Cfrtjryk

try2:

   set -vn

   set -o pipefail

   set -e

   if grep -v '^#' file.tx | grep -P 'name' file.tx; then 

      echo "    No name"; exit 0;

      echo " This message is print from file.tx" 

      cat file.tx; fi

1) This code above is try to grep if name is not exist in file.tx then, it will echo " No Name ". I want only to grep the word if it not exits in uncommented line but it seems doesn't work.

2) How I want to make if first statement is false, it will go to second statement. The command above seem doesnt't work.

Note: This code is write in Makefile and the target name is try2

The issue is that instead of grepping for name in the non-commented data in file.tx, you run grep against the original file

grep -v '^#' file.tx | grep -P 'name' file.tx

                                      ^^^^^^^

                                     will not read from pipe

Instead, use

grep -v '^#' file.tx | grep -q 'name'

i.e., don't make the second grep in the pipeline read from the original file. Also, since you are only interested in the exit status of grep (for use in the if statement), use it with -q.

Taking your second question into account, it seem, if I understand correctly, that you want to run cat file.tx only if the string name is present outside of comments. In this case you have your logic backwards.

if grep -v '^#' file.ex | grep -q 'name'; then

This will be true if the string name occurs in a non-commented line. If you want to cat the file, then you would need to do it here:

if grep -v '^#' file.ex | grep -q 'name'; then 

    cat file.tx; 

else 

    echo 'No name'; 

fi

I'm uncertain about the exit 0 as that has implications for the rest of the Makefile target. If you want the target to fail if name is not present, then do exit 1 after the echo, otherwise don't exit at all (unless you have further shell code that you don't want to execute in the same Makefile target).

I'm also noticing your cd ../... Unless you have a file.tx in the current directory and in the directory ../.., the cat would fail for you. You have not mentioned why you step two directory levels up, so I can't say more about this.

Also note that the cd will be "undone" as soon as the shell snippet is completed as make runs each individual line of a target in a separate shell instance. This also means that the various set instructions that you have are run in separate shells.

If I understand the question, you have a file like this:

# a comment with the magic word name

some stuff that does not include the magic word

and you want "No name" to be printed. If the first line were uncommented, then "No name" should not be printed.

The following should do that:

if grep -v '^#' file.tx | grep -q name; then

       echo "no name"

fi

In your code, the second grep includes the filename, so it is not looking at the piped input from the first one. Also, since you're not using a Perl regexp, I dropped the -P, and I also added -q to suppress any output that grep might print if something matched.