Creating alias failing in bashrc using function method
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-1
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I am trying to create alias in bashrc using function method as I need to pass argument while executing.
Here i have created alias.
login-lnx1 () { 'ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2'; }
Here is output after execution.
bash-3.2$ login-lnx1 3001
bash: ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2: No such file or directory
function bourne-shell
edited Nov 20 at 22:46
Rui F Ribeiro
38.2k1475125
asked Jan 13 '17 at 18:33
hafiz
1
add a comment |
up vote
-1
down vote
favorite
I am trying to create alias in bashrc using function method as I need to pass argument while executing.
Here i have created alias.
login-lnx1 () { 'ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2'; }
Here is output after execution.
bash-3.2$ login-lnx1 3001
bash: ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2: No such file or directory
function bourne-shell
edited Nov 20 at 22:46
Rui F Ribeiro
38.2k1475125
asked Jan 13 '17 at 18:33
hafiz
1
2
As @xhienne says in his answer, functions are not aliases, so there isn't a "function method" to create an alias. You either create a function or an alias, they're different things.
– Eric Renouf
Jan 13 '17 at 19:00
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I am trying to create alias in bashrc using function method as I need to pass argument while executing.
Here i have created alias.
login-lnx1 () { 'ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2'; }
Here is output after execution.
bash-3.2$ login-lnx1 3001
bash: ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2: No such file or directory
function bourne-shell
edited Nov 20 at 22:46
Rui F Ribeiro
38.2k1475125
asked Jan 13 '17 at 18:33
hafiz
1
I am trying to create alias in bashrc using function method as I need to pass argument while executing.
Here i have created alias.
login-lnx1 () { 'ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2'; }
Here is output after execution.
bash-3.2$ login-lnx1 3001
bash: ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2: No such file or directory
function bourne-shell
function bourne-shell
edited Nov 20 at 22:46
Rui F Ribeiro
38.2k1475125
asked Jan 13 '17 at 18:33
hafiz
1
edited Nov 20 at 22:46
Rui F Ribeiro
38.2k1475125
asked Jan 13 '17 at 18:33
hafiz
1
edited Nov 20 at 22:46
Rui F Ribeiro
38.2k1475125
edited Nov 20 at 22:46
Rui F Ribeiro
38.2k1475125
edited Nov 20 at 22:46
Rui F Ribeiro
38.2k1475125
38.2k1475125
asked Jan 13 '17 at 18:33
hafiz
1
asked Jan 13 '17 at 18:33
hafiz
1
asked Jan 13 '17 at 18:33
hafiz
1
1
2
As @xhienne says in his answer, functions are not aliases, so there isn't a "function method" to create an alias. You either create a function or an alias, they're different things.
– Eric Renouf
Jan 13 '17 at 19:00
add a comment |
2
As @xhienne says in his answer, functions are not aliases, so there isn't a "function method" to create an alias. You either create a function or an alias, they're different things.
– Eric Renouf
Jan 13 '17 at 19:00
2
2
As @xhienne says in his answer, functions are not aliases, so there isn't a "function method" to create an alias. You either create a function or an alias, they're different things.
– Eric Renouf
Jan 13 '17 at 19:00
As @xhienne says in his answer, functions are not aliases, so there isn't a "function method" to create an alias. You either create a function or an alias, they're different things.
– Eric Renouf
Jan 13 '17 at 19:00
add a comment |
1 Answer
1
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oldest
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up vote
3
down vote
Just remove the single quotes in your function (this is not an alias):
login-lnx1 () { ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2; }
answered Jan 13 '17 at 18:57
xhienne
11.9k2554
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
Just remove the single quotes in your function (this is not an alias):
login-lnx1 () { ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2; }
answered Jan 13 '17 at 18:57
xhienne
11.9k2554
add a comment |
up vote
3
down vote
Just remove the single quotes in your function (this is not an alias):
login-lnx1 () { ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2; }
answered Jan 13 '17 at 18:57
xhienne
11.9k2554
add a comment |
up vote
3
down vote
up vote
3
down vote
Just remove the single quotes in your function (this is not an alias):
login-lnx1 () { ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2; }
answered Jan 13 '17 at 18:57
xhienne
11.9k2554
Just remove the single quotes in your function (this is not an alias):
login-lnx1 () { ssh -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no -p "$1" -l username lnx2; }
answered Jan 13 '17 at 18:57
xhienne
11.9k2554
answered Jan 13 '17 at 18:57
xhienne
11.9k2554
answered Jan 13 '17 at 18:57
xhienne
11.9k2554
answered Jan 13 '17 at 18:57
xhienne
11.9k2554
11.9k2554
add a comment |
add a comment |
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As @xhienne says in his answer, functions are not aliases, so there isn't a "function method" to create an alias. You either create a function or an alias, they're different things.
– Eric Renouf
Jan 13 '17 at 19:00