Store Single Variable from Input File into Array
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0
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I am trying to create a logon program for users listed on a file. When I try to store the names into and array and check to see if they exist, I only return the header. So if I put NAME as the fname, it says it exists. But if I put Bob as fname, it says it doesn't. How do I store each first and last name into an array?
users.txt
NAME PASSWORD DEPT AUTH
Bob Jones 12345678 MKTG N
Sam Smith password MKTG Y
Pat Johnson 87654321 SALES N
Dina Shore drowssap OPS Y
Script
#!/bin/bash
FILE="users.txt"
read -p "Please enter first and last name: " fname lname
read -a name < $FILE
for name in "${name[0]}"
do
if [[ ${name[0]} = $fname ]]
then
echo "exist"
else
echo "Not Exist"
fi
done
linux bash
asked Dec 6 at 2:44
Jeff
1
add a comment |
up vote
0
down vote
favorite
I am trying to create a logon program for users listed on a file. When I try to store the names into and array and check to see if they exist, I only return the header. So if I put NAME as the fname, it says it exists. But if I put Bob as fname, it says it doesn't. How do I store each first and last name into an array?
users.txt
NAME PASSWORD DEPT AUTH
Bob Jones 12345678 MKTG N
Sam Smith password MKTG Y
Pat Johnson 87654321 SALES N
Dina Shore drowssap OPS Y
Script
#!/bin/bash
FILE="users.txt"
read -p "Please enter first and last name: " fname lname
read -a name < $FILE
for name in "${name[0]}"
do
if [[ ${name[0]} = $fname ]]
then
echo "exist"
else
echo "Not Exist"
fi
done
linux bash
asked Dec 6 at 2:44
Jeff
1
Why an array at all?
– RudiC
Dec 6 at 11:56
The assignment asks for it but I may not end up using one.
– Jeff
Dec 6 at 21:58
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am trying to create a logon program for users listed on a file. When I try to store the names into and array and check to see if they exist, I only return the header. So if I put NAME as the fname, it says it exists. But if I put Bob as fname, it says it doesn't. How do I store each first and last name into an array?
users.txt
NAME PASSWORD DEPT AUTH
Bob Jones 12345678 MKTG N
Sam Smith password MKTG Y
Pat Johnson 87654321 SALES N
Dina Shore drowssap OPS Y
Script
#!/bin/bash
FILE="users.txt"
read -p "Please enter first and last name: " fname lname
read -a name < $FILE
for name in "${name[0]}"
do
if [[ ${name[0]} = $fname ]]
then
echo "exist"
else
echo "Not Exist"
fi
done
linux bash
asked Dec 6 at 2:44
Jeff
1
I am trying to create a logon program for users listed on a file. When I try to store the names into and array and check to see if they exist, I only return the header. So if I put NAME as the fname, it says it exists. But if I put Bob as fname, it says it doesn't. How do I store each first and last name into an array?
users.txt
NAME PASSWORD DEPT AUTH
Bob Jones 12345678 MKTG N
Sam Smith password MKTG Y
Pat Johnson 87654321 SALES N
Dina Shore drowssap OPS Y
Script
#!/bin/bash
FILE="users.txt"
read -p "Please enter first and last name: " fname lname
read -a name < $FILE
for name in "${name[0]}"
do
if [[ ${name[0]} = $fname ]]
then
echo "exist"
else
echo "Not Exist"
fi
done
linux bash
linux bash
asked Dec 6 at 2:44
Jeff
1
asked Dec 6 at 2:44
Jeff
1
edited Dec 6 at 10:37
asked Dec 6 at 2:44
Jeff
1
asked Dec 6 at 2:44
Jeff
1
asked Dec 6 at 2:44
Jeff
1
1
Why an array at all?
– RudiC
Dec 6 at 11:56
The assignment asks for it but I may not end up using one.
– Jeff
Dec 6 at 21:58
add a comment |
Why an array at all?
– RudiC
Dec 6 at 11:56
The assignment asks for it but I may not end up using one.
– Jeff
Dec 6 at 21:58
Why an array at all?
– RudiC
Dec 6 at 11:56
Why an array at all?
– RudiC
Dec 6 at 11:56
The assignment asks for it but I may not end up using one.
