Find directory names with N occurences of a set of characters
How to match non-recursively directory names that contain N occurrences of a subset of characters (using find
)?
In my specific case, I just want directory names with 6 digits. Here is what worked but is non-specific (it will give me all directory names with digits):
find . -maxdepth 1 -type d -regex './[0-9]+'
ls -d +([0-9])
This worked too, but gave me names of directories beginning with numbers and followed by anything:
find . -maxdepth 1 -type d -name '[0-9]*'
From what I read, I don't know how to make ls
match N occurrences because it uses globs and not regular expressions (and I know nothing about globs). And what I can't understand is that non of these worked using find
:
find . -maxdepth 1 -type d -regex './[0-9]{6}'
find . -maxdepth 1 -type d -name '[0-9]{6}'
find . -maxdepth 1 -type d -name '[0-9]+'
I have used regular-expressions quite a few times already, and I don't understand what's wrong with my patterns (I'm also surprised I had to specify ./
with -regex
)?
find regular-expression directory ls
add a comment |
How to match non-recursively directory names that contain N occurrences of a subset of characters (using find
)?
In my specific case, I just want directory names with 6 digits. Here is what worked but is non-specific (it will give me all directory names with digits):
find . -maxdepth 1 -type d -regex './[0-9]+'
ls -d +([0-9])
This worked too, but gave me names of directories beginning with numbers and followed by anything:
find . -maxdepth 1 -type d -name '[0-9]*'
From what I read, I don't know how to make ls
match N occurrences because it uses globs and not regular expressions (and I know nothing about globs). And what I can't understand is that non of these worked using find
:
find . -maxdepth 1 -type d -regex './[0-9]{6}'
find . -maxdepth 1 -type d -name '[0-9]{6}'
find . -maxdepth 1 -type d -name '[0-9]+'
I have used regular-expressions quite a few times already, and I don't understand what's wrong with my patterns (I'm also surprised I had to specify ./
with -regex
)?
find regular-expression directory ls
add a comment |
How to match non-recursively directory names that contain N occurrences of a subset of characters (using find
)?
In my specific case, I just want directory names with 6 digits. Here is what worked but is non-specific (it will give me all directory names with digits):
find . -maxdepth 1 -type d -regex './[0-9]+'
ls -d +([0-9])
This worked too, but gave me names of directories beginning with numbers and followed by anything:
find . -maxdepth 1 -type d -name '[0-9]*'
From what I read, I don't know how to make ls
match N occurrences because it uses globs and not regular expressions (and I know nothing about globs). And what I can't understand is that non of these worked using find
:
find . -maxdepth 1 -type d -regex './[0-9]{6}'
find . -maxdepth 1 -type d -name '[0-9]{6}'
find . -maxdepth 1 -type d -name '[0-9]+'
I have used regular-expressions quite a few times already, and I don't understand what's wrong with my patterns (I'm also surprised I had to specify ./
with -regex
)?
find regular-expression directory ls
How to match non-recursively directory names that contain N occurrences of a subset of characters (using find
)?
In my specific case, I just want directory names with 6 digits. Here is what worked but is non-specific (it will give me all directory names with digits):
find . -maxdepth 1 -type d -regex './[0-9]+'
ls -d +([0-9])
This worked too, but gave me names of directories beginning with numbers and followed by anything:
find . -maxdepth 1 -type d -name '[0-9]*'
From what I read, I don't know how to make ls
match N occurrences because it uses globs and not regular expressions (and I know nothing about globs). And what I can't understand is that non of these worked using find
:
find . -maxdepth 1 -type d -regex './[0-9]{6}'
find . -maxdepth 1 -type d -name '[0-9]{6}'
find . -maxdepth 1 -type d -name '[0-9]+'
I have used regular-expressions quite a few times already, and I don't understand what's wrong with my patterns (I'm also surprised I had to specify ./
with -regex
)?
find regular-expression directory ls
find regular-expression directory ls
edited Dec 16 at 4:22
Rui F Ribeiro
38.9k1479129
38.9k1479129
asked Jun 21 '15 at 16:05
Sheljohn
5663620
5663620
add a comment |
add a comment |
1 Answer
1
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oldest
votes
The default regex
type for GNU find
is emacs
, which doesn't support intervals. You can specify different regex types, such as posix-egrep
, which will solve your issue:
find . -maxdepth 1 -type d -regextype posix-egrep -regex './[0-9]{6}'
Thank you, I also just found this while browsing SO: stackoverflow.com/questions/6844785/…. Would you know how to do it using-name
?
– Sheljohn
Jun 21 '15 at 16:12
@Sh3ljohn-name '[0-9][0-9][0-9][0-9][0-9][0-9]'
. Same thing withls
:ls -d [0-9][0-9][0-9][0-9][0-9][0-9]
.
– lcd047
Jun 21 '15 at 16:20
@lcd047 Sarcasm.. right? :D
– Sheljohn
Jun 21 '15 at 16:42
2
@Sh3ljohn Nope, serious answer, sadly. :) That's how glob works. If there's another way to make glob match exactly 6 digits, I'm not aware of it...
– lcd047
Jun 21 '15 at 17:30
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The default regex
type for GNU find
is emacs
, which doesn't support intervals. You can specify different regex types, such as posix-egrep
, which will solve your issue:
find . -maxdepth 1 -type d -regextype posix-egrep -regex './[0-9]{6}'
Thank you, I also just found this while browsing SO: stackoverflow.com/questions/6844785/…. Would you know how to do it using-name
?
