How can I grep for empty functions?
I'm recursively looking in a directory for all functions containing only a blank one-line comment, such as the following:
public function index()
{
//
}
I tried grep -PR "//$" * with no luck.
shell grep regular-expression
edited Jan 8 at 0:08
Rui F Ribeiro
39.5k1479132
asked Jan 7 at 18:49
Brandon M.Brandon M.
1164
add a comment |
I'm recursively looking in a directory for all functions containing only a blank one-line comment, such as the following:
public function index()
{
//
}
I tried grep -PR "//$" * with no luck.
shell grep regular-expression
edited Jan 8 at 0:08
Rui F Ribeiro
39.5k1479132
asked Jan 7 at 18:49
Brandon M.Brandon M.
1164
3
Doesn'tgrep -PR "^s*//s*$" *work?
– terdon♦
Jan 7 at 18:52
1
It does. Thanks!
– Brandon M.
Jan 7 at 19:01
add a comment |
I'm recursively looking in a directory for all functions containing only a blank one-line comment, such as the following:
public function index()
{
//
}
I tried grep -PR "//$" * with no luck.
shell grep regular-expression
edited Jan 8 at 0:08
Rui F Ribeiro
39.5k1479132
asked Jan 7 at 18:49
Brandon M.Brandon M.
1164
I'm recursively looking in a directory for all functions containing only a blank one-line comment, such as the following:
public function index()
{
//
}
I tried grep -PR "//$" * with no luck.
shell grep regular-expression
shell grep regular-expression
edited Jan 8 at 0:08
Rui F Ribeiro
39.5k1479132
asked Jan 7 at 18:49
Brandon M.Brandon M.
1164
edited Jan 8 at 0:08
Rui F Ribeiro
39.5k1479132
asked Jan 7 at 18:49
Brandon M.Brandon M.
1164
edited Jan 8 at 0:08
Rui F Ribeiro
39.5k1479132
edited Jan 8 at 0:08
Rui F Ribeiro
39.5k1479132
edited Jan 8 at 0:08
Rui F Ribeiro
39.5k1479132
39.5k1479132
asked Jan 7 at 18:49
Brandon M.Brandon M.
1164
asked Jan 7 at 18:49
Brandon M.Brandon M.
1164
asked Jan 7 at 18:49
Brandon M.Brandon M.
1164
1164
3
Doesn'tgrep -PR "^s*//s*$" *work?
– terdon♦
Jan 7 at 18:52
1
It does. Thanks!
– Brandon M.
Jan 7 at 19:01
add a comment |
3
Doesn'tgrep -PR "^s*//s*$" *work?
– terdon♦
Jan 7 at 18:52
1
It does. Thanks!
– Brandon M.
Jan 7 at 19:01
3
3
Doesn't
grep -PR "^s*//s*$" * work?– terdon♦
Jan 7 at 18:52
Doesn't
grep -PR "^s*//s*$" * work?– terdon♦
Jan 7 at 18:52
1
1
It does. Thanks!
– Brandon M.
Jan 7 at 19:01
It does. Thanks!
– Brandon M.
Jan 7 at 19:01
add a comment |
1 Answer
1
active
oldest
votes
Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered Jan 7 at 19:04
terdon♦terdon
129k32253428
add a comment |
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1 Answer
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1 Answer
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active
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Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered Jan 7 at 19:04
terdon♦terdon
129k32253428
add a comment |
Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered Jan 7 at 19:04
terdon♦terdon
129k32253428
add a comment |
Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered Jan 7 at 19:04
terdon♦terdon
129k32253428
Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered Jan 7 at 19:04
terdon♦terdon
129k32253428
answered Jan 7 at 19:04
terdon♦terdon
129k32253428
answered Jan 7 at 19:04
terdon♦terdon
129k32253428
answered Jan 7 at 19:04
terdon♦terdon
129k32253428
129k32253428
add a comment |
add a comment |
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3
Doesn't
grep -PR "^s*//s*$" *work?– terdon♦
Jan 7 at 18:52
1
It does. Thanks!
– Brandon M.
Jan 7 at 19:01