Bash Conditional String and Integer together
up vote
-1
down vote
favorite
I am trying to do both integer and string comparison in a statement as follows:
$ TimeHr=$(date +%_H)
$ Time=Night
$ echo TimeHr
1
$ if ((TimeHr>18 || TimeHr<5 )) && [ Time == "Night" ]; then echo "Night Time"; else echo "Day Time"; fi
Day Time
$ if ((TimeHr>18 || TimeHr<5 )) && [[ Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
Day Time
But it is not printing the correct if-branch. How should I modify it?
Edit:
I prefer to use (( for numerical comparisons as the code looks more understandable.
bash shell-script command-line gnu
asked Dec 3 at 0:14
Nikhil
23319
add a comment |
up vote
-1
down vote
favorite
I am trying to do both integer and string comparison in a statement as follows:
$ TimeHr=$(date +%_H)
$ Time=Night
$ echo TimeHr
1
$ if ((TimeHr>18 || TimeHr<5 )) && [ Time == "Night" ]; then echo "Night Time"; else echo "Day Time"; fi
Day Time
$ if ((TimeHr>18 || TimeHr<5 )) && [[ Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
Day Time
But it is not printing the correct if-branch. How should I modify it?
Edit:
I prefer to use (( for numerical comparisons as the code looks more understandable.
bash shell-script command-line gnu
asked Dec 3 at 0:14
Nikhil
23319
Crawl before you leap high hurdles. If your attempt to combine three tests into one doesn't work, try to get a single test working. P.S. For what you're doing, there's no reason to include the_in+%_H.
– G-Man
Dec 3 at 16:50
@G-Man I am not sure, but I think I did this to remove the leading 0, to prevent the number to be interpreted as octal form.
– Nikhil
Dec 3 at 17:14
OK, good point; I had overlooked that issue. It looks like+%-Hwould work as well.
– G-Man
Dec 3 at 17:38
@G-Man What is the difference between_and-here?
– Nikhil
Dec 3 at 17:40
1
_replaces the leading zero with a space ( 7),-simply outputs numbers less than ten as a single digit, with nothing in front.
– G-Man
Dec 3 at 17:43
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I am trying to do both integer and string comparison in a statement as follows:
$ TimeHr=$(date +%_H)
$ Time=Night
$ echo TimeHr
1
$ if ((TimeHr>18 || TimeHr<5 )) && [ Time == "Night" ]; then echo "Night Time"; else echo "Day Time"; fi
Day Time
$ if ((TimeHr>18 || TimeHr<5 )) && [[ Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
Day Time
But it is not printing the correct if-branch. How should I modify it?
Edit:
I prefer to use (( for numerical comparisons as the code looks more understandable.
bash shell-script command-line gnu
asked Dec 3 at 0:14
Nikhil
23319
I am trying to do both integer and string comparison in a statement as follows:
$ TimeHr=$(date +%_H)
$ Time=Night
$ echo TimeHr
1
$ if ((TimeHr>18 || TimeHr<5 )) && [ Time == "Night" ]; then echo "Night Time"; else echo "Day Time"; fi
Day Time
$ if ((TimeHr>18 || TimeHr<5 )) && [[ Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
Day Time
But it is not printing the correct if-branch. How should I modify it?
Edit:
I prefer to use (( for numerical comparisons as the code looks more understandable.
bash shell-script command-line gnu
bash shell-script command-line gnu
asked Dec 3 at 0:14
Nikhil
23319
asked Dec 3 at 0:14
Nikhil
23319
edited Dec 3 at 0:27
asked Dec 3 at 0:14
Nikhil
23319
asked Dec 3 at 0:14
Nikhil
23319
asked Dec 3 at 0:14
Nikhil
23319
23319
Crawl before you leap high hurdles. If your attempt to combine three tests into one doesn't work, try to get a single test working. P.S. For what you're doing, there's no reason to include the_in+%_H.
– G-Man
Dec 3 at 16:50
@G-Man I am not sure, but I think I did this to remove the leading 0, to prevent the number to be interpreted as octal form.
– Nikhil
Dec 3 at 17:14
OK, good point; I had overlooked that issue. It looks like+%-Hwould work as well.
– G-Man
Dec 3 at 17:38
@G-Man What is the difference between_and-here?
– Nikhil
Dec 3 at 17:40
1
_replaces the leading zero with a space ( 7),-simply outputs numbers less than ten as a single digit, with nothing in front.
– G-Man
Dec 3 at 17:43
add a comment |
Crawl before you leap high hurdles. If your attempt to combine three tests into one doesn't work, try to get a single test working. P.S. For what you're doing, there's no reason to include the_in+%_H.
– G-Man
Dec 3 at 16:50
@G-Man I am not sure, but I think I did this to remove the leading 0, to prevent the number to be interpreted as octal form.
– Nikhil
Dec 3 at 17:14
OK, good point; I had overlooked that issue. It looks like+%-Hwould work as well.
