Calculating Exponential Moving Average in Python
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7
down vote
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I'm in the process of creating a forex trading algorithm and wanted to try my shot at calculating EMA (Exponential Moving Averages). My results appear to be correct (compared to the calculations I did by hand) so I believe the following method works, but just wanted to get an extra set of eyes to makes sure i'm not missing anything.
Note that this just returns the EMA for the latest price, it doesn't return an array of EMA's as that isn't what I need for my application.
I am using this link as a reference: Exponential Moving Average
class Indicators:
def sma(self, data, window):
"""
Calculates Simple Moving Average
http://fxtrade.oanda.com/learn/forex-indicators/simple-moving-average
"""
if len(data) < window:
return None
return sum(data[-window:]) / float(window)
def ema(self, data, window, position=None, previous_ema=None):
"""
Calculates Exponential Moving Average
http://fxtrade.oanda.com/learn/forex-indicators/exponential-moving-average
"""
if len(data) < window + 2:
return None
c = 2 / float(window + 1)
if not previous_ema:
return self.ema(data, window, window, self.sma(data[-window*2 + 1:-window + 1], window))
else:
current_ema = (c * data[-position]) + ((1 - c) * previous_ema)
if position > 0:
return self.ema(data, window, position - 1, current_ema)
return previous_ema
# Sample close prices for GBP_USD currency pair on the 2 hour timeframe
close_prices = [1.682555, 1.682545, 1.682535, 1.682655, 1.682455, 1.682685, 1.68205, 1.683245, 1.68405, 1.68401, 1.68506, 1.685825, 1.685955, 1.686595, 1.686325, 1.686375, 1.68701, 1.684995, 1.687245, 1.686135, 1.686205, 1.68724, 1.68753, 1.687775, 1.688245, 1.687745, 1.68699, 1.687285, 1.686325, 1.686295, 1.683945, 1.683035, 1.68401, 1.68327, 1.685185, 1.684755, 1.685265, 1.685325, 1.68625, 1.685645, 1.684355, 1.68387, 1.68413, 1.68416, 1.683425, 1.68481, 1.683245, 1.683645, 1.68325, 1.682745, 1.680385, 1.680655, 1.680875, 1.679995, 1.680445, 1.68064, 1.67937, 1.677735, 1.67769, 1.67777, 1.677525, 1.677435, 1.67766, 1.677835, 1.678005, 1.67823, 1.67902, 1.678605, 1.678425, 1.67876, 1.678555, 1.678505, 1.679085, 1.678755, 1.678125, 1.677495, 1.67677, 1.676205, 1.67716, 1.67741, 1.677135, 1.679295, 1.68054, 1.68143, 1.68115, 1.68111, 1.68055, 1.680495, 1.680565, 1.681375, 1.68244, 1.673395, 1.670885, 1.67156, 1.669525, 1.66906, 1.66903, 1.668935, 1.668805, 1.667895, 1.667905, 1.668485, 1.666345, 1.66832, 1.668005, 1.668615, 1.669305, 1.668415, 1.66891, 1.66843, 1.66855, 1.66834, 1.668725, 1.66952, 1.668075, 1.66859, 1.669, 1.669685, 1.668575, 1.66909, 1.66957, 1.669375, 1.671655, 1.67186, 1.67244, 1.6729, 1.672965, 1.673405, 1.67284, 1.67256, 1.67216, 1.67193, 1.673265, 1.67295, 1.672705, 1.67224, 1.67221, 1.67222, 1.67254, 1.670105, 1.66501, 1.663845, 1.66201, 1.661935, 1.661725, 1.66189, 1.661605, 1.661925, 1.66215, 1.66049, 1.660185, 1.66233, 1.66374, 1.66491, 1.665195, 1.663225, 1.66267, 1.65927, 1.659415, 1.65998, 1.6583, 1.656825, 1.65741, 1.659025, 1.658355, 1.659355, 1.65871, 1.65887, 1.658595, 1.65768, 1.657965, 1.657855, 1.657415, 1.658125, 1.65816, 1.659125, 1.658245, 1.65773, 1.658585, 1.65732, 1.657825, 1.65731, 1.65725, 1.65433, 1.654875, 1.65508, 1.656205, 1.656185, 1.6567, 1.658865, 1.658805, 1.65879, 1.6584, 1.65806, 1.658145, 1.65706, 1.656925, 1.65885, 1.65917, 1.659, 1.65794, 1.65797, 1.65711, 1.658675, 1.656915, 1.65474, 1.65455, 1.654135, 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python mathematics
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up vote
7
down vote
favorite
I'm in the process of creating a forex trading algorithm and wanted to try my shot at calculating EMA (Exponential Moving Averages). My results appear to be correct (compared to the calculations I did by hand) so I believe the following method works, but just wanted to get an extra set of eyes to makes sure i'm not missing anything.
