Python - username and password authentication
up vote
2
down vote
favorite
How can I reduce the amount of if statements in this program to make it more robust and any other tips for improvement would be grateful.
# importing pickle
import pickle
# defining variables
create_username = 0
create_password = 0
password = 0
username = 0
# this variable allows the user or denies the user to the rest of the program (will only run if access is 1)
access = 0
# creates a users dictionary
with open('users.pickle', 'rb') as f:
users = pickle.load(f)
print(users)
# sign up (creating new account)
while username not in users and username != 'signup':
username = input("enter username(type signup to create an account): ")
# add new user to dictionary
if username == "signup" or username == "Signup":
create_username = input("enter a new username: ")
create_password = input("enter a new password (Your password cannot be the same as your username !!!!!!!): ")
if create_password in users:
create_password = input("password taken re-enter: ")
# then adds the new username to the users dictionary
if username == 'signup':
users[create_username] = create_password
if username in users:
password = input("enter password: ")
if password in users:
print("access granted")
access = 1
if username not in users and username != 'signup':
username = input("enter username: ")
if username in users:
password = input("enter password")
if password in users:
print("access granted")
access = 1
if password not in users:
print("access denied")
with open('users.pickle', 'wb') as f:
# Pickle the 'data' dictionary using the highest protocol available.
pickle.dump(users, f, pickle.HIGHEST_PROTOCOL)
print(users)
python
New contributor
add a comment |
up vote
2
down vote
favorite
How can I reduce the amount of if statements in this program to make it more robust and any other tips for improvement would be grateful.
# importing pickle
import pickle
# defining variables
create_username = 0
create_password = 0
password = 0
username = 0
# this variable allows the user or denies the user to the rest of the program (will only run if access is 1)
access = 0
# creates a users dictionary
with open('users.pickle', 'rb') as f:
users = pickle.load(f)
print(users)
# sign up (creating new account)
while username not in users and username != 'signup':
username = input("enter username(type signup to create an account): ")
# add new user to dictionary
if username == "signup" or username == "Signup":
create_username = input("enter a new username: ")
create_password = input("enter a new password (Your password cannot be the same as your username !!!!!!!): ")
if create_password in users:
create_password = input("password taken re-enter: ")
# then adds the new username to the users dictionary
if username == 'signup':
users[create_username] = create_password
if username in users:
password = input("enter password: ")
if password in users:
print("access granted")
access = 1
if username not in users and username != 'signup':
username = input("enter username: ")
if username in users:
password = input("enter password")
if password in users:
print("access granted")
access = 1
if password not in users:
print("access denied")
with open('users.pickle', 'wb') as f:
# Pickle the 'data' dictionary using the highest protocol available.
pickle.dump(users, f, pickle.HIGHEST_PROTOCOL)
print(users)
python
New contributor
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
How can I reduce the amount of if statements in this program to make it more robust and any other tips for improvement would be grateful.
# importing pickle
import pickle
# defining variables
create_username = 0
create_password = 0
password = 0
username = 0
# this variable allows the user or denies the user to the rest of the program (will only run if access is 1)
access = 0
# creates a users dictionary
with open('users.pickle', 'rb') as f:
users = pickle.load(f)
print(users)
# sign up (creating new account)
while username not in users and username != 'signup':
username = input("enter username(type signup to create an account): ")
# add new user to dictionary
if username == "signup" or username == "Signup":
create_username = input("enter a new username: ")
create_password = input("enter a new password (Your password cannot be the same as your username !!!!!!!): ")
if create_password in users:
create_password = input("password taken re-enter: ")
# then adds the new username to the users dictionary
if username == 'signup':
users[create_username] = create_password
if username in users:
password = input("enter password: ")
if password in users:
print("access granted")
access = 1
if username not in users and username != 'signup':
username = input("enter username: ")
if username in users:
password = input("enter password")
if password in users:
print("access granted")
access = 1
if password not in users:
print("access denied")
with open('users.pickle', 'wb') as f:
# Pickle the 'data' dictionary using the highest protocol available.
pickle.dump(users, f, pickle.HIGHEST_PROTOCOL)
print(users)
python
New contributor
How can I reduce the amount of if statements in this program to make it more robust and any other tips for improvement would be grateful.
