Cfrtjryk

I would like to have in a variable the most recent file with a specific format.

exemple : in /home/test, 5 files :

• 
  file_test_hadoop_20181130.csv (This is the last modified one for hadoop file)


• file_test_hadoop_20181130.txt



• file_test_hadoop_20181130.ini




• file_test_hub_20181130.txt (This is the last modified one for txt file)



• file_test_hub_20181130.csv


• file_test_hub_20181130.ini

So the result that i want is the last modified one in each type :
HADOOP_NAME=file_test_hadoop_20181130.csv

HUB_NAME=file_test_hub_20181130.txt

So i started to do something like this :

HADOOP_NAME=$(ls -tr /home/test | tail -n 1 | find /home/test -maxdepth 1 -name "file_test_hadoop*" -printf '%fn')

HUB_NAME=$(ls -tr /home/test | tail -n 1 | find /home/test -maxdepth 1 -name "file_test_hub*" -printf '%fn')

But i get all files.

So you want to retrieve the most recently modified file with a specific naming pattern. The following commands should work for you:

[haxiel@testvm1 ~]$ ls -1t file_test_hadoop* | head -n1

file_test_hadoop_20181130.csv



[haxiel@testvm1 ~]$ ls -1t file_test_hub* | head -n1

file_test_hub_20181130.txt

Tried with below command and it worked fine

ls -ltrh /home/test/file_test_hadoop*| tail -n1

ls -ltrh /home/test/file_test_hub* | tail -n1

Instead of trying to parse ls or pipe ls to find & print, just use bash arrays, shell globbing, and the natural sorting order of YYYYMMDD:

cd /home/test

hadoop_files=(file_test_hadoop*)

HADOOP_NAME=${hadoop_files[-1]}

unset hadoop_files

hub_files=(file_test_hub*)

HUB_NAME=${hub_files[-1]}

unset hub_files

cd -

This populates temporary array variables with the list of filenames that match the various patterns. You'd want to add error-checking for the situations where there are no files at all, or files of an unexpected pattern (file_test_hadoop9, for example).