Note that this just returns the EMA for the latest price, it doesn't return an array of EMA's as that isn't what I need for my application.
I am using this link as a reference: Exponential Moving Average
class Indicators:
def sma(self, data, window):
"""
Calculates Simple Moving Average
http://fxtrade.oanda.com/learn/forex-indicators/simple-moving-average
"""
if len(data) < window:
return None
return sum(data[-window:]) / float(window)
def ema(self, data, window, position=None, previous_ema=None):
"""
Calculates Exponential Moving Average
http://fxtrade.oanda.com/learn/forex-indicators/exponential-moving-average
"""
if len(data) < window + 2:
return None
c = 2 / float(window + 1)
if not previous_ema:
return self.ema(data, window, window, self.sma(data[-window*2 + 1:-window + 1], window))
else:
current_ema = (c * data[-position]) + ((1 - c) * previous_ema)
if position > 0:
return self.ema(data, window, position - 1, current_ema)
return previous_ema
# Sample close prices for GBP_USD currency pair on the 2 hour timeframe
close_prices = [1.682555, 1.682545, 1.682535, 1.682655, 1.682455, 1.682685, 1.68205, 1.683245, 1.68405, 1.68401, 1.68506, 1.685825, 1.685955, 1.686595, 1.686325, 1.686375, 1.68701, 1.684995, 1.687245, 1.686135, 1.686205, 1.68724, 1.68753, 1.687775, 1.688245, 1.687745, 1.68699, 1.687285, 1.686325, 1.686295, 1.683945, 1.683035, 1.68401, 1.68327, 1.685185, 1.684755, 1.685265, 1.685325, 1.68625, 1.685645, 1.684355, 1.68387, 1.68413, 1.68416, 1.683425, 1.68481, 1.683245, 1.683645, 1.68325, 1.682745, 1.680385, 1.680655, 1.680875, 1.679995, 1.680445, 1.68064, 1.67937, 1.677735, 1.67769, 1.67777, 1.677525, 1.677435, 1.67766, 1.677835, 1.678005, 1.67823, 1.67902, 1.678605, 1.678425, 1.67876, 1.678555, 1.678505, 1.679085, 1.678755, 1.678125, 1.677495, 1.67677, 1.676205, 1.67716, 1.67741, 1.677135, 1.679295, 1.68054, 1.68143, 1.68115, 1.68111, 1.68055, 1.680495, 1.680565, 1.681375, 1.68244, 1.673395, 1.670885, 1.67156, 1.669525, 1.66906, 1.66903, 1.668935, 1.668805, 1.667895, 1.667905, 1.668485, 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python mathematics
Welcome to CodeReview.SE ! Would you be able to provide dummy data so that one can give your code a try before reviewing it ?
– Josay
Nov 24 '14 at 17:55
Hi Josay, I've added a sample list of data for you if you'd like to test.