# importing pickle
import pickle
# defining variables
create_username = 0
create_password = 0
password = 0
username = 0
# this variable allows the user or denies the user to the rest of the program (will only run if access is 1)
access = 0
# creates a users dictionary
with open('users.pickle', 'rb') as f:
users = pickle.load(f)
print(users)
# sign up (creating new account)
while username not in users and username != 'signup':
username = input("enter username(type signup to create an account): ")
# add new user to dictionary
if username == "signup" or username == "Signup":
create_username = input("enter a new username: ")
create_password = input("enter a new password (Your password cannot be the same as your username !!!!!!!): ")
if create_password in users:
create_password = input("password taken re-enter: ")
# then adds the new username to the users dictionary
if username == 'signup':
users[create_username] = create_password
if username in users:
password = input("enter password: ")
if password in users:
print("access granted")
access = 1
if username not in users and username != 'signup':
username = input("enter username: ")
if username in users:
password = input("enter password")
if password in users:
print("access granted")
access = 1
if password not in users:
print("access denied")
with open('users.pickle', 'wb') as f:
# Pickle the 'data' dictionary using the highest protocol available.
pickle.dump(users, f, pickle.HIGHEST_PROTOCOL)
print(users)
python
python
New contributor
New contributor
New contributor
asked 11 hours ago
Krishna
111
111
New contributor
New contributor
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
# importing pickle
Obviously. Don't clutter your code with comments unless they add something we don't already know.
# defining variables
create_username = 0
create_password = 0
password = 0
username = 0
This is generally a bad idea, and you aren't in mid-1990s C. Don't predeclare your variables. Initialize them where they're actually used.
print(users)
If users
is a plain-old dictionary, I recommend the use of pprint
instead of print
.
"enter username(type signup to create an account): "
This is called in-band control, and is a bad idea. What if someone's username is called "signup"? You want out-of-band control. Ask explicitly whether the user wants to sign up or log in.
if username == "signup" or username == "Signup":
Don't do two comparisons. Convert username
to lowercase and compare with 'signup'
.
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
# importing pickle
Obviously. Don't clutter your code with comments unless they add something we don't already know.
# defining variables
create_username = 0
create_password = 0
password = 0
username = 0
This is generally a bad idea, and you aren't in mid-1990s C. Don't predeclare your variables. Initialize them where they're actually used.
print(users)
If users
is a plain-old dictionary, I recommend the use of pprint
instead of print
.
"enter username(type signup to create an account): "
This is called in-band control, and is a bad idea. What if someone's username is called "signup"? You want out-of-band control. Ask explicitly whether the user wants to sign up or log in.
if username == "signup" or username == "Signup":
Don't do two comparisons. Convert username
to lowercase and compare with 'signup'
.
add a comment |
up vote
0
down vote
# importing pickle
Obviously. Don't clutter your code with comments unless they add something we don't already know.
# defining variables
create_username = 0
create_password = 0
password = 0
username = 0
This is generally a bad idea, and you aren't in mid-1990s C. Don't predeclare your variables. Initialize them where they're actually used.
print(users)
If users
is a plain-old dictionary, I recommend the use of pprint
instead of print
.
"enter username(type signup to create an account): "
This is called in-band control, and is a bad idea. What if someone's username is called "signup"? You want out-of-band control. Ask explicitly whether the user wants to sign up or log in.
if username == "signup" or username == "Signup":
Don't do two comparisons. Convert username
to lowercase and compare with 'signup'
.
add a comment |
up vote
0
down vote
up vote
0
down vote
# importing pickle
Obviously. Don't clutter your code with comments unless they add something we don't already know.
# defining variables
create_username = 0
create_password = 0
password = 0
username = 0
This is generally a bad idea, and you aren't in mid-1990s C. Don't predeclare your variables. Initialize them where they're actually used.
print(users)
If users
is a plain-old dictionary, I recommend the use of pprint
instead of print
.
"enter username(type signup to create an account): "
This is called in-band control, and is a bad idea. What if someone's username is called "signup"? You want out-of-band control. Ask explicitly whether the user wants to sign up or log in.
if username == "signup" or username == "Signup":
Don't do two comparisons. Convert username
to lowercase and compare with 'signup'
.
# importing pickle
Obviously. Don't clutter your code with comments unless they add something we don't already know.
# defining variables
create_username = 0
create_password = 0
password = 0
username = 0
This is generally a bad idea, and you aren't in mid-1990s C. Don't predeclare your variables. Initialize them where they're actually used.
print(users)
If users
is a plain-old dictionary, I recommend the use of pprint
instead of print
.
"enter username(type signup to create an account): "
This is called in-band control, and is a bad idea. What if someone's username is called "signup"? You want out-of-band control. Ask explicitly whether the user wants to sign up or log in.
if username == "signup" or username == "Signup":
Don't do two comparisons. Convert username
to lowercase and compare with 'signup'
.
answered 8 hours ago
Reinderien
1,724616
1,724616
add a comment |
add a comment |
Krishna is a new contributor. Be nice, and check out our Code of Conduct.
Krishna is a new contributor. Be nice, and check out our Code of Conduct.
Krishna is a new contributor. Be nice, and check out our Code of Conduct.
Krishna is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f209464%2fpython-username-and-password-authentication%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown