How can I insert a character in a string?
I have tried
echo "ABCDE-123456" | sed 's/-//' | sed 's/./& -/g'
A -B -C -D -E -1 -2 -3 -4 -5 -6 -
sed is not putting the - on the first character.
How can I make it output
-A -B -C -D -E -1 -2 -3 -4 -5 -6
`
bash sed
asked Dec 10 at 10:16
Bret Joseph
758
add a comment |
I have tried
echo "ABCDE-123456" | sed 's/-//' | sed 's/./& -/g'
A -B -C -D -E -1 -2 -3 -4 -5 -6 -
sed is not putting the - on the first character.
How can I make it output
-A -B -C -D -E -1 -2 -3 -4 -5 -6
`
bash sed
asked Dec 10 at 10:16
Bret Joseph
758
what aboutsed 's/./-& /g'?
– RoVo
Dec 10 at 10:19
@RoVo thanks it works
– Bret Joseph
Dec 10 at 10:32
add a comment |
I have tried
echo "ABCDE-123456" | sed 's/-//' | sed 's/./& -/g'
A -B -C -D -E -1 -2 -3 -4 -5 -6 -
sed is not putting the - on the first character.
How can I make it output
-A -B -C -D -E -1 -2 -3 -4 -5 -6
`
bash sed
asked Dec 10 at 10:16
Bret Joseph
758
I have tried
echo "ABCDE-123456" | sed 's/-//' | sed 's/./& -/g'
A -B -C -D -E -1 -2 -3 -4 -5 -6 -
sed is not putting the - on the first character.
How can I make it output
-A -B -C -D -E -1 -2 -3 -4 -5 -6
`
bash sed
bash sed
asked Dec 10 at 10:16
Bret Joseph
758
asked Dec 10 at 10:16
Bret Joseph
758
asked Dec 10 at 10:16
Bret Joseph
758
asked Dec 10 at 10:16
Bret Joseph
758
asked Dec 10 at 10:16
Bret Joseph
758
758
what aboutsed 's/./-& /g'?
– RoVo
Dec 10 at 10:19
@RoVo thanks it works
– Bret Joseph
Dec 10 at 10:32
add a comment |
what aboutsed 's/./-& /g'?
– RoVo
Dec 10 at 10:19
@RoVo thanks it works
– Bret Joseph
Dec 10 at 10:32
what about
sed 's/./-& /g' ?– RoVo
Dec 10 at 10:19
what about
sed 's/./-& /g' ?– RoVo
Dec 10 at 10:19
@RoVo thanks it works
– Bret Joseph
Dec 10 at 10:32
@RoVo thanks it works
– Bret Joseph
Dec 10 at 10:32
add a comment |
1 Answer
1
active
oldest
votes
You can turn around your sed replacement string to be -&.
Also, no need to call sed twice as you can combine multiple commands with ;.
sed 's/-//; s/./-& /g'
Note, that you will have a space at the end which you might need to get rid of.
answered Dec 10 at 10:36
RoVo
2,558215
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "106"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f487074%2fhow-can-i-insert-a-character-in-a-string%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can turn around your sed replacement string to be -&.
Also, no need to call sed twice as you can combine multiple commands with ;.
sed 's/-//; s/./-& /g'
Note, that you will have a space at the end which you might need to get rid of.
answered Dec 10 at 10:36
RoVo
2,558215
add a comment |
You can turn around your sed replacement string to be -&.
Also, no need to call sed twice as you can combine multiple commands with ;.
sed 's/-//; s/./-& /g'
Note, that you will have a space at the end which you might need to get rid of.
answered Dec 10 at 10:36
RoVo
2,558215
add a comment |
You can turn around your sed replacement string to be -&.
Also, no need to call sed twice as you can combine multiple commands with ;.
sed 's/-//; s/./-& /g'
Note, that you will have a space at the end which you might need to get rid of.
answered Dec 10 at 10:36
RoVo
2,558215
You can turn around your sed replacement string to be -&.
Also, no need to call sed twice as you can combine multiple commands with ;.
sed 's/-//; s/./-& /g'
Note, that you will have a space at the end which you might need to get rid of.
answered Dec 10 at 10:36
RoVo
2,558215
answered Dec 10 at 10:36
RoVo
2,558215
answered Dec 10 at 10:36
RoVo
2,558215
answered Dec 10 at 10:36
RoVo
2,558215
2,558215
add a comment |
add a comment |
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f487074%2fhow-can-i-insert-a-character-in-a-string%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
what about
sed 's/./-& /g'?– RoVo
Dec 10 at 10:19
@RoVo thanks it works
– Bret Joseph
Dec 10 at 10:32