– ChrisC
Nov 25 '14 at 19:10
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I'm in the process of creating a forex trading algorithm and wanted to try my shot at calculating EMA (Exponential Moving Averages). My results appear to be correct (compared to the calculations I did by hand) so I believe the following method works, but just wanted to get an extra set of eyes to makes sure i'm not missing anything.
Note that this just returns the EMA for the latest price, it doesn't return an array of EMA's as that isn't what I need for my application.
I am using this link as a reference: Exponential Moving Average
class Indicators:
def sma(self, data, window):
"""
Calculates Simple Moving Average
http://fxtrade.oanda.com/learn/forex-indicators/simple-moving-average
"""
if len(data) < window:
return None
return sum(data[-window:]) / float(window)
def ema(self, data, window, position=None, previous_ema=None):
"""
Calculates Exponential Moving Average
http://fxtrade.oanda.com/learn/forex-indicators/exponential-moving-average
"""
if len(data) < window + 2:
return None
c = 2 / float(window + 1)
if not previous_ema:
return self.ema(data, window, window, self.sma(data[-window*2 + 1:-window + 1], window))
else:
current_ema = (c * data[-position]) + ((1 - c) * previous_ema)
if position > 0:
return self.ema(data, window, position - 1, current_ema)
return previous_ema
# Sample close prices for GBP_USD currency pair on the 2 hour timeframe
close_prices = [1.682555, 1.682545, 1.682535, 1.682655, 1.682455, 1.682685, 1.68205, 1.683245, 1.68405, 1.68401, 1.68506, 1.685825, 1.685955, 1.686595, 1.686325, 1.686375, 1.68701, 1.684995, 1.687245, 1.686135, 1.686205, 1.68724, 1.68753, 1.687775, 1.688245, 1.687745, 1.68699, 1.687285, 1.686325, 1.686295, 1.683945, 1.683035, 1.68401, 1.68327, 1.685185, 1.684755, 1.685265, 1.685325, 1.68625, 1.685645, 1.684355, 1.68387, 1.68413, 1.68416, 1.683425, 1.68481, 1.683245, 1.683645, 1.68325, 1.682745, 1.680385, 1.680655, 1.680875, 1.679995, 1.680445, 1.68064, 1.67937, 1.677735, 1.67769, 1.67777, 1.677525, 1.677435, 1.67766, 1.677835, 1.678005, 1.67823, 1.67902, 1.678605, 1.678425, 1.67876, 1.678555, 1.678505, 1.679085, 1.678755, 1.678125, 1.677495, 1.67677, 1.676205, 1.67716, 1.67741, 1.677135, 1.679295, 1.68054, 1.68143, 1.68115, 1.68111, 1.68055, 1.680495, 1.680565, 1.681375, 1.68244, 1.673395, 1.670885, 1.67156, 1.669525, 1.66906, 1.66903, 1.668935, 1.668805, 1.667895, 1.667905, 1.668485, 1.666345, 1.66832, 1.668005, 1.668615, 1.669305, 1.668415, 1.66891, 1.66843, 1.66855, 1.66834, 1.668725, 1.66952, 1.668075, 1.66859, 1.669, 1.669685, 1.668575, 1.66909, 1.66957, 1.669375, 1.671655, 1.67186, 1.67244, 1.6729, 1.672965, 1.673405, 1.67284, 1.67256, 1.67216, 1.67193, 1.673265, 1.67295, 1.672705, 1.67224, 1.67221, 1.67222, 1.67254, 1.670105, 1.66501, 1.663845, 1.66201, 1.661935, 1.661725, 1.66189, 1.661605, 1.661925, 1.66215, 1.66049, 1.660185, 1.66233, 1.66374, 1.66491, 1.665195, 1.663225, 1.66267, 1.65927, 1.659415, 1.65998, 1.6583, 1.656825, 1.65741, 1.659025, 1.658355, 1.659355, 1.65871, 1.65887, 1.658595, 1.65768, 1.657965, 1.657855, 1.657415, 1.658125, 1.65816, 1.659125, 1.658245, 1.65773, 1.658585, 1.65732, 1.657825, 1.65731, 1.65725, 1.65433, 1.654875, 1.65508, 1.656205, 1.656185, 1.6567, 1.658865, 1.658805, 1.65879, 1.6584, 1.65806, 1.658145, 1.65706, 1.656925, 1.65885, 1.65917, 1.659, 1.65794, 1.65797, 1.65711, 1.658675, 1.656915, 1.65474, 1.65455, 1.654135, 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python mathematics
I'm in the process of creating a forex trading algorithm and wanted to try my shot at calculating EMA (Exponential Moving Averages). My results appear to be correct (compared to the calculations I did by hand) so I believe the following method works, but just wanted to get an extra set of eyes to makes sure i'm not missing anything.
Note that this just returns the EMA for the latest price, it doesn't return an array of EMA's as that isn't what I need for my application.
I am using this link as a reference: Exponential Moving Average
class Indicators:
def sma(self, data, window):
"""
Calculates Simple Moving Average
http://fxtrade.oanda.com/learn/forex-indicators/simple-moving-average
"""
if len(data) < window:
return None
return sum(data[-window:]) / float(window)
def ema(self, data, window, position=None, previous_ema=None):
"""
Calculates Exponential Moving Average
http://fxtrade.oanda.com/learn/forex-indicators/exponential-moving-average
"""
if len(data) < window + 2:
return None
c = 2 / float(window + 1)
if not previous_ema:
return self.ema(data, window, window, self.sma(data[-window*2 + 1:-window + 1], window))
else:
current_ema = (c * data[-position]) + ((1 - c) * previous_ema)
if position > 0:
return self.ema(data, window, position - 1, current_ema)
return previous_ema
# Sample close prices for GBP_USD currency pair on the 2 hour timeframe
close_prices = [1.682555, 1.682545, 1.682535, 1.682655, 1.682455, 1.682685, 1.68205, 1.683245, 1.68405, 1.68401, 1.68506, 1.685825, 1.685955, 1.686595, 1.686325, 1.686375, 1.68701, 1.684995, 1.687245, 1.686135, 1.686205, 1.68724, 1.68753, 1.687775, 1.688245, 1.687745, 1.68699, 1.687285, 1.686325, 1.686295, 1.683945, 1.683035, 1.68401, 1.68327, 1.685185, 1.684755, 1.685265, 1.685325, 1.68625, 1.685645, 1.684355, 1.68387, 1.68413, 1.68416, 1.683425, 1.68481, 1.683245, 1.683645, 1.68325, 1.682745, 1.680385, 1.680655, 1.680875, 1.679995, 1.680445, 1.68064, 1.67937, 1.677735, 1.67769, 1.67777, 1.677525, 1.677435, 1.67766, 1.677835, 1.678005, 1.67823, 1.67902, 1.678605, 1.678425, 1.67876, 1.678555, 1.678505, 1.679085, 1.678755, 1.678125, 1.677495, 1.67677, 1.676205, 1.67716, 1.67741, 1.677135, 1.679295, 1.68054, 1.68143, 1.68115, 1.68111, 1.68055, 1.680495, 1.680565, 1.681375, 1.68244, 1.673395, 1.670885, 1.67156, 1.669525, 1.66906, 1.66903, 1.668935, 1.668805, 1.667895, 1.667905, 1.668485, 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python mathematics
python mathematics
edited Nov 25 '14 at 19:10
asked Nov 21 '14 at 14:37
ChrisC
138115
138115
Welcome to CodeReview.SE ! Would you be able to provide dummy data so that one can give your code a try before reviewing it ?
– Josay
Nov 24 '14 at 17:55
Hi Josay, I've added a sample list of data for you if you'd like to test.
– ChrisC
Nov 25 '14 at 19:10
add a comment |
Welcome to CodeReview.SE ! Would you be able to provide dummy data so that one can give your code a try before reviewing it ?
