How to properly align Tikz pictures in Latex fraction environment
3
How to properly align Tikz pictures in Latex environment to get the following picture?
My trial code does not compile,
documentclass[preview]{standalone}
usepackage{tikz}
usepackage{amsmath}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}
defL{1.0}
matrix[column sep=.1cm, row sep=2mm]
{
draw (0,0) to[bend left] (L,0) to[bend left] (0,0);
&
node at (0,0) {$-$};
&
draw[dashed] (0,0) -- (L,0);
draw[xshift=L cm] (0,0) to[bend left] (L,0) to[bend left] (0,0); \
};
end{tikzpicture}
}
end{equation*}
end{document}
tikz-pgf amsmath fractions alignment
asked Dec 16 at 2:59
Kevin Powell
36016
add a comment |
3
How to properly align Tikz pictures in Latex environment to get the following picture?
My trial code does not compile,
documentclass[preview]{standalone}
usepackage{tikz}
usepackage{amsmath}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}
defL{1.0}
matrix[column sep=.1cm, row sep=2mm]
{
draw (0,0) to[bend left] (L,0) to[bend left] (0,0);
&
node at (0,0) {$-$};
&
draw[dashed] (0,0) -- (L,0);
draw[xshift=L cm] (0,0) to[bend left] (L,0) to[bend left] (0,0); \
};
end{tikzpicture}
}
end{equation*}
end{document}
tikz-pgf amsmath fractions alignment
asked Dec 16 at 2:59
Kevin Powell
36016
please, extend your code fragment to complete small document ...
– Zarko
Dec 16 at 3:05
add a comment |
3
3
3
1
How to properly align Tikz pictures in Latex environment to get the following picture?
My trial code does not compile,
documentclass[preview]{standalone}
usepackage{tikz}
usepackage{amsmath}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}
defL{1.0}
matrix[column sep=.1cm, row sep=2mm]
{
draw (0,0) to[bend left] (L,0) to[bend left] (0,0);
&
node at (0,0) {$-$};
&
draw[dashed] (0,0) -- (L,0);
draw[xshift=L cm] (0,0) to[bend left] (L,0) to[bend left] (0,0); \
};
end{tikzpicture}
}
end{equation*}
end{document}
tikz-pgf amsmath fractions alignment
asked Dec 16 at 2:59
Kevin Powell
36016
How to properly align Tikz pictures in Latex environment to get the following picture?
My trial code does not compile,
documentclass[preview]{standalone}
usepackage{tikz}
usepackage{amsmath}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}
defL{1.0}
matrix[column sep=.1cm, row sep=2mm]
{
draw (0,0) to[bend left] (L,0) to[bend left] (0,0);
&
node at (0,0) {$-$};
&
draw[dashed] (0,0) -- (L,0);
draw[xshift=L cm] (0,0) to[bend left] (L,0) to[bend left] (0,0); \
};
end{tikzpicture}
}
end{equation*}
end{document}
tikz-pgf amsmath fractions alignment
tikz-pgf amsmath fractions alignment
asked Dec 16 at 2:59
Kevin Powell
36016
asked Dec 16 at 2:59
Kevin Powell
36016
edited Dec 16 at 5:49
asked Dec 16 at 2:59
Kevin Powell
36016
asked Dec 16 at 2:59
Kevin Powell
36016
asked Dec 16 at 2:59
Kevin Powell
36016
36016
please, extend your code fragment to complete small document ...
– Zarko
Dec 16 at 3:05
add a comment |
please, extend your code fragment to complete small document ...
– Zarko
Dec 16 at 3:05
please, extend your code fragment to complete small document ...
– Zarko
Dec 16 at 3:05
please, extend your code fragment to complete small document ...
– Zarko
Dec 16 at 3:05
add a comment |
2 Answers
2
active
oldest
votes
3
Generally you can control the vertical alignment with the baseline option.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
-
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
draw[dashed](0,0) -- (-1,0);
end{tikzpicture}
}
end{equation*}
end{document}
I don't know what these objects represent, so you may want to use another baseline.