– G-Man
Dec 3 at 17:38
@G-Man What is the difference between_and-here?
– Nikhil
Dec 3 at 17:40
1
_replaces the leading zero with a space ( 7),-simply outputs numbers less than ten as a single digit, with nothing in front.
– G-Man
Dec 3 at 17:43
Crawl before you leap high hurdles. If your attempt to combine three tests into one doesn't work, try to get a single test working. P.S. For what you're doing, there's no reason to include the
_ in +%_H.– G-Man
Dec 3 at 16:50
Crawl before you leap high hurdles. If your attempt to combine three tests into one doesn't work, try to get a single test working. P.S. For what you're doing, there's no reason to include the
_ in +%_H.– G-Man
Dec 3 at 16:50
@G-Man I am not sure, but I think I did this to remove the leading 0, to prevent the number to be interpreted as octal form.
– Nikhil
Dec 3 at 17:14
@G-Man I am not sure, but I think I did this to remove the leading 0, to prevent the number to be interpreted as octal form.
– Nikhil
Dec 3 at 17:14
OK, good point; I had overlooked that issue. It looks like
+%-H would work as well.– G-Man
Dec 3 at 17:38
OK, good point; I had overlooked that issue. It looks like
+%-H would work as well.– G-Man
Dec 3 at 17:38
@G-Man What is the difference between
_ and - here?– Nikhil
Dec 3 at 17:40
@G-Man What is the difference between
_ and - here?– Nikhil
Dec 3 at 17:40
1
1
_ replaces the leading zero with a space ( 7), - simply outputs numbers less than ten as a single digit, with nothing in front.– G-Man
Dec 3 at 17:43
_ replaces the leading zero with a space ( 7), - simply outputs numbers less than ten as a single digit, with nothing in front.– G-Man
Dec 3 at 17:43
add a comment |
1 Answer
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votes
up vote
2
down vote
accepted
I would combine the two conditionals into a single one
if [[ ( $TimeHr -gt 18 || $TimeHr -lt 5 ) && $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
Night Time
However your original test has a simple error; inside the [ and [[ tests you need to use $variable and not just variable.
So
if ((TimeHr>18 || TimeHr<5 )) && [[ $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
answered Dec 3 at 0:24
Stephen Harris
24k24477
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
I would combine the two conditionals into a single one
if [[ ( $TimeHr -gt 18 || $TimeHr -lt 5 ) && $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
Night Time
However your original test has a simple error; inside the [ and [[ tests you need to use $variable and not just variable.
So
if ((TimeHr>18 || TimeHr<5 )) && [[ $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
answered Dec 3 at 0:24
Stephen Harris
24k24477
add a comment |
up vote
2
down vote
accepted
I would combine the two conditionals into a single one
if [[ ( $TimeHr -gt 18 || $TimeHr -lt 5 ) && $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
Night Time
However your original test has a simple error; inside the [ and [[ tests you need to use $variable and not just variable.
So
if ((TimeHr>18 || TimeHr<5 )) && [[ $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
answered Dec 3 at 0:24
Stephen Harris
24k24477
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
I would combine the two conditionals into a single one
if [[ ( $TimeHr -gt 18 || $TimeHr -lt 5 ) && $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
Night Time
However your original test has a simple error; inside the [ and [[ tests you need to use $variable and not just variable.
So
if ((TimeHr>18 || TimeHr<5 )) && [[ $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
answered Dec 3 at 0:24
Stephen Harris
24k24477
I would combine the two conditionals into a single one
if [[ ( $TimeHr -gt 18 || $TimeHr -lt 5 ) && $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
Night Time
However your original test has a simple error; inside the [ and [[ tests you need to use $variable and not just variable.
So
if ((TimeHr>18 || TimeHr<5 )) && [[ $Time == "Night" ]]; then echo "Night Time"; else echo "Day Time"; fi
answered Dec 3 at 0:24
Stephen Harris
24k24477
answered Dec 3 at 0:24
Stephen Harris
24k24477
answered Dec 3 at 0:24
Stephen Harris
24k24477
answered Dec 3 at 0:24
Stephen Harris
24k24477
24k24477
add a comment |
add a comment |
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Crawl before you leap high hurdles. If your attempt to combine three tests into one doesn't work, try to get a single test working. P.S. For what you're doing, there's no reason to include the
_in+%_H.– G-Man
Dec 3 at 16:50
@G-Man I am not sure, but I think I did this to remove the leading 0, to prevent the number to be interpreted as octal form.
– Nikhil
Dec 3 at 17:14
OK, good point; I had overlooked that issue. It looks like
+%-Hwould work as well.– G-Man
Dec 3 at 17:38
@G-Man What is the difference between
_and-here?– Nikhil
Dec 3 at 17:40
1
_replaces the leading zero with a space ( 7),-simply outputs numbers less than ten as a single digit, with nothing in front.– G-Man
Dec 3 at 17:43