– Josay
Nov 24 '14 at 17:55
Hi Josay, I've added a sample list of data for you if you'd like to test.
– ChrisC
Nov 25 '14 at 19:10
Welcome to CodeReview.SE ! Would you be able to provide dummy data so that one can give your code a try before reviewing it ?
– Josay
Nov 24 '14 at 17:55
Welcome to CodeReview.SE ! Would you be able to provide dummy data so that one can give your code a try before reviewing it ?
– Josay
Nov 24 '14 at 17:55
Hi Josay, I've added a sample list of data for you if you'd like to test.
– ChrisC
Nov 25 '14 at 19:10
Hi Josay, I've added a sample list of data for you if you'd like to test.
– ChrisC
Nov 25 '14 at 19:10
add a comment |
3 Answers
3
active
oldest
votes
up vote
2
down vote
accepted
- Recursion is a good tool for the right job, but here it is used to accomplish simple looping. As such the code...
- is more difficult to read and reason about.
- is slower because much of the code in
emaonly needs to run once. - will fail with large enough value of
windowdue to overflowing Python's call stack.
- Please document at least the parameters of each function, eg. that
windowis the length of the window, and thatpositioncounts backwards from the end ofdata. (In fact things would be clearer ifpositionwere a normal forward index intodata) - Raise an exception when you find a parameter has an invalid value. Returning
Noneinstead will only cause a more confusing exception later. In fact, if I tryIndicators().ema(close_prices, 600)I get infinite recursion becausesmareturnsNone, which makesemacallsmaover and over again. - The previous point also reveals that
if len(data) < window + 2is not the right validity check. - The
+ 1indata[-window*2 + 1:-window + 1]don't seem correct to me. I suppose you wantdata[-window*2:-window] - The statement
return previous_emais in an odd place because at that point you have calculated a newcurrent_ema. This is the base case of the recursion, and it is customary to handle the base case first.
My proposal for ema:
def ema(self, data, window):
if len(data) < 2 * window:
raise ValueError("data is too short")
c = 2.0 / (window + 1)
current_ema = self.sma(data[-window*2:-window], window)
for value in data[-window:]:
current_ema = (c * value) + ((1 - c) * current_ema)
return current_ema
add a comment |
up vote
4
down vote
Here's a short implementation:
https://pythonprogramming.net/advanced-matplotlib-graphing-charting-tutorial/
def ExpMovingAverage(values, window):
""" Numpy implementation of EMA
"""
weights = np.exp(np.linspace(-1., 0., window))
weights /= weights.sum()
a = np.convolve(values, weights, mode='full')[:len(values)]
a[:window] = a[window]
return a
Note that it uses Numpy. I performed some tests and its answers match talib - that's another good option if you want to (and can) leverage C libraries for speed.
a[window]raises an error iflen(values) ==windows
– gies0r
Oct 14 at 17:27
add a comment |
up vote
1
down vote
Pretty shallow review :
You don't need to write a class for what you are doing (and I suggest you have a look at this video). Your class does not encapsulate any data and you just use it to have your functions in a the same entity. I guess things would easier to understand if you were to define classmethod to make it obvious that you won't really rely on any instance whatsoever. However, an even better option would be to just define functions in a indicator module.
Thanks for the suggestions! I actually did have them as classmethods and debated going back and forth between even using a class or just defining functions in an indicator module (which I will now do).
– ChrisC
Nov 25 '14 at 19:12
Just watched the video too, great stuff.
– ChrisC
Nov 25 '14 at 19:43
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
- Recursion is a good tool for the right job, but here it is used to accomplish simple looping. As such the code...
- is more difficult to read and reason about.
- is slower because much of the code in
emaonly needs to run once. - will fail with large enough value of
windowdue to overflowing Python's call stack.
