Python if statements [on hold]











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I am trying to write some code in python where you enter a password. If you enter the correct password then it will display success and will close after 5 seconds. However, I keep getting syntax errors.



inputed_password = str(input("Enter password"))
correct_password = ("password123")
if inputed_password is correct_password:
print("Correct")
else print("incorrect")
import time

time.sleep(5)









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put on hold as off-topic by Graipher, πάντα ῥεῖ, 200_success, alecxe, t3chb0t Nov 18 at 13:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Graipher, πάντα ῥεῖ, 200_success, alecxe, t3chb0t

If this question can be reworded to fit the rules in the help center, please edit the question.









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    Hey, welcome to Code Review! This question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
    – Graipher
    Nov 18 at 12:19















up vote
-4
down vote

favorite












I am trying to write some code in python where you enter a password. If you enter the correct password then it will display success and will close after 5 seconds. However, I keep getting syntax errors.



inputed_password = str(input("Enter password"))
correct_password = ("password123")
if inputed_password is correct_password:
print("Correct")
else print("incorrect")
import time

time.sleep(5)









share|improve this question









New contributor




F.Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











put on hold as off-topic by Graipher, πάντα ῥεῖ, 200_success, alecxe, t3chb0t Nov 18 at 13:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Graipher, πάντα ῥεῖ, 200_success, alecxe, t3chb0t

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    Hey, welcome to Code Review! This question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
    – Graipher
    Nov 18 at 12:19













up vote
-4
down vote

favorite









up vote
-4
down vote

favorite











I am trying to write some code in python where you enter a password. If you enter the correct password then it will display success and will close after 5 seconds. However, I keep getting syntax errors.



inputed_password = str(input("Enter password"))
correct_password = ("password123")
if inputed_password is correct_password:
print("Correct")
else print("incorrect")
import time

time.sleep(5)









share|improve this question









New contributor




F.Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I am trying to write some code in python where you enter a password. If you enter the correct password then it will display success and will close after 5 seconds. However, I keep getting syntax errors.



inputed_password = str(input("Enter password"))
correct_password = ("password123")
if inputed_password is correct_password:
print("Correct")
else print("incorrect")
import time

time.sleep(5)






python python-3.x






share|improve this question









New contributor




F.Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




F.Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited Nov 18 at 14:56









Graham

538113




538113






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asked Nov 18 at 12:19









F.Ahmed

11




11




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F.Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





F.Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






F.Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




put on hold as off-topic by Graipher, πάντα ῥεῖ, 200_success, alecxe, t3chb0t Nov 18 at 13:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Graipher, πάντα ῥεῖ, 200_success, alecxe, t3chb0t

If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by Graipher, πάντα ῥεῖ, 200_success, alecxe, t3chb0t Nov 18 at 13:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Graipher, πάντα ῥεῖ, 200_success, alecxe, t3chb0t

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Hey, welcome to Code Review! This question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
    – Graipher
    Nov 18 at 12:19














  • 1




    Hey, welcome to Code Review! This question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
    – Graipher
    Nov 18 at 12:19








1




1




Hey, welcome to Code Review! This question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
– Graipher
Nov 18 at 12:19




Hey, welcome to Code Review! This question does not match what this site is about. Code Review is about improving existing, working code. Code Review is not the site to ask for help in fixing or changing what your code does. Once the code does what you want, we would love to help you do the same thing in a cleaner way! Please see our help center for more information.
– Graipher
Nov 18 at 12:19















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