– Jeff
Dec 6 at 21:58
The assignment asks for it but I may not end up using one.
– Jeff
Dec 6 at 21:58
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
To answer your question: the single read reads the first line's (the header's) words into the array elements. No other lines are considered. You might experiment with the readarray command, but that doesn't lean itself towards your problem. YMMV
No array needed. Use adequate text tools instead. Try
#!/bin/bash
FILE="users.txt"
read -p "Please enter first and last name: " fname lname
if grep "$fname.*$lname" $FILE
then echo "exist"
else echo "Not Exist"
fi
answered Dec 6 at 12:03
RudiC
3,9541312
Thanks! I needed to match the user name with the password in the file so I didif grep "$fname.*$lname.*$psswd" $FILEand it worked great.
– Jeff
Dec 6 at 21:55
add a comment |
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
To answer your question: the single read reads the first line's (the header's) words into the array elements. No other lines are considered. You might experiment with the readarray command, but that doesn't lean itself towards your problem. YMMV
No array needed. Use adequate text tools instead. Try
#!/bin/bash
FILE="users.txt"
read -p "Please enter first and last name: " fname lname
if grep "$fname.*$lname" $FILE
then echo "exist"
else echo "Not Exist"
fi
answered Dec 6 at 12:03
RudiC
3,9541312
Thanks! I needed to match the user name with the password in the file so I didif grep "$fname.*$lname.*$psswd" $FILEand it worked great.
– Jeff
Dec 6 at 21:55
add a comment |
up vote
0
down vote
To answer your question: the single read reads the first line's (the header's) words into the array elements. No other lines are considered. You might experiment with the readarray command, but that doesn't lean itself towards your problem. YMMV
No array needed. Use adequate text tools instead. Try
#!/bin/bash
FILE="users.txt"
read -p "Please enter first and last name: " fname lname
if grep "$fname.*$lname" $FILE
then echo "exist"
else echo "Not Exist"
fi
answered Dec 6 at 12:03
RudiC
3,9541312
Thanks! I needed to match the user name with the password in the file so I didif grep "$fname.*$lname.*$psswd" $FILEand it worked great.
– Jeff
Dec 6 at 21:55
add a comment |
up vote
0
down vote
up vote
0
down vote
To answer your question: the single read reads the first line's (the header's) words into the array elements. No other lines are considered. You might experiment with the readarray command, but that doesn't lean itself towards your problem. YMMV
No array needed. Use adequate text tools instead. Try
#!/bin/bash
FILE="users.txt"
read -p "Please enter first and last name: " fname lname
if grep "$fname.*$lname" $FILE
then echo "exist"
else echo "Not Exist"
fi
answered Dec 6 at 12:03
RudiC
3,9541312
To answer your question: the single read reads the first line's (the header's) words into the array elements. No other lines are considered. You might experiment with the readarray command, but that doesn't lean itself towards your problem. YMMV
No array needed. Use adequate text tools instead. Try
#!/bin/bash
FILE="users.txt"
read -p "Please enter first and last name: " fname lname
if grep "$fname.*$lname" $FILE
then echo "exist"
else echo "Not Exist"
fi
answered Dec 6 at 12:03
RudiC
3,9541312
answered Dec 6 at 12:03
RudiC
3,9541312
answered Dec 6 at 12:03
RudiC
3,9541312
answered Dec 6 at 12:03
RudiC
3,9541312
3,9541312
Thanks! I needed to match the user name with the password in the file so I didif grep "$fname.*$lname.*$psswd" $FILEand it worked great.
– Jeff
Dec 6 at 21:55
add a comment |
Thanks! I needed to match the user name with the password in the file so I didif grep "$fname.*$lname.*$psswd" $FILEand it worked great.
– Jeff
Dec 6 at 21:55
Thanks! I needed to match the user name with the password in the file so I did
if grep "$fname.*$lname.*$psswd" $FILE and it worked great.– Jeff
Dec 6 at 21:55
Thanks! I needed to match the user name with the password in the file so I did
if grep "$fname.*$lname.*$psswd" $FILE and it worked great.– Jeff
Dec 6 at 21:55
add a comment |
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Why an array at all?
– RudiC
Dec 6 at 11:56
The assignment asks for it but I may not end up using one.
– Jeff
Dec 6 at 21:58