- Please document at least the parameters of each function, eg. that
windowis the length of the window, and thatpositioncounts backwards from the end ofdata. (In fact things would be clearer ifpositionwere a normal forward index intodata) - Raise an exception when you find a parameter has an invalid value. Returning
Noneinstead will only cause a more confusing exception later. In fact, if I tryIndicators().ema(close_prices, 600)I get infinite recursion becausesmareturnsNone, which makesemacallsmaover and over again. - The previous point also reveals that
if len(data) < window + 2is not the right validity check. - The
+ 1indata[-window*2 + 1:-window + 1]don't seem correct to me. I suppose you wantdata[-window*2:-window] - The statement
return previous_emais in an odd place because at that point you have calculated a newcurrent_ema. This is the base case of the recursion, and it is customary to handle the base case first.
My proposal for ema:
def ema(self, data, window):
if len(data) < 2 * window:
raise ValueError("data is too short")
c = 2.0 / (window + 1)
current_ema = self.sma(data[-window*2:-window], window)
for value in data[-window:]:
current_ema = (c * value) + ((1 - c) * current_ema)
return current_ema
add a comment |
up vote
2
down vote
accepted
- Recursion is a good tool for the right job, but here it is used to accomplish simple looping. As such the code...
- is more difficult to read and reason about.
- is slower because much of the code in
emaonly needs to run once. - will fail with large enough value of
windowdue to overflowing Python's call stack.
- Please document at least the parameters of each function, eg. that
windowis the length of the window, and thatpositioncounts backwards from the end ofdata. (In fact things would be clearer ifpositionwere a normal forward index intodata) - Raise an exception when you find a parameter has an invalid value. Returning
Noneinstead will only cause a more confusing exception later. In fact, if I tryIndicators().ema(close_prices, 600)I get infinite recursion becausesmareturnsNone, which makesemacallsmaover and over again. - The previous point also reveals that
if len(data) < window + 2is not the right validity check. - The
+ 1indata[-window*2 + 1:-window + 1]don't seem correct to me. I suppose you wantdata[-window*2:-window] - The statement
return previous_emais in an odd place because at that point you have calculated a newcurrent_ema. This is the base case of the recursion, and it is customary to handle the base case first.
My proposal for ema:
def ema(self, data, window):
if len(data) < 2 * window:
raise ValueError("data is too short")
c = 2.0 / (window + 1)
current_ema = self.sma(data[-window*2:-window], window)
for value in data[-window:]:
current_ema = (c * value) + ((1 - c) * current_ema)
return current_ema
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
- Recursion is a good tool for the right job, but here it is used to accomplish simple looping. As such the code...
- is more difficult to read and reason about.
- is slower because much of the code in
emaonly needs to run once. - will fail with large enough value of
windowdue to overflowing Python's call stack.
- Please document at least the parameters of each function, eg. that
windowis the length of the window, and thatpositioncounts backwards from the end ofdata. (In fact things would be clearer ifpositionwere a normal forward index intodata) - Raise an exception when you find a parameter has an invalid value. Returning
Noneinstead will only cause a more confusing exception later. In fact, if I tryIndicators().ema(close_prices, 600)I get infinite recursion becausesmareturnsNone, which makesemacallsmaover and over again. - The previous point also reveals that
if len(data) < window + 2is not the right validity check. - The
+ 1indata[-window*2 + 1:-window + 1]don't seem correct to me. I suppose you wantdata[-window*2:-window] - The statement
return previous_emais in an odd place because at that point you have calculated a newcurrent_ema. This is the base case of the recursion, and it is customary to handle the base case first.
My proposal for ema:
def ema(self, data, window):
if len(data) < 2 * window:
raise ValueError("data is too short")
c = 2.0 / (window + 1)
current_ema = self.sma(data[-window*2:-window], window)
for value in data[-window:]:
current_ema = (c * value) + ((1 - c) * current_ema)
return current_ema
- Recursion is a good tool for the right job, but here it is used to accomplish simple looping. As such the code...
