interest)
else:
l=
n = 0
count = 1
list_interest=
for e in interest:
list_interest.append(e)
for e in list_interest:
if count == 1 or count == 3:
l.append(e)
count = count +1
continue
if e == '/':
n = n + 1
count = count +1
else:
l[n] = l[n] + e
return int(l[0]) / int(l[1])
interest = input("Interest rate: ")
interest = toNum(interest)
print(interest)
python python-3.x
New contributor
ikadorus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.
I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.
def toNum(interest):
if '/' not in interest:
if float(interest) > 1:
return float(interest)/100
else:
return float(interest)
else:
l=
n = 0
count = 1
list_interest=
for e in interest:
list_interest.append(e)
for e in list_interest:
if count == 1 or count == 3:
l.append(e)
count = count +1
continue
if e == '/':
n = n + 1
count = count +1
else:
l[n] = l[n] + e
return int(l[0]) / int(l[1])
interest = input("Interest rate: ")
interest = toNum(interest)
print(interest)
python python-3.x
python python-3.x
New contributor
ikadorus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ikadorus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ikadorus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
ikadorus
233
233
New contributor
ikadorus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ikadorus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
ikadorus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
3
down vote
accepted
For reading a fraction such as "97/100", you can use the fractions library.
For example:
from fractions import Fraction
f = Fraction("97/100")
print(float(f)) # prints 0.97
And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:
from fractions import Fraction
def toNum(interest):
f = Fraction(interest)
f = float(f)
if f > 1:
f /= 100
return f
print(toNum("97/100")) # prints 0.97
print(toNum(0.97)) # prints 0.97
print(toNum(9)) # prints 0.09
1
Why convert tofloatat all and not keep afractions.Fractionobject all along?
– Mathias Ettinger
2 days ago
@MathiasEttinger That's also a good option, just depends on preference.
– esote
2 days ago
add a comment |
up vote
0
down vote
While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:
if "/" in interest:
numerator, denominator = map(int, interest.split("/"))
return numerator / denominator
Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.
Note also that using sensible names makes it immediately obvious what this code does.
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
For reading a fraction such as "97/100", you can use the fractions library.
For example:
from fractions import Fraction
f = Fraction("97/100")
print(float(f)) # prints 0.97
And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:
from fractions import Fraction
def toNum(interest):
f = Fraction(interest)
f = float(f)
if f > 1:
f /= 100
return f
print(toNum("97/100")) # prints 0.97
print(toNum(0.97)) # prints 0.97
print(toNum(9)) # prints 0.09
1
Why convert tofloatat all and not keep afractions.Fractionobject all along?
– Mathias Ettinger
2 days ago
@MathiasEttinger That's also a good option, just depends on preference.
– esote
2 days ago
add a comment |
up vote
3
down vote
accepted
For reading a fraction such as "97/100", you can use the fractions library.
For example:
from fractions import Fraction
f = Fraction("97/100")
print(float(f)) # prints 0.97
And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:
from fractions import Fraction
def toNum(interest):
f = Fraction(interest)
f = float(f)
if f > 1:
f /= 100
return f
print(toNum("97/100")) # prints 0.97
print(toNum(0.97)) # prints 0.97
print(toNum(9)) # prints 0.09
1
Why convert tofloatat all and not keep afractions.Fractionobject all along?
– Mathias Ettinger
2 days ago
@MathiasEttinger That's also a good option, just depends on preference.
– esote
2 days ago
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
For reading a fraction such as "97/100", you can use the fractions library.
For example:
from fractions import Fraction
f = Fraction("97/100")
print(float(f)) # prints 0.97
And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:
from fractions import Fraction
def toNum(interest):
f = Fraction(interest)
f = float(f)
if f > 1:
f /= 100
return f
print(toNum("97/100")) # prints 0.97
print(toNum(0.97)) # prints 0.97
print(toNum(9)) # prints 0.09
For reading a fraction such as "97/100", you can use the fractions library.
For example:
from fractions import Fraction
f = Fraction("97/100")
print(float(f)) # prints 0.97
And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:
from fractions import Fraction
def toNum(interest):
f = Fraction(interest)
f = float(f)
if f > 1:
f /= 100
return f
print(toNum("97/100")) # prints 0.97
print(toNum(0.97)) # prints 0.97
print(toNum(9)) # prints 0.09
edited 2 days ago
answered 2 days ago
esote
1,4051731
1,4051731
1
Why convert tofloatat all and not keep afractions.Fractionobject all along?
– Mathias Ettinger
2 days ago
@MathiasEttinger That's also a good option, just depends on preference.
– esote
2 days ago
add a comment |
1
Why convert tofloatat all and not keep afractions.Fractionobject all along?
– Mathias Ettinger
2 days ago
@MathiasEttinger That's also a good option, just depends on preference.
– esote
2 days ago
1
1
Why convert to
float at all and not keep a fractions.Fraction object all along?– Mathias Ettinger
2 days ago
Why convert to
float at all and not keep a fractions.Fraction object all along?– Mathias Ettinger
2 days ago
@MathiasEttinger That's also a good option, just depends on preference.
– esote
2 days ago
@MathiasEttinger That's also a good option, just depends on preference.
– esote
2 days ago
add a comment |
up vote
0
down vote
While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:
if "/" in interest:
numerator, denominator = map(int, interest.split("/"))
return numerator / denominator
Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.
Note also that using sensible names makes it immediately obvious what this code does.
add a comment |
up vote
0
down vote
While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:
if "/" in interest:
numerator, denominator = map(int, interest.split("/"))
return numerator / denominator
Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.
Note also that using sensible names makes it immediately obvious what this code does.
add a comment |
up vote
0
down vote
up vote
0
down vote
While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:
if "/" in interest:
numerator, denominator = map(int, interest.split("/"))
return numerator / denominator
Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.
Note also that using sensible names makes it immediately obvious what this code does.
While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:
if "/" in interest:
numerator, denominator = map(int, interest.split("/"))
return numerator / denominator
Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.
Note also that using sensible names makes it immediately obvious what this code does.
answered yesterday
Graipher
22.5k53384
22.5k53384
add a comment |
add a comment |
ikadorus is a new contributor. Be nice, and check out our Code of Conduct.
ikadorus is a new contributor. Be nice, and check out our Code of Conduct.
ikadorus is a new contributor. Be nice, and check out our Code of Conduct.
ikadorus is a new contributor. Be nice, and check out our Code of Conduct.
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