Note that you can use a TikZ matrix:
documentclass{article}
usepackage{tikz}
usepackage{amsmath}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline]
defL{1.0}
matrix[column sep=.1cm, row sep=2mm,ampersand replacement=&]
{
draw (0,0) to[bend left] (L,0) to[bend left] (0,0);
&
node at (0,0) {$-$};
&
draw[dashed] (0,0) -- (L,0);
draw[xshift=L cm] (0,0) to[bend left] (L,0) to[bend left] (0,0); \
};
end{tikzpicture}
}
end{equation*}
end{document}
answered Dec 16 at 3:22
marmot
86.5k499184
Thanks! It seems that the more versatilematrixintikzpicturedoes not work withfrac. Althoughbaselineis one answer to this figure, it will become difficult to deal with multiple rows of figure in the denominator.
– Kevin Powell
Dec 16 at 6:14
@KevinPowell You can definitely use a matrix, just addampersand replacement=&and replace&by&.
– marmot
Dec 16 at 7:42
That's quite neat! Why[baseline]option centers the figure in the numerator? It is black magic for me.
– Kevin Powell
Dec 17 at 7:42
add a comment |
4
documentclass{article}
usepackage{tikz}
begin{document}
[
A = frac{tikz[baseline=1pt]{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0);}}
{tikz{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0)
( 0.5,0) to[bend left] ( 1.5,0) to[bend left] ( 0.5,0);
draw[dashed, shorten >=1mm, shorten <=1mm] (-0.5,0) -- (0.5,0);}
}
]
end{document}
answered Dec 16 at 3:32
Zarko
120k865156
How is that different from my answer except that you defineMbut do not use it? The only thing apart from the unused definition I can see is the use ofbaseline, which is precisely what I am using.
– marmot
Dec 16 at 3:38
@marmot the denominator is different. I think there's an error here, because the minus is missing.
– CarLaTeX
Dec 16 at 4:04
2
I would create apicfor the shapes, and suggest to use dots instead of dashes, which could be confused with the minus (@marmot, too).
– CarLaTeX
Dec 16 at 4:43
@CarLaTeX That's a brilliant idea!
– Kevin Powell
Dec 16 at 6:10
@KevinPowell Thank you :)
– CarLaTeX
Dec 16 at 6:54
|
show 1 more comment
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
Generally you can control the vertical alignment with the baseline option.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
-
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
draw[dashed](0,0) -- (-1,0);
end{tikzpicture}
}
end{equation*}
end{document}
I don't know what these objects represent, so you may want to use another baseline.
Note that you can use a TikZ matrix:
documentclass{article}
usepackage{tikz}
usepackage{amsmath}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline]
defL{1.0}
matrix[column sep=.1cm, row sep=2mm,ampersand replacement=&]
{
draw (0,0) to[bend left] (L,0) to[bend left] (0,0);
&
node at (0,0) {$-$};
&
draw[dashed] (0,0) -- (L,0);
draw[xshift=L cm] (0,0) to[bend left] (L,0) to[bend left] (0,0); \
};
end{tikzpicture}
}
end{equation*}
end{document}
answered Dec 16 at 3:22
marmot
86.5k499184
Thanks! It seems that the more versatilematrixintikzpicturedoes not work withfrac. Althoughbaselineis one answer to this figure, it will become difficult to deal with multiple rows of figure in the denominator.
– Kevin Powell
Dec 16 at 6:14
@KevinPowell You can definitely use a matrix, just addampersand replacement=&and replace&by&.
– marmot
Dec 16 at 7:42
That's quite neat! Why[baseline]option centers the figure in the numerator? It is black magic for me.
– Kevin Powell
Dec 17 at 7:42
add a comment |
3
Generally you can control the vertical alignment with the baseline option.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
-
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
draw[dashed](0,0) -- (-1,0);
end{tikzpicture}
}
end{equation*}
end{document}
I don't know what these objects represent, so you may want to use another baseline.