- is more difficult to read and reason about.
- is slower because much of the code in
emaonly needs to run once. - will fail with large enough value of
windowdue to overflowing Python's call stack.
- Please document at least the parameters of each function, eg. that
windowis the length of the window, and thatpositioncounts backwards from the end ofdata. (In fact things would be clearer ifpositionwere a normal forward index intodata) - Raise an exception when you find a parameter has an invalid value. Returning
Noneinstead will only cause a more confusing exception later. In fact, if I tryIndicators().ema(close_prices, 600)I get infinite recursion becausesmareturnsNone, which makesemacallsmaover and over again. - The previous point also reveals that
if len(data) < window + 2is not the right validity check. - The
+ 1indata[-window*2 + 1:-window + 1]don't seem correct to me. I suppose you wantdata[-window*2:-window] - The statement
return previous_emais in an odd place because at that point you have calculated a newcurrent_ema. This is the base case of the recursion, and it is customary to handle the base case first.
My proposal for ema:
def ema(self, data, window):
if len(data) < 2 * window:
raise ValueError("data is too short")
c = 2.0 / (window + 1)
current_ema = self.sma(data[-window*2:-window], window)
for value in data[-window:]:
current_ema = (c * value) + ((1 - c) * current_ema)
return current_ema
answered Nov 26 '14 at 18:56
Janne Karila
9,6931430
9,6931430
add a comment |
add a comment |
up vote
4
down vote
Here's a short implementation:
https://pythonprogramming.net/advanced-matplotlib-graphing-charting-tutorial/
def ExpMovingAverage(values, window):
""" Numpy implementation of EMA
"""
weights = np.exp(np.linspace(-1., 0., window))
weights /= weights.sum()
a = np.convolve(values, weights, mode='full')[:len(values)]
a[:window] = a[window]
return a
Note that it uses Numpy. I performed some tests and its answers match talib - that's another good option if you want to (and can) leverage C libraries for speed.
a[window]raises an error iflen(values) ==windows
– gies0r
Oct 14 at 17:27
add a comment |
up vote
4
down vote
Here's a short implementation:
https://pythonprogramming.net/advanced-matplotlib-graphing-charting-tutorial/
def ExpMovingAverage(values, window):
""" Numpy implementation of EMA
"""
weights = np.exp(np.linspace(-1., 0., window))
weights /= weights.sum()
a = np.convolve(values, weights, mode='full')[:len(values)]
a[:window] = a[window]
return a
Note that it uses Numpy. I performed some tests and its answers match talib - that's another good option if you want to (and can) leverage C libraries for speed.
a[window]raises an error iflen(values) ==windows
– gies0r
Oct 14 at 17:27
add a comment |
up vote
4
down vote
up vote
4
down vote
Here's a short implementation:
https://pythonprogramming.net/advanced-matplotlib-graphing-charting-tutorial/
def ExpMovingAverage(values, window):
""" Numpy implementation of EMA
"""
weights = np.exp(np.linspace(-1., 0., window))
weights /= weights.sum()
a = np.convolve(values, weights, mode='full')[:len(values)]
a[:window] = a[window]
return a
Note that it uses Numpy. I performed some tests and its answers match talib - that's another good option if you want to (and can) leverage C libraries for speed.
Here's a short implementation:
https://pythonprogramming.net/advanced-matplotlib-graphing-charting-tutorial/
def ExpMovingAverage(values, window):
""" Numpy implementation of EMA
"""
weights = np.exp(np.linspace(-1., 0., window))
weights /= weights.sum()
a = np.convolve(values, weights, mode='full')[:len(values)]
a[:window] = a[window]
return a
Note that it uses Numpy. I performed some tests and its answers match talib - that's another good option if you want to (and can) leverage C libraries for speed.
