Match an array from a JSON array with selected radio buttons
up vote
0
down vote
favorite
I’ve written some code that does the following:
Push the selected radio buttons (default options set by PHP) into an array (selectedOptions)
Loop over a JSON array (from Shopify) and for each array (variants) push the values into an array (variantOptions)
If the variantOptions array is equal to the selectedOptions (i.e if the users selection matches a valid product variant) then break the loop and update a few DOM elements, otherwise declare the product unavailable.
My question is... is this the most efficient way to do this? Is it okay to be looping multiple times for my checks and should I be storing the fetches JSON array somehow so I’m not fetching it via the API on every radio button change?
function optionChange() {
var gid = $('[data-gid]').attr('data-gid');
selectedOptions = new Array();
$('.product__options .option input:radio:checked').each(function() {
var $this = $(this),
selectedOption = $this.val();
selectedOptions.push(selectedOption);
});
client.product.fetch(gid).then(function(product) {
console.log('product ↓');
console.log(product);
$.each(product.variants, function(index, variant) {
variantOptions = new Array();
$.each(variant.selectedOptions, function(index, option) {
variantOptions.push(option.value);
});
if (variantOptions.join() == selectedOptions.join()) {
console.log('variant ↓');
console.log(variant);
$('a.add-to--cart').attr('data-variant-id', variant.id);
$('a.add-to--cart').text('Add to Cart');
$('span.money').text(parseFloat(variant.price).toLocaleString(navigator.language, {style: 'currency', currency: 'GBP'}));
return false;
} else {
$('a.add-to--cart').attr('data-variant-id', '');
$('a.add-to--cart').text('Unavaliable');
}
});
});
}
optionChange();
$('.product__options .option input:radio').on('change', optionChange);
javascript jquery json
add a comment |
up vote
0
down vote
favorite
I’ve written some code that does the following:
Push the selected radio buttons (default options set by PHP) into an array (selectedOptions)
Loop over a JSON array (from Shopify) and for each array (variants) push the values into an array (variantOptions)
If the variantOptions array is equal to the selectedOptions (i.e if the users selection matches a valid product variant) then break the loop and update a few DOM elements, otherwise declare the product unavailable.
My question is... is this the most efficient way to do this? Is it okay to be looping multiple times for my checks and should I be storing the fetches JSON array somehow so I’m not fetching it via the API on every radio button change?
function optionChange() {
var gid = $('[data-gid]').attr('data-gid');
selectedOptions = new Array();
$('.product__options .option input:radio:checked').each(function() {
var $this = $(this),
selectedOption = $this.val();
selectedOptions.push(selectedOption);
});
client.product.fetch(gid).then(function(product) {
console.log('product ↓');
console.log(product);
$.each(product.variants, function(index, variant) {
variantOptions = new Array();
$.each(variant.selectedOptions, function(index, option) {
variantOptions.push(option.value);
});
if (variantOptions.join() == selectedOptions.join()) {
console.log('variant ↓');
console.log(variant);
$('a.add-to--cart').attr('data-variant-id', variant.id);
$('a.add-to--cart').text('Add to Cart');
$('span.money').text(parseFloat(variant.price).toLocaleString(navigator.language, {style: 'currency', currency: 'GBP'}));
return false;
} else {
$('a.add-to--cart').attr('data-variant-id', '');
$('a.add-to--cart').text('Unavaliable');
}
});
});
}
optionChange();
$('.product__options .option input:radio').on('change', optionChange);
javascript jquery json
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I’ve written some code that does the following:
Push the selected radio buttons (default options set by PHP) into an array (selectedOptions)
Loop over a JSON array (from Shopify) and for each array (variants) push the values into an array (variantOptions)
If the variantOptions array is equal to the selectedOptions (i.e if the users selection matches a valid product variant) then break the loop and update a few DOM elements, otherwise declare the product unavailable.
My question is... is this the most efficient way to do this? Is it okay to be looping multiple times for my checks and should I be storing the fetches JSON array somehow so I’m not fetching it via the API on every radio button change?
function optionChange() {
var gid = $('[data-gid]').attr('data-gid');
selectedOptions = new Array();
$('.product__options .option input:radio:checked').each(function() {
var $this = $(this),
selectedOption = $this.val();
selectedOptions.push(selectedOption);
});
client.product.fetch(gid).then(function(product) {
console.log('product ↓');
console.log(product);
$.each(product.variants, function(index, variant) {
variantOptions = new Array();
$.each(variant.selectedOptions, function(index, option) {
variantOptions.push(option.value);
});
if (variantOptions.join() == selectedOptions.join()) {
console.log('variant ↓');
console.log(variant);
$('a.add-to--cart').attr('data-variant-id', variant.id);
$('a.add-to--cart').text('Add to Cart');
$('span.money').text(parseFloat(variant.price).toLocaleString(navigator.language, {style: 'currency', currency: 'GBP'}));
return false;
} else {
$('a.add-to--cart').attr('data-variant-id', '');
$('a.add-to--cart').text('Unavaliable');
}
});
});
}
optionChange();
$('.product__options .option input:radio').on('change', optionChange);
javascript jquery json
I’ve written some code that does the following:
Push the selected radio buttons (default options set by PHP) into an array (selectedOptions)
Loop over a JSON array (from Shopify) and for each array (variants) push the values into an array (variantOptions)
If the variantOptions array is equal to the selectedOptions (i.e if the users selection matches a valid product variant) then break the loop and update a few DOM elements, otherwise declare the product unavailable.
My question is... is this the most efficient way to do this? Is it okay to be looping multiple times for my checks and should I be storing the fetches JSON array somehow so I’m not fetching it via the API on every radio button change?
function optionChange() {
var gid = $('[data-gid]').attr('data-gid');
selectedOptions = new Array();
$('.product__options .option input:radio:checked').each(function() {
var $this = $(this),
selectedOption = $this.val();
selectedOptions.push(selectedOption);
});
client.product.fetch(gid).then(function(product) {
console.log('product ↓');
console.log(product);
$.each(product.variants, function(index, variant) {
variantOptions = new Array();
$.each(variant.selectedOptions, function(index, option) {
variantOptions.push(option.value);
});
if (variantOptions.join() == selectedOptions.join()) {
console.log('variant ↓');
console.log(variant);
$('a.add-to--cart').attr('data-variant-id', variant.id);
$('a.add-to--cart').text('Add to Cart');
$('span.money').text(parseFloat(variant.price).toLocaleString(navigator.language, {style: 'currency', currency: 'GBP'}));
return false;
} else {
$('a.add-to--cart').attr('data-variant-id', '');
$('a.add-to--cart').text('Unavaliable');
}
});
});
}
optionChange();
$('.product__options .option input:radio').on('change', optionChange);
javascript jquery json
javascript jquery json
asked 2 days ago
John the Painter
1061
1061
add a comment |
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f208708%2fmatch-an-array-from-a-json-array-with-selected-radio-buttons%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown