Find All images file size and width in directory
I'm trying to find all .png .jpg and .gif files in my directory. I'm getting the file sizes properly but unable to get image width (I'm using imagemagick) in log file.
Script code
#!/bin/bash
for d in ./*;
do
echo "listing contents of dir: $d";
find . -iname "*.jpg" -type f -exec identify -format '%w %h %i' '{}' ; | awk '$1<300 || $2<300'
find . ( -name "*.jpg" -or -name "*.png" -or -name "*.gif" ) -size "+120k" -type f -exec ls -lah {} ; > sandip-log.txt
done
shell shell-script files imagemagick
edited May 12 '16 at 22:22
Gilles
531k12810631591
asked May 12 '16 at 15:53
sandiprbsandiprb
183
add a comment |
I'm trying to find all .png .jpg and .gif files in my directory. I'm getting the file sizes properly but unable to get image width (I'm using imagemagick) in log file.
Script code
#!/bin/bash
for d in ./*;
do
echo "listing contents of dir: $d";
find . -iname "*.jpg" -type f -exec identify -format '%w %h %i' '{}' ; | awk '$1<300 || $2<300'
find . ( -name "*.jpg" -or -name "*.png" -or -name "*.gif" ) -size "+120k" -type f -exec ls -lah {} ; > sandip-log.txt
done
shell shell-script files imagemagick
edited May 12 '16 at 22:22
Gilles
531k12810631591
asked May 12 '16 at 15:53
sandiprbsandiprb
183
add a comment |
I'm trying to find all .png .jpg and .gif files in my directory. I'm getting the file sizes properly but unable to get image width (I'm using imagemagick) in log file.
Script code
#!/bin/bash
for d in ./*;
do
echo "listing contents of dir: $d";
find . -iname "*.jpg" -type f -exec identify -format '%w %h %i' '{}' ; | awk '$1<300 || $2<300'
find . ( -name "*.jpg" -or -name "*.png" -or -name "*.gif" ) -size "+120k" -type f -exec ls -lah {} ; > sandip-log.txt
done
shell shell-script files imagemagick
edited May 12 '16 at 22:22
Gilles
531k12810631591
asked May 12 '16 at 15:53
sandiprbsandiprb
183
I'm trying to find all .png .jpg and .gif files in my directory. I'm getting the file sizes properly but unable to get image width (I'm using imagemagick) in log file.
Script code
#!/bin/bash
for d in ./*;
do
echo "listing contents of dir: $d";
find . -iname "*.jpg" -type f -exec identify -format '%w %h %i' '{}' ; | awk '$1<300 || $2<300'
find . ( -name "*.jpg" -or -name "*.png" -or -name "*.gif" ) -size "+120k" -type f -exec ls -lah {} ; > sandip-log.txt
done
shell shell-script files imagemagick
shell shell-script files imagemagick
edited May 12 '16 at 22:22
Gilles
531k12810631591
asked May 12 '16 at 15:53
sandiprbsandiprb
183
edited May 12 '16 at 22:22
Gilles
531k12810631591
asked May 12 '16 at 15:53
sandiprbsandiprb
183
edited May 12 '16 at 22:22
Gilles
531k12810631591
edited May 12 '16 at 22:22
Gilles
531k12810631591
edited May 12 '16 at 22:22
Gilles
531k12810631591
531k12810631591
asked May 12 '16 at 15:53
sandiprbsandiprb
183
asked May 12 '16 at 15:53
sandiprbsandiprb
183
asked May 12 '16 at 15:53
sandiprbsandiprb
183
183
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
When using identify -format you must explicitly add a newline if you want one. Without it, all your widths are on one line, and if the first one doesn't match your awk condition, you will see nothing.
...-exec identify -format '%w %h %in' '{}' ; ...
edited Jan 5 at 15:31
Jeff Schaller
39.3k1054125
answered May 12 '16 at 16:34
meuhmeuh
31.7k11854
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
When using identify -format you must explicitly add a newline if you want one. Without it, all your widths are on one line, and if the first one doesn't match your awk condition, you will see nothing.
...-exec identify -format '%w %h %in' '{}' ; ...
edited Jan 5 at 15:31
Jeff Schaller
39.3k1054125
answered May 12 '16 at 16:34
meuhmeuh
31.7k11854
add a comment |
When using identify -format you must explicitly add a newline if you want one. Without it, all your widths are on one line, and if the first one doesn't match your awk condition, you will see nothing.
...-exec identify -format '%w %h %in' '{}' ; ...
edited Jan 5 at 15:31
Jeff Schaller
39.3k1054125
answered May 12 '16 at 16:34
meuhmeuh
31.7k11854
add a comment |
When using identify -format you must explicitly add a newline if you want one. Without it, all your widths are on one line, and if the first one doesn't match your awk condition, you will see nothing.
...-exec identify -format '%w %h %in' '{}' ; ...
edited Jan 5 at 15:31
Jeff Schaller
39.3k1054125
answered May 12 '16 at 16:34
meuhmeuh
31.7k11854
When using identify -format you must explicitly add a newline if you want one. Without it, all your widths are on one line, and if the first one doesn't match your awk condition, you will see nothing.
...-exec identify -format '%w %h %in' '{}' ; ...
edited Jan 5 at 15:31
Jeff Schaller
39.3k1054125
answered May 12 '16 at 16:34
meuhmeuh
31.7k11854
edited Jan 5 at 15:31
Jeff Schaller
39.3k1054125
edited Jan 5 at 15:31
Jeff Schaller
39.3k1054125
edited Jan 5 at 15:31
Jeff Schaller
39.3k1054125
39.3k1054125
answered May 12 '16 at 16:34
meuhmeuh
31.7k11854
answered May 12 '16 at 16:34
meuhmeuh
31.7k11854
answered May 12 '16 at 16:34
meuhmeuh
31.7k11854
31.7k11854
add a comment |
add a comment |
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