answered Jun 26 '17 at 5:06
hamx0r
1413
1413
a[window]raises an error iflen(values) ==windows
– gies0r
Oct 14 at 17:27
add a comment |
a[window]raises an error iflen(values) ==windows
– gies0r
Oct 14 at 17:27
a[window] raises an error if len(values) ==windows– gies0r
Oct 14 at 17:27
a[window] raises an error if len(values) ==windows– gies0r
Oct 14 at 17:27
add a comment |
up vote
1
down vote
Pretty shallow review :
You don't need to write a class for what you are doing (and I suggest you have a look at this video). Your class does not encapsulate any data and you just use it to have your functions in a the same entity. I guess things would easier to understand if you were to define classmethod to make it obvious that you won't really rely on any instance whatsoever. However, an even better option would be to just define functions in a indicator module.
Thanks for the suggestions! I actually did have them as classmethods and debated going back and forth between even using a class or just defining functions in an indicator module (which I will now do).
– ChrisC
Nov 25 '14 at 19:12
Just watched the video too, great stuff.
– ChrisC
Nov 25 '14 at 19:43
add a comment |
up vote
1
down vote
Pretty shallow review :
You don't need to write a class for what you are doing (and I suggest you have a look at this video). Your class does not encapsulate any data and you just use it to have your functions in a the same entity. I guess things would easier to understand if you were to define classmethod to make it obvious that you won't really rely on any instance whatsoever. However, an even better option would be to just define functions in a indicator module.
Thanks for the suggestions! I actually did have them as classmethods and debated going back and forth between even using a class or just defining functions in an indicator module (which I will now do).
– ChrisC
Nov 25 '14 at 19:12
Just watched the video too, great stuff.
– ChrisC
Nov 25 '14 at 19:43
add a comment |
up vote
1
down vote
up vote
1
down vote
Pretty shallow review :
You don't need to write a class for what you are doing (and I suggest you have a look at this video). Your class does not encapsulate any data and you just use it to have your functions in a the same entity. I guess things would easier to understand if you were to define classmethod to make it obvious that you won't really rely on any instance whatsoever. However, an even better option would be to just define functions in a indicator module.
Pretty shallow review :
You don't need to write a class for what you are doing (and I suggest you have a look at this video). Your class does not encapsulate any data and you just use it to have your functions in a the same entity. I guess things would easier to understand if you were to define classmethod to make it obvious that you won't really rely on any instance whatsoever. However, an even better option would be to just define functions in a indicator module.
answered Nov 24 '14 at 18:04
Josay
24.6k13783
24.6k13783
Thanks for the suggestions! I actually did have them as classmethods and debated going back and forth between even using a class or just defining functions in an indicator module (which I will now do).
– ChrisC
Nov 25 '14 at 19:12
Just watched the video too, great stuff.
– ChrisC
Nov 25 '14 at 19:43
add a comment |
Thanks for the suggestions! I actually did have them as classmethods and debated going back and forth between even using a class or just defining functions in an indicator module (which I will now do).
– ChrisC
Nov 25 '14 at 19:12
Just watched the video too, great stuff.
– ChrisC
Nov 25 '14 at 19:43
Thanks for the suggestions! I actually did have them as classmethods and debated going back and forth between even using a class or just defining functions in an indicator module (which I will now do).
– ChrisC
Nov 25 '14 at 19:12
Thanks for the suggestions! I actually did have them as classmethods and debated going back and forth between even using a class or just defining functions in an indicator module (which I will now do).
– ChrisC
Nov 25 '14 at 19:12
Just watched the video too, great stuff.
– ChrisC
Nov 25 '14 at 19:43
Just watched the video too, great stuff.
– ChrisC
Nov 25 '14 at 19:43
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Welcome to CodeReview.SE ! Would you be able to provide dummy data so that one can give your code a try before reviewing it ?
– Josay
Nov 24 '14 at 17:55
Hi Josay, I've added a sample list of data for you if you'd like to test.
– ChrisC
Nov 25 '14 at 19:10