Note that you can use a TikZ matrix:
documentclass{article}
usepackage{tikz}
usepackage{amsmath}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline]
defL{1.0}
matrix[column sep=.1cm, row sep=2mm,ampersand replacement=&]
{
draw (0,0) to[bend left] (L,0) to[bend left] (0,0);
&
node at (0,0) {$-$};
&
draw[dashed] (0,0) -- (L,0);
draw[xshift=L cm] (0,0) to[bend left] (L,0) to[bend left] (0,0); \
};
end{tikzpicture}
}
end{equation*}
end{document}
answered Dec 16 at 3:22
marmot
86.5k499184
Thanks! It seems that the more versatilematrixintikzpicturedoes not work withfrac. Althoughbaselineis one answer to this figure, it will become difficult to deal with multiple rows of figure in the denominator.
– Kevin Powell
Dec 16 at 6:14
@KevinPowell You can definitely use a matrix, just addampersand replacement=&and replace&by&.
– marmot
Dec 16 at 7:42
That's quite neat! Why[baseline]option centers the figure in the numerator? It is black magic for me.
– Kevin Powell
Dec 17 at 7:42
add a comment |
3
3
3
Generally you can control the vertical alignment with the baseline option.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
-
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
draw[dashed](0,0) -- (-1,0);
end{tikzpicture}
}
end{equation*}
end{document}
I don't know what these objects represent, so you may want to use another baseline.
Note that you can use a TikZ matrix:
documentclass{article}
usepackage{tikz}
usepackage{amsmath}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline]
defL{1.0}
matrix[column sep=.1cm, row sep=2mm,ampersand replacement=&]
{
draw (0,0) to[bend left] (L,0) to[bend left] (0,0);
&
node at (0,0) {$-$};
&
draw[dashed] (0,0) -- (L,0);
draw[xshift=L cm] (0,0) to[bend left] (L,0) to[bend left] (0,0); \
};
end{tikzpicture}
}
end{equation*}
end{document}
answered Dec 16 at 3:22
marmot
86.5k499184
Generally you can control the vertical alignment with the baseline option.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
-
begin{tikzpicture}[baseline={(0,-0.1)}]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
draw[dashed](0,0) -- (-1,0);
end{tikzpicture}
}
end{equation*}
end{document}
I don't know what these objects represent, so you may want to use another baseline.
Note that you can use a TikZ matrix:
documentclass{article}
usepackage{tikz}
usepackage{amsmath}
begin{document}
begin{equation*}
A = frac{%
begin{tikzpicture}[baseline]
draw (0,0) to[bend left] (1,0) to[bend left] (0,0);
end{tikzpicture}
}{%
begin{tikzpicture}[baseline]
defL{1.0}
matrix[column sep=.1cm, row sep=2mm,ampersand replacement=&]
{
draw (0,0) to[bend left] (L,0) to[bend left] (0,0);
&
node at (0,0) {$-$};
&
draw[dashed] (0,0) -- (L,0);
draw[xshift=L cm] (0,0) to[bend left] (L,0) to[bend left] (0,0); \
};
end{tikzpicture}
}
end{equation*}
end{document}
answered Dec 16 at 3:22
marmot
86.5k499184
edited Dec 16 at 7:46
answered Dec 16 at 3:22
marmot
86.5k499184
answered Dec 16 at 3:22
marmot
86.5k499184
answered Dec 16 at 3:22
marmot
86.5k499184
86.5k499184
Thanks! It seems that the more versatilematrixintikzpicturedoes not work withfrac. Althoughbaselineis one answer to this figure, it will become difficult to deal with multiple rows of figure in the denominator.
– Kevin Powell
Dec 16 at 6:14
@KevinPowell You can definitely use a matrix, just addampersand replacement=&and replace&by&.
– marmot
Dec 16 at 7:42
That's quite neat! Why[baseline]option centers the figure in the numerator? It is black magic for me.
– Kevin Powell
Dec 17 at 7:42
add a comment |
Thanks! It seems that the more versatilematrixintikzpicturedoes not work withfrac. Althoughbaselineis one answer to this figure, it will become difficult to deal with multiple rows of figure in the denominator.
– Kevin Powell
Dec 16 at 6:14
@KevinPowell You can definitely use a matrix, just addampersand replacement=&and replace&by&.
– marmot
Dec 16 at 7:42
That's quite neat! Why[baseline]option centers the figure in the numerator? It is black magic for me.
– Kevin Powell
Dec 17 at 7:42
Thanks! It seems that the more versatile
matrix in tikzpicture does not work with frac. Although baseline is one answer to this figure, it will become difficult to deal with multiple rows of figure in the denominator.– Kevin Powell
Dec 16 at 6:14
Thanks! It seems that the more versatile
matrix in tikzpicture does not work with frac. Although baseline is one answer to this figure, it will become difficult to deal with multiple rows of figure in the denominator.– Kevin Powell
Dec 16 at 6:14
@KevinPowell You can definitely use a matrix, just add
ampersand replacement=& and replace & by &.– marmot
Dec 16 at 7:42
@KevinPowell You can definitely use a matrix, just add
ampersand replacement=& and replace & by &.– marmot
Dec 16 at 7:42
That's quite neat! Why
[baseline] option centers the figure in the numerator? It is black magic for me.– Kevin Powell
Dec 17 at 7:42
That's quite neat! Why
[baseline] option centers the figure in the numerator? It is black magic for me.– Kevin Powell
Dec 17 at 7:42
add a comment |
4
documentclass{article}
usepackage{tikz}
begin{document}
[
A = frac{tikz[baseline=1pt]{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0);}}
{tikz{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0)
( 0.5,0) to[bend left] ( 1.5,0) to[bend left] ( 0.5,0);
draw[dashed, shorten >=1mm, shorten <=1mm] (-0.5,0) -- (0.5,0);}
}
]
end{document}
answered Dec 16 at 3:32
Zarko
120k865156
How is that different from my answer except that you defineMbut do not use it? The only thing apart from the unused definition I can see is the use ofbaseline, which is precisely what I am using.
– marmot
Dec 16 at 3:38
@marmot the denominator is different. I think there's an error here, because the minus is missing.
– CarLaTeX
Dec 16 at 4:04
2
I would create apicfor the shapes, and suggest to use dots instead of dashes, which could be confused with the minus (@marmot, too).
– CarLaTeX
Dec 16 at 4:43
@CarLaTeX That's a brilliant idea!
– Kevin Powell
Dec 16 at 6:10
@KevinPowell Thank you :)
– CarLaTeX
Dec 16 at 6:54
|
show 1 more comment
4
documentclass{article}
usepackage{tikz}
begin{document}
[
A = frac{tikz[baseline=1pt]{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0);}}
{tikz{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0)
( 0.5,0) to[bend left] ( 1.5,0) to[bend left] ( 0.5,0);
draw[dashed, shorten >=1mm, shorten <=1mm] (-0.5,0) -- (0.5,0);}
}
]
end{document}
answered Dec 16 at 3:32
Zarko
120k865156
How is that different from my answer except that you defineMbut do not use it? The only thing apart from the unused definition I can see is the use ofbaseline, which is precisely what I am using.
– marmot
Dec 16 at 3:38
@marmot the denominator is different. I think there's an error here, because the minus is missing.
– CarLaTeX
Dec 16 at 4:04
2
I would create apicfor the shapes, and suggest to use dots instead of dashes, which could be confused with the minus (@marmot, too).
– CarLaTeX
Dec 16 at 4:43
@CarLaTeX That's a brilliant idea!