– Sheljohn
Jun 21 '15 at 16:12
@Sh3ljohn-name '[0-9][0-9][0-9][0-9][0-9][0-9]'
. Same thing withls
:ls -d [0-9][0-9][0-9][0-9][0-9][0-9]
.
– lcd047
Jun 21 '15 at 16:20
@lcd047 Sarcasm.. right? :D
– Sheljohn
Jun 21 '15 at 16:42
2
@Sh3ljohn Nope, serious answer, sadly. :) That's how glob works. If there's another way to make glob match exactly 6 digits, I'm not aware of it...
– lcd047
Jun 21 '15 at 17:30
add a comment |
The default regex
type for GNU find
is emacs
, which doesn't support intervals. You can specify different regex types, such as posix-egrep
, which will solve your issue:
find . -maxdepth 1 -type d -regextype posix-egrep -regex './[0-9]{6}'
Thank you, I also just found this while browsing SO: stackoverflow.com/questions/6844785/…. Would you know how to do it using-name
?
– Sheljohn
Jun 21 '15 at 16:12
@Sh3ljohn-name '[0-9][0-9][0-9][0-9][0-9][0-9]'
. Same thing withls
:ls -d [0-9][0-9][0-9][0-9][0-9][0-9]
.
– lcd047
Jun 21 '15 at 16:20
@lcd047 Sarcasm.. right? :D
– Sheljohn
Jun 21 '15 at 16:42
2
@Sh3ljohn Nope, serious answer, sadly. :) That's how glob works. If there's another way to make glob match exactly 6 digits, I'm not aware of it...
– lcd047
Jun 21 '15 at 17:30
add a comment |
The default regex
type for GNU find
is emacs
, which doesn't support intervals. You can specify different regex types, such as posix-egrep
, which will solve your issue:
find . -maxdepth 1 -type d -regextype posix-egrep -regex './[0-9]{6}'
The default regex
type for GNU find
is emacs
, which doesn't support intervals. You can specify different regex types, such as posix-egrep
, which will solve your issue:
find . -maxdepth 1 -type d -regextype posix-egrep -regex './[0-9]{6}'
answered Jun 21 '15 at 16:11
jordanm
30.2k28292
30.2k28292
Thank you, I also just found this while browsing SO: stackoverflow.com/questions/6844785/…. Would you know how to do it using-name
?
– Sheljohn
Jun 21 '15 at 16:12
@Sh3ljohn-name '[0-9][0-9][0-9][0-9][0-9][0-9]'
. Same thing withls
:ls -d [0-9][0-9][0-9][0-9][0-9][0-9]
.
– lcd047
Jun 21 '15 at 16:20
@lcd047 Sarcasm.. right? :D
– Sheljohn
Jun 21 '15 at 16:42
2
@Sh3ljohn Nope, serious answer, sadly. :) That's how glob works. If there's another way to make glob match exactly 6 digits, I'm not aware of it...
– lcd047
Jun 21 '15 at 17:30
add a comment |
Thank you, I also just found this while browsing SO: stackoverflow.com/questions/6844785/…. Would you know how to do it using-name
?
– Sheljohn
Jun 21 '15 at 16:12
@Sh3ljohn-name '[0-9][0-9][0-9][0-9][0-9][0-9]'
. Same thing withls
:ls -d [0-9][0-9][0-9][0-9][0-9][0-9]
.
– lcd047
Jun 21 '15 at 16:20
@lcd047 Sarcasm.. right? :D
– Sheljohn
Jun 21 '15 at 16:42
2
@Sh3ljohn Nope, serious answer, sadly. :) That's how glob works. If there's another way to make glob match exactly 6 digits, I'm not aware of it...
– lcd047
Jun 21 '15 at 17:30
Thank you, I also just found this while browsing SO: stackoverflow.com/questions/6844785/…. Would you know how to do it using
-name
?– Sheljohn
Jun 21 '15 at 16:12
Thank you, I also just found this while browsing SO: stackoverflow.com/questions/6844785/…. Would you know how to do it using
-name
?– Sheljohn
Jun 21 '15 at 16:12
@Sh3ljohn
-name '[0-9][0-9][0-9][0-9][0-9][0-9]'
. Same thing with ls
: ls -d [0-9][0-9][0-9][0-9][0-9][0-9]
.– lcd047
Jun 21 '15 at 16:20
@Sh3ljohn
-name '[0-9][0-9][0-9][0-9][0-9][0-9]'
. Same thing with ls
: ls -d [0-9][0-9][0-9][0-9][0-9][0-9]
.– lcd047
Jun 21 '15 at 16:20
@lcd047 Sarcasm.. right? :D
– Sheljohn
Jun 21 '15 at 16:42
@lcd047 Sarcasm.. right? :D
– Sheljohn
Jun 21 '15 at 16:42
2
2
@Sh3ljohn Nope, serious answer, sadly. :) That's how glob works. If there's another way to make glob match exactly 6 digits, I'm not aware of it...
– lcd047
Jun 21 '15 at 17:30
@Sh3ljohn Nope, serious answer, sadly. :) That's how glob works. If there's another way to make glob match exactly 6 digits, I'm not aware of it...
– lcd047
Jun 21 '15 at 17:30
add a comment |
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