What's wrong with this Latex equation? Missing $? and undefinded control sequence
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documentclass[10pt]{article}
usepackage[usenames]{color} % Farbunterstützung
usepackage{amssymb} % Mathe
usepackage{amsmath} % Mathe
usepackage[utf8]{inputenc} % Direkte Eingabe von Umlauten und anderen Diakritika
usepackage{braket}
(-1)^p=(-1)^{$P^{prime}$+$P^{primeprime}$}
math-mode equations
edited yesterday
Peter Mortensen
53336
asked yesterday
tqink
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up vote
3
down vote
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documentclass[10pt]{article}
usepackage[usenames]{color} % Farbunterstützung
usepackage{amssymb} % Mathe
usepackage{amsmath} % Mathe
usepackage[utf8]{inputenc} % Direkte Eingabe von Umlauten und anderen Diakritika
usepackage{braket}
(-1)^p=(-1)^{$P^{prime}$+$P^{primeprime}$}
math-mode equations
edited yesterday
Peter Mortensen
53336
asked yesterday
tqink
161
New contributor
tqink is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
4
Welcome! You cannot have(-1)^p=(-1)^outsidemathmode. Trydocumentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.
– marmot
yesterday
4
You're also missing both abegin{document}and anend{document}directive.
– Mico
yesterday
add a comment |
up vote
3
down vote
favorite
up vote
3
down vote
favorite
documentclass[10pt]{article}
usepackage[usenames]{color} % Farbunterstützung
usepackage{amssymb} % Mathe
usepackage{amsmath} % Mathe
usepackage[utf8]{inputenc} % Direkte Eingabe von Umlauten und anderen Diakritika
usepackage{braket}
(-1)^p=(-1)^{$P^{prime}$+$P^{primeprime}$}
math-mode equations
edited yesterday
Peter Mortensen
53336
asked yesterday
tqink
161
New contributor
tqink is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
documentclass[10pt]{article}
usepackage[usenames]{color} % Farbunterstützung
usepackage{amssymb} % Mathe
usepackage{amsmath} % Mathe
usepackage[utf8]{inputenc} % Direkte Eingabe von Umlauten und anderen Diakritika
usepackage{braket}
(-1)^p=(-1)^{$P^{prime}$+$P^{primeprime}$}
math-mode equations
math-mode equations
edited yesterday
Peter Mortensen
53336
asked yesterday
tqink
161
New contributor
tqink is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited yesterday
Peter Mortensen
53336
asked yesterday
tqink
161
New contributor
tqink is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited yesterday
Peter Mortensen
53336
edited yesterday
Peter Mortensen
53336
edited yesterday
Peter Mortensen
53336
53336
asked yesterday
tqink
161
New contributor
tqink is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
tqink
161
asked yesterday
tqink
161
161
New contributor
tqink is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
tqink is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
tqink is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
4
Welcome! You cannot have(-1)^p=(-1)^outsidemathmode. Trydocumentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.
– marmot
yesterday
4
You're also missing both abegin{document}and anend{document}directive.
– Mico
yesterday
add a comment |
4
Welcome! You cannot have(-1)^p=(-1)^outsidemathmode. Trydocumentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.
– marmot
yesterday
4
You're also missing both abegin{document}and anend{document}directive.
– Mico
yesterday
4
4
Welcome! You cannot have
(-1)^p=(-1)^ outside math mode. Try documentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.– marmot
yesterday
Welcome! You cannot have
(-1)^p=(-1)^ outside math mode. Try documentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.– marmot
yesterday
4
4
You're also missing both a
begin{document} and an end{document} directive.– Mico
yesterday
You're also missing both a
begin{document} and an end{document} directive.– Mico
yesterday
add a comment |
1 Answer
1
active
oldest
votes
up vote
6
down vote
I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)
documentclass{article}
begin{document}
$(-1)^p=(-1)^{(P'+P'')}$
end{document}
answered yesterday
Mico
271k30367755
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)
documentclass{article}
begin{document}
$(-1)^p=(-1)^{(P'+P'')}$
end{document}
answered yesterday
Mico
271k30367755
add a comment |
up vote
6
down vote
I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)
documentclass{article}
begin{document}
$(-1)^p=(-1)^{(P'+P'')}$
end{document}
answered yesterday
Mico
271k30367755
add a comment |
up vote
6
down vote
up vote
6
down vote
I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)
documentclass{article}
begin{document}
$(-1)^p=(-1)^{(P'+P'')}$
end{document}
answered yesterday
Mico
271k30367755
I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)
documentclass{article}
begin{document}
$(-1)^p=(-1)^{(P'+P'')}$
end{document}
answered yesterday
Mico
271k30367755
answered yesterday
Mico
271k30367755
answered yesterday
Mico
271k30367755
answered yesterday
Mico
271k30367755
271k30367755
add a comment |
add a comment |
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4
Welcome! You cannot have
(-1)^p=(-1)^outsidemathmode. Trydocumentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.– marmot
yesterday
4
You're also missing both a
begin{document}and anend{document}directive.– Mico
yesterday