– Kevin Powell
Dec 16 at 6:10
@KevinPowell Thank you :)
– CarLaTeX
Dec 16 at 6:54
|
show 1 more comment
4
4
4
documentclass{article}
usepackage{tikz}
begin{document}
[
A = frac{tikz[baseline=1pt]{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0);}}
{tikz{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0)
( 0.5,0) to[bend left] ( 1.5,0) to[bend left] ( 0.5,0);
draw[dashed, shorten >=1mm, shorten <=1mm] (-0.5,0) -- (0.5,0);}
}
]
end{document}
answered Dec 16 at 3:32
Zarko
120k865156
documentclass{article}
usepackage{tikz}
begin{document}
[
A = frac{tikz[baseline=1pt]{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0);}}
{tikz{draw (-1.5,0) to[bend left] (-0.5,0) to[bend left] (-1.5,0)
( 0.5,0) to[bend left] ( 1.5,0) to[bend left] ( 0.5,0);
draw[dashed, shorten >=1mm, shorten <=1mm] (-0.5,0) -- (0.5,0);}
}
]
end{document}
answered Dec 16 at 3:32
Zarko
120k865156
edited Dec 16 at 7:16
answered Dec 16 at 3:32
Zarko
120k865156
answered Dec 16 at 3:32
Zarko
120k865156
answered Dec 16 at 3:32
Zarko
120k865156
120k865156
How is that different from my answer except that you defineMbut do not use it? The only thing apart from the unused definition I can see is the use ofbaseline, which is precisely what I am using.
– marmot
Dec 16 at 3:38
@marmot the denominator is different. I think there's an error here, because the minus is missing.
– CarLaTeX
Dec 16 at 4:04
2
I would create apicfor the shapes, and suggest to use dots instead of dashes, which could be confused with the minus (@marmot, too).
– CarLaTeX
Dec 16 at 4:43
@CarLaTeX That's a brilliant idea!
– Kevin Powell
Dec 16 at 6:10
@KevinPowell Thank you :)
– CarLaTeX
Dec 16 at 6:54
|
show 1 more comment
How is that different from my answer except that you defineMbut do not use it? The only thing apart from the unused definition I can see is the use ofbaseline, which is precisely what I am using.
– marmot
Dec 16 at 3:38
@marmot the denominator is different. I think there's an error here, because the minus is missing.
– CarLaTeX
Dec 16 at 4:04
2
I would create apicfor the shapes, and suggest to use dots instead of dashes, which could be confused with the minus (@marmot, too).
– CarLaTeX
Dec 16 at 4:43
@CarLaTeX That's a brilliant idea!
– Kevin Powell
Dec 16 at 6:10
@KevinPowell Thank you :)
– CarLaTeX
Dec 16 at 6:54
How is that different from my answer except that you define
M but do not use it? The only thing apart from the unused definition I can see is the use of baseline, which is precisely what I am using.– marmot
Dec 16 at 3:38
How is that different from my answer except that you define
M but do not use it? The only thing apart from the unused definition I can see is the use of baseline, which is precisely what I am using.– marmot
Dec 16 at 3:38
@marmot the denominator is different. I think there's an error here, because the minus is missing.
– CarLaTeX
Dec 16 at 4:04
@marmot the denominator is different. I think there's an error here, because the minus is missing.
– CarLaTeX
Dec 16 at 4:04
2
2
I would create a
pic for the shapes, and suggest to use dots instead of dashes, which could be confused with the minus (@marmot, too).– CarLaTeX
Dec 16 at 4:43
I would create a
pic for the shapes, and suggest to use dots instead of dashes, which could be confused with the minus (@marmot, too).– CarLaTeX
Dec 16 at 4:43
@CarLaTeX That's a brilliant idea!
– Kevin Powell
Dec 16 at 6:10
@CarLaTeX That's a brilliant idea!
– Kevin Powell
Dec 16 at 6:10
@KevinPowell Thank you :)
– CarLaTeX
Dec 16 at 6:54
@KevinPowell Thank you :)
– CarLaTeX
Dec 16 at 6:54
|
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please, extend your code fragment to complete small document ...
– Zarko
Dec 16 at 3:05