How to create a list of six unit vectors in 3D?











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I want to have a list {{1,0,0},{0,1,0},{0,0,1},{-1,0,0},{0,-1,0},{0,0,-1}}. How to generate it smartly?










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    up vote
    2
    down vote

    favorite












    I want to have a list {{1,0,0},{0,1,0},{0,0,1},{-1,0,0},{0,-1,0},{0,0,-1}}. How to generate it smartly?










    share|improve this question
























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I want to have a list {{1,0,0},{0,1,0},{0,0,1},{-1,0,0},{0,-1,0},{0,0,-1}}. How to generate it smartly?










      share|improve this question













      I want to have a list {{1,0,0},{0,1,0},{0,0,1},{-1,0,0},{0,-1,0},{0,0,-1}}. How to generate it smartly?







      list-manipulation






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      share|improve this question










      asked Nov 30 at 15:10









      Artificial Stupidity

      21219




      21219






















          3 Answers
          3






          active

          oldest

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          up vote
          5
          down vote



          accepted










          Perhaps this



          Join[IdentityMatrix[3], -IdentityMatrix[3]]
          (* {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}} *)





          share|improve this answer





















          • +1: Good one! Thanks!
            – Artificial Stupidity
            Nov 30 at 15:23






          • 1




            I like the variant Join[#, -#] &@IdentityMatrix[3]
            – mikado
            Nov 30 at 16:53






          • 1




            @mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
            – Michael E2
            Nov 30 at 17:04


















          up vote
          2
          down vote













          Join@@(Permutations[#]&/@{#,-#}&@{1,0,0})    



          {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}







          share|improve this answer




























            up vote
            1
            down vote













            UnitVector:



            Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])



            {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}






            share|improve this answer





















              Your Answer





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              3 Answers
              3






              active

              oldest

              votes








              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              5
              down vote



              accepted










              Perhaps this



              Join[IdentityMatrix[3], -IdentityMatrix[3]]
              (* {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}} *)





              share|improve this answer





















              • +1: Good one! Thanks!
                – Artificial Stupidity
                Nov 30 at 15:23






              • 1




                I like the variant Join[#, -#] &@IdentityMatrix[3]
                – mikado
                Nov 30 at 16:53






              • 1




                @mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
                – Michael E2
                Nov 30 at 17:04















              up vote
              5
              down vote



              accepted










              Perhaps this



              Join[IdentityMatrix[3], -IdentityMatrix[3]]
              (* {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}} *)





              share|improve this answer





















              • +1: Good one! Thanks!
                – Artificial Stupidity
                Nov 30 at 15:23






              • 1




                I like the variant Join[#, -#] &@IdentityMatrix[3]
                – mikado
                Nov 30 at 16:53






              • 1




                @mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
                – Michael E2
                Nov 30 at 17:04













              up vote
              5
              down vote



              accepted







              up vote
              5
              down vote



              accepted






              Perhaps this



              Join[IdentityMatrix[3], -IdentityMatrix[3]]
              (* {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}} *)





              share|improve this answer












              Perhaps this



              Join[IdentityMatrix[3], -IdentityMatrix[3]]
              (* {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}} *)






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Nov 30 at 15:22









              Michael E2

              144k11193463




              144k11193463












              • +1: Good one! Thanks!
                – Artificial Stupidity
                Nov 30 at 15:23






              • 1




                I like the variant Join[#, -#] &@IdentityMatrix[3]
                – mikado
                Nov 30 at 16:53






              • 1




                @mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
                – Michael E2
                Nov 30 at 17:04


















              • +1: Good one! Thanks!
                – Artificial Stupidity
                Nov 30 at 15:23






              • 1




                I like the variant Join[#, -#] &@IdentityMatrix[3]
                – mikado
                Nov 30 at 16:53






              • 1




                @mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
                – Michael E2
                Nov 30 at 17:04
















              +1: Good one! Thanks!
              – Artificial Stupidity
              Nov 30 at 15:23




              +1: Good one! Thanks!
              – Artificial Stupidity
              Nov 30 at 15:23




              1




              1




              I like the variant Join[#, -#] &@IdentityMatrix[3]
              – mikado
              Nov 30 at 16:53




              I like the variant Join[#, -#] &@IdentityMatrix[3]
              – mikado
              Nov 30 at 16:53




              1




              1




              @mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
              – Michael E2
              Nov 30 at 17:04




              @mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
              – Michael E2
              Nov 30 at 17:04










              up vote
              2
              down vote













              Join@@(Permutations[#]&/@{#,-#}&@{1,0,0})    



              {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}







              share|improve this answer

























                up vote
                2
                down vote













                Join@@(Permutations[#]&/@{#,-#}&@{1,0,0})    



                {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}







                share|improve this answer























                  up vote
                  2
                  down vote










                  up vote
                  2
                  down vote









                  Join@@(Permutations[#]&/@{#,-#}&@{1,0,0})    



                  {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}







                  share|improve this answer












                  Join@@(Permutations[#]&/@{#,-#}&@{1,0,0})    



                  {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 30 at 15:23









                  J42161217

                  3,687220




                  3,687220






















                      up vote
                      1
                      down vote













                      UnitVector:



                      Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])



                      {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}






                      share|improve this answer

























                        up vote
                        1
                        down vote













                        UnitVector:



                        Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])



                        {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}






                        share|improve this answer























                          up vote
                          1
                          down vote










                          up vote
                          1
                          down vote









                          UnitVector:



                          Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])



                          {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}






                          share|improve this answer












                          UnitVector:



                          Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])



                          {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1}}







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Dec 1 at 11:31









                          Αλέξανδρος Ζεγγ

                          3,7321927




                